Uvalive 3989 ladies& #39; Choice

The classic stable marriage matching problem

UVALive-3989Ladies ' Choice Time Limit: 6000MS Memory Limit: Unknown 64bit IO Format: %lld &%llu [Submit]   [Go back] [Status] Description Problem i–ladies? Choice Background Teenagers from the local high school has asked you to help them with the organization of next Year?s Prom. The idea was to find a suitable date for everyone in the class in a fair and civilized. So, they has organized a Web site where all students, boys and girls, state their preferences among the class members, by Ordering all the possible candidates. Your mission is to keep everyone as happy as possible. Assume that there is equal numbers of boys and girls. Problem Given a set of preferences, set up the blind dates such that there is no other than people of opposite sex who would both Rather has each of the other than their the current partners. Since It was decided the Prom is Ladies ' Choice, we want to produce the best possible Choice for the girls. Input Input consists of multiple test cases the first line of the input contains the number of test cases. There is a blank line before each dataset. The input for each dataset consists of a positive integerN, not greater than, indicating the number of coup Les in the class. Next, there is N lines, each one containing the "all" the integers from 1 to N, ordered according to the Girl?s preferences. Next, there is N lines, each one containing all the integers from 1 to N, ordered according to the boy? S preferences. Output The output for each dataset consists of a sequence of N lines, where the i-th line contains the number O f the boy assigned to the i-th Girl (from 1 to N). Print a blank line between datasets. Sample Input 1 5 1 2 3) 5 4 5 2 4) 3 1 3 5 1) 2 4 3 4 2) 1 5 4 5 1) 2 3 2 5 4) 1 3 3 2 4) 1 5 1 2 4) 3 5 4 1 2) 5 3 5 3 2) 4 1 Sample Output 1 2 5 3 4 Source Southwestern 2007-2008 [Submit]   [Go back] [Status]

#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include < queue>using namespace Std;const int maxn=1100;int n;int perfect_boy[maxn][maxn];int perfect_girl[maxn][maxn];int Future_husband[maxn],future_wife[maxn];int next[maxn];queue<int> q;void Engage (int boy,int girl) {int m=future_    Husband[girl];        if (m) {future_wife[m]=0;    Q.push (m);    } Future_husband[girl]=boy; Future_wife[boy]=girl;}        BOOL Lover (int m1,int m2,int girl) {for (int i=1;i<=n;i++) {if (PERFECT_BOY[GIRL][I]==M1) return true;    if (PERFECT_BOY[GIRL][I]==M2) return false;    }}int Main () {int t_t;    scanf ("%d", &t_t);        while (t_t--) {scanf ("%d", &n);        memset (perfect_boy,0,sizeof (Perfect_boy));        memset (perfect_girl,0,sizeof (Perfect_girl));        memset (future_husband,0,sizeof (Future_husband));        memset (future_wife,0,sizeof (Future_wife));        memset (Next,0,sizeof (next));while (!q.empty ()) Q.pop ();        for (int i=1;i<=n;i++) for (int j=1;j<=n;j++) scanf ("%d", &perfect_girl[i][j]);            for (int i=1;i<=n;i++) {for (int j=1;j<=n;j++) scanf ("%d", &perfect_boy[i][j]);        Q.push (i);            } while (!q.empty ()) {int Boy=q.front (); Q.pop ();            int Girl=perfect_girl[boy][++next[boy]];            if (future_husband[girl]==0) engage (boy,girl);                else {int M=future_husband[girl];                if (Lover (Boy,m,girl)) engage (boy,girl);            else Q.push (boy);        }} for (int i=1;i<=n;i++) printf ("%d\n", Future_wife[i]);    If (T_T) Putchar (10); } return 0;}

Uvalive 3989 ladies& #39; Choice