ada programming language tutorial

Problem DescriptionTo print out all the "daffodils", the so-called "Narcissus number" refers to a three-digit number, whose numbers are cubic and equal to that of itself. For example: 153 is a narcissus number, because 153=1^3+5^3+3^3. Output:153?????????InputNoOutputThe number of daffodils, the beginning of childhood. One per lineSample InputSample Output1#include 2 3#include 4 5 6 7 intMain ()8 9 {Ten One inti; A - for(i= -;i +; i++) - the if(I==pow (i

Title Description Write a function to concatenate two strings into a string sample input after two lines of string output link123abcSample output123abc1#include 2#include string.h>3 4 voidStr_cat (CharS1[],Chars2[])5 {6 intL1 =strlen (S1);7 intL2 =strlen (S2);8 inti;9 Ten for(i = L1; i ) One { AS1[i] = s2[i-L1]; - } - theS1[i] =' /'; - } - - intMainintargcChar Const*argv[]) + { - Chars1[Bayi], s2[Bayi]; + Ascanf"%s", S1); atscanf"%s", S2); - - str_cat (S1, S2

The title describes the value of SN=A+AA+AAA+...+AA...AAA (with n a), where a is a number. For example: 2+22+222+2222+22222 (n=5), n is entered by the keyboard. Input a output and sample input5Sample output246901#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 intN, Sn =0, num =2;6scanf"%d", n);7 8 while(N >0)9 {TenSn + =num; Onenum = num *Ten+2; AN--; - } - theprintf"%d\n", Sn); - return 0; -}1013:c Language

The title description inputs two positive integers m and N, seeking their greatest common divisor and least common multiple. Input two integer output greatest common divisor, least common multiple sample input5 7Sample output1 351#include 2 3 intMax_common_diviser (intN1,intn2)4 {5 inttemp;6 7 if(N1 n2)8 {9temp = N1; N1 = n2; N2 =temp;Ten } One A - while(n1% N2! =0) - { the intt =N2; -N2 = n1%N2; -N1 =T; - } + -

Original VML polar path Tutorial: Mu Yuanhua Chapter 1 and section 4: getting started with VML 1: getting started with VML-before you officially start learning VML, follow the following rules to achieve the best results and learn the best path. 1: If you have studied HTML, CSS, or HTML and CSS, we recommend that you consider the process of learning VML as the same as that of learning html, because it is similar. 2: from this chapter and each chapter

1353:c Language Programming Tutorial (third Edition) After class exercise 10.4 time limit:1 Sec Memory limit:128 MBsubmit:296 solved:219[Submit] [Status] [BBS] Description have n integers, so that the previous number of sequential moves backward m position, the last m number into the first number of M, see figure. Write a function: To achieve the above f

/******************************************************************** @file main.cpp@date 2017-05-07@author Zor O_tiger@brief Problem 1006:c Language Programming Tutorial (third Edition) after class exercise 5.4http://www.dotcpp.com/oj/problem1006.html********************************************************************///! Header file#include #include//! Macro De

/******************************************************************** @file main.cpp@date 2017-5-11@author Zoro _tiger@brief Problem 1016:c Language Programming Tutorial (third Edition) after class exercise 6.6http://www.dotcpp.com/oj/problem1016.html********************************************************************/#include#include#defineTEST#undefTESTintMaini

/******************************************************************** @file main.cpp@date 2017-06-01 12:17:46@au Thor Zoro_tiger@brief Problem 1047:c Language Programming Tutorial (third Edition) After class exercise 10.5http://www.dotcpp.com/oj/problem1047.html********************************************************************/#include#defineTEST#undefTESTintMa

/******************************************************************** @file main.cpp@date 2017-05-29 12:55:07@au Thor Zoro_tiger@brief Problem 1043:c Language Programming Tutorial (third Edition) After class exercise 10.1http://www.dotcpp.com/oj/problem1043.html********************************************************************/#include#include#include#defineTES

/******************************************************************** @file main.cpp@date 2017-5-26 09:45:32@aut Hor Zoro_tiger@brief Problem 1032:c Language Programming Tutorial (third Edition) after class exercise 8.6http://www.dotcpp.com/oj/problem1032.html********************************************************************/#include#include#includestring>#incl

The title describes the sum of the diagonal elements of a 3x3 matrix. Input matrix output main diagonal sub-diagonal element and sample input1 2 31 1 13 2 1Sample output3 7Hint Source#includeint main(){int a[9];int x,y,i;for(i=0;iscanf("%d",a+i);x=a[0]+a[4]+a[8];y=a[2]+a[4]+a[6];printf("%d %d\n",x,y);} 1025:c Language Programming Tutorial (third Edition) after cl

The title describes a ball from the M-meter height of the free fall, each landing after the return of the original height of half, and then fall. How high does it bounce when it lands on nth time? How many meters are there? Leave two-bit decimal input m n output how high does it bounce when it lands on nth time? How many meters are there? Keep two decimal places separated by spaces and put in one line sample input1000 5Sample output31.25 2875.00Hint Source#includeint main(){int m,n,i;float h,l=0

The title description has a fractional sequence: 2/1 3/2 5/3 8/5 13/8 21/13 ... The sum of the first n items of this sequence is calculated, and two decimal places are reserved. Input n output series top N and sample input10Sample output16.481#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 6 intN, M =2, n =1, I;7 floats =0;8scanf"%d", N);9 for(i =0; i )Ten { One intT; As + = (float) m/N; -t =m; -m = n +m; then =T; - } - -printf"%.2f\n", s); + return 0;

The title describes the sum of the following three numbers, preserving the 1~b of the sum of the squares and 1~c of the 2-bit decimal 1~a and the input a B c output 1+2+...+a + 1^2+2^2+...+b^2 + 1/1+1/2+...+1/c Sample input100 50 10Sample output47977.931 intMainintargcChar Const*argv[])2 {3 4 intA, B, C, I;5 floatS1 =0, S2 =0, S3 =0;6 7scanf"%d%d%d", a, b, c);8 9 for(i =1; I )Ten { OneS1 + =i; A } - - for(i =1; I ) the { -S2 + = i *i; - } - + for(i =1

=1; J ) {Putchar ('*'); if(J! =i) {Putchar ('_'); }} putchar ('\ n'); }}Results:Program Two:Function Description: Enter lines of text, counting the number of lines, words, and characters.#include Program Three:Function Description: Output monthly calendar of the current month.#include Main () {intN, I, J; scanf_s ("%d", N); if(n = =7) n=0; ElseN=N; printf ("Sun Mon Tue Wed Tur Fri sat\n"); for(i =1; I ) {printf ("%4c",' '); } for(j =1; J -; J + +){ if((j + N)%7==0) {printf ("%4d",

The title description enters two integers, asking them to divide the remainder. Use a macro with parameters to implement, program. Input a b two number output A/b remainder sample input3 2Sample output11#include 2 #defineDivide (A, b) res = a% B;3 intMainintargcChar Const*argv[])4 {5 intA, B, res;6scanf"%d%d", a, b);7 8 Divide (A, b);9 Tenprintf"%d\n", res); One return 0; A}1037:c Language Programming