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Poj 1580 string matching [string processing]

/* Question: When a mobile string matches another string, the rule that finds the maximum number of matches is to fix one string, then compare the string with another string from left to right */ # Include Question link http://poj.org/problem? Id = 1580 Poj 1580 string matching [string processing]

Solution of NUBT 1580 prime number Decomposition Parent function method

#include #include #include #include using namespace STD;intpre[209];intans[209];inttmp[409];intMain () {intSq= (int)sqrt(209.0); for(inti =0; I $; i+=2) {Pre[i] =1; Ans[i] =1; } for(inti =3; I $; i + +) {if(!pre[i]) {memset(TMP,0,sizeof(TMP)); for(intj =0; J $; j + = i) {Pre[j] =1; for(intK =0; K+j $; k++) {Tmp[k+j] + = ans[k]; } } for(inti =0; I $; i++) {ans[i] = Tmp[i]; } } }intN while(Cin>> N) {printf("%d\n", Ans[n]); }return 0;} Copyright NOTICE: This article for Bo

Yum was lock Existing lock/var/run/yum.pid:another copy is running as PID 1580. Another app is currently holding the Yum lock; Waiting for it to Exi

[Email protected] bin]# yum-y install LrzszLoaded Plugins:fastestmirrorExisting lock/var/run/yum.pid:another copy is running as PID 1580.Another app is currently holding the Yum lock; Waiting for it to exit ...The other application Is:yummemory:37 M RSS (331 MB VSZ)started:wed 23:05:35 2018-12:26 agostate:traced/stopped, pid:1580Another app is currently holding the Yum lock; Waiting for it to exit ...The other application Is:yummemory:37 M RSS (331 MB

Poj 1580 String Matching

// Note: you must understand the meaning of the question: instead of finding the same character from the two strings, you can find it in the process of comparing strings one by one! # Include # include # include using namespace STD; int gcd (int

Reproduced Jdom/xpath Programming Guide

node, such as attributes, functions, etc., are expanded with square brackets, and the property is preceded by the @ sign.The following XPath returns the files node with a file count of 1580:/hd/disk/files[text () = ' 1580 ']It is noted that the above contains a text (), which is a function of XPath, its function is to take out the text of the current node.The following XPath returns a partition with a file

Nagios monitors Oracle Alert log Scripts

It's going to be a little nagios, you know how to use it. # Add Nagios to Oinstall group #usermod-a-G Oinstall Nagios#!/bin/shdbversion=11Bdump=/u01/app/oracle/oradata/prod/dump/diag/rdbms/prod/prod/trace/alert_prod.logstate_ok=0state_warning=1state_critical=2state_unknown=3if [$dbversion = one]Then ins_log_pwd= $bdumpElseins_log_pwd= $ORACLE _base/admin/$SERVICE _name/bdump/alert_$oracle_sid.logfiif [' Tail-50 $ins _log_pwd | grep ' ora-' |grep-v-i-e ' 1013|1031|1144|1652|1722|8103|12012|3297|1

Nagios monitoring oracle alert Log script, nagiosalert

Nagios monitoring oracle alert Log script, nagiosalertClick Nagios to know how to use it # Add nagios to the oinstall group # usermod-a-G oinstall nagios#! /Bin/shDbversion = 11Bdump =/u01/app/oracle/oradata/PROD/dump/diag/rdbms/prod/PROD/trace/alert_PROD.logSTATE_ OK = 0STATE_WARNING = 1STATE_CRITICAL = 2STATE_UNKNOWN = 3If [$ dbversion = 11]Then ins_log_pwd = $ bdumpElseIns_log_pwd = $ ORACLE_BASE/admin/$ SERVICE_NAME/bdump/alert _ $ ORACLE_SID.logFiIf ['Tail-50 $ ins_log_pwd | grep 'ora-'| gr

JDOM/XPath programming guide

search for information. These expressions are composed of many methods.Node element search is the most frequent query method you will encounter. In the preceding XML document, the root HD contains the disk node. You can use the path to find these nodes, and use a forward slash (/) to separate the child nodes and return all elements that match the pattern. The following XPath statement returns all disk elements:/HD/Disk"*" Indicates "all. /HD/* indicates all nodes in HD.The following XPath retur

Linux file system, System Management class commands, bash basic features

not found[[emailprotected] ~]# echo $?127[[emailprotected] ~]# cat /etc/issueecat: /etc/issuee: No such file or directory[[emailprotected] ~]# echo $?1程序执行有两类结果:程序的返回值;程序的执行状态结果;Directory Management class Commands:Cd,pwd,lsMkdir,rmdirmkdir [Options]/path/to/somewhere-p: No error when present, and can automatically create the required directories, recursively created by hierarchy [[emailprotected] tmp]# ls-ltotal 16drwx------2 root root 4096 Mar 19:49 gconfd-rootsrwxr-xr-x 1 root root 0 Mar 19:0

What can I do if I have a pre-tax salary? Please read it carefully.

yuan.Pre-tax expenditure. So what is the tax he should pay? This is a relatively complex knowledge. This article provides the formula and answer:(3902.6-1600) * 15%-125 =220.39(RMB)That is to say, the total tax paid by this person in 1st day of this month is220.39(RMB) How much can he get in the end?4940-543.4-494.00-220.39= 3682.21 (RMB) Let's look at another example. For a college student, the Unit promises a monthly salary of 2000.Therefore, the total social insurance individual payments = 2

The fun of Linux terminal

command. $ Echo 'tecmint team' | fold-w1 Sample Output T E C M I N T T E A M Note:-w1 only sets the length. Now we will sort the results from every letter in the text file to obtain the 10 most common characters of the desired output frequency. $ Fold-w1 Sample Output 8579 2413 e 1987 1875 TB 1644 I 1553 n 1522 o 1514 s 1224 r 1021 l How is case sensitive? We used to ignore case sensitivity. Therefore, use the following command. $ Fold-w1 Sample Output 11636

Drdb + heartbeat + nfs for Linux high-availability cluster (HA)

certain setups cause problems:1) software that runs at boot time (e.g., old versions of LILO)2) booting and partitioning software from other OSs(E.g., dos fdisk, OS/2 FDISK) Command (m for help): n # Add a new partitionCommand actionE extendedP primary partition (1-4)P # add primary partitionSelected partition 4First cylinder (1580-2610, default 1580): # default cylinder. press Enter.Using default value 15

How to realize the frequency statistic of characters in the Linux command line

most commonly used. How do you look at a single letter? Then use the following command. The code is as follows: $ Echo ' Tecmint team ' | Fold-w1 Sample Output [Code] t E C M I N T T E A M Note:-W1 just set the length Now we'll sort the results by breaking each letter from that text file to get the 10 most common characters for the desired output frequency. $ FOLD-W1 Sample Output The code is as follows: 8579 2413 E 1987 A 1875 T 1644 I 1553 N 1522 O 1514 S 1224 R

ASM data File Migration (OS–>ASM)

--Adding Test table space sql> Create tablespace xff datafile '/u01/oradata/xifenfei.dbf ' size 10m autoextend on maxsize 100m; Tablespace created. --View Data File location Sql> select name from V$datafile; NAME -------------------------------------------------------------------------------- +data/tasm/system01.dbf +data/tasm/undotbs01.dbf +data/tasm/sysaux01.dbf +data/tasm/users01.dbf +data/tasm/example01.dbf /u01/oradata/xifenfei.dbf 6 rows selected. --Create a test table Sql>

Oracle paging query statement (4)

Plan----------------------------------------------------------0 SELECT statement optimizer = choose (cost = 26 card = 20 bytes = 1580)1 0 view (cost = 26 card = 20 bytes = 1580)2 1 count (stopkey)3 2 view (cost = 26 card = 6361 bytes = 419826)4 3 index (Full scan) of 'ind _ t_object_name '(NON-UNIQUE) (cost = 26 card = 6361 bytes = 108137) Statistics----------------------------------------------------

Space and Tab Mixed error: Indentationerror:unindent does not match any outer indentation level

special characters.The currently used text editor notepad++, as if there is a setting that can display all the characters.Found, in:Show spaces and tabs, display symbols, viewThen you can see the problem:The original error line number is 1580 rows:But the source of the 1580 lines of the alignment with a dot point of space, and the previous lines of the alignment of the arrows used to indicate the TAB key,

VMwareWorkstation8.0RHEL5.6mdadm implement soft RAID 5

1. Check the system drive letter [root @ rhel5 ~] # Fdisk-lDisk/dev/sda: 32.2 GB, 32212254720bytes255heads, 63 sectors/track, 3916 cylindersUnits = cylindersof16065 * 512 = 8225280 bytesDeviceBootStartEndBlocks 1. view system drive letters [Root @ rhel5 ~] # Fdisk-l Disk/dev/sda: 32.2 GB, 32212254720 bytes255 heads, 63 sectors/track, 3916 cylindersUnits = cylinders of 16065*512 = 8225280 bytes Device Boot Start End Blocks Id System/Dev/sda1*1 13 104391 83 Linux/Dev/sda2 14 1318 10482412 + 83

ASM data File Migration (Asm–>os)

--View current situation Sql> Select COUNT (*) from HR.A; COUNT (*) ---------- 1580 Sql> select name from V$datafile; NAME ----------------------------------------------------------- +data/tasm/system01.dbf +data/tasm/undotbs01.dbf +data/tasm/sysaux01.dbf +data/tasm/users01.dbf +data/tasm/example01.dbf +dg2/tasm/datafile/xff.256.754902279 6 rows selected. --Create a table of contents Sql> Create directory Asmsrc as ' +dg2/tasm/datafile

Excerpt from the JAVA JDOM operation XML file

Org.jdom.input.saxbuilder;public class Sample1 {public static void main ( String[] args) throws exception{ Saxbuilder sb=new saxbuilder (); Document doc=sb.build ("Sample.xml"); Element root=doc.getrootelement (); List List=root.getchildren ("Disk"); for (int i=0;iThe output of the program:Disk information: partition drive: C partition Capacity: 8G Number of directories: 200 files: 1580-----------------------------------disk information: partit

Common RMAN problems in 11GR2

, the file system is required to be mounted using the NOAC option; otherwise the ORA-27054 will be reportedSymptoms:If the snapshot (snapshot) control file is located to the NFS file system and is not mounted using the option "NOAC", The RMAN backup fails with a ORA-27054 error. According to Bug 5064356, if 10.2.0.4.0 or later is running, the NFS mount point NOAC option is no longer needed. However, this fix only appears to apply to specific file types, such as online redo logs, archived redo lo

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