cass certify

width, YW = right width, A = cross slope rate, ZC = left Super High, YC = right super high, ztg = left single slope height limit, ytg = right single slope height limit, zwh = left slope width, ywh = right slope width, zi2 = 1: Left Level 2 slope, yi2 = 1: Right level 2 slope, zsl = left Level 2, YSL = right level 2, zwg = left Level 2, YWG = right gully top width, zdg = left gully bottom width, ydg = right gully bottom width, zhg = left gully height, yhg = right gully height End End. This lesso

Hello, everyone. You are welcome to watch the cass9.1 video course produced by Lao Wang's documents of work. I am the lecturer of this lesson for nine days. The attachment of our tutorial is shared. Please note that you are requesting measurement space. Contact information of the 9-day instructor (ask him for HD video) In this lesson, we will learn how to extract coordinates from cass9.1. Method 1 is generated with the encoding path Method 2: generate without

out in the opposite direction according to the test point n+ This point is connected to the upper N point, and the connection is carried out according to the test point sequence N- This point is connected to the next n point, and the connection is carried out in the opposite direction according to the test point P This point is parallel to the previous location Np This point is parallel to the location of the upper N po

period, when the design surface of earthwork calculation is a "Triangle file", the operation steps are basically the same as those of the "plane, the difference is that when you select the "coordinate data file" in the square grid earthwork calculation dialog box, you must select the first phase of the ground point elevation data, and in the "design area" column, select "Triangle network file ". When selecting a tin file, you must select a tin that consists of the second phase of the ground poi

Hello, everyone. You are welcome to watch the cass9.1 video course produced by Lao Wang's documents of work. I am the lecturer of this lesson for nine days. The attachment of our tutorial is shared. Please note that you are requesting measurement

  Hello, everyone. You are welcome to watch the cass9.1 video course produced by Lao Wang's documents of work. I am the lecturer of this lesson for nine days. The attachment of our tutorial is shared. Please note that you are requesting

After two years of college time, I constantly learn the knowledge of surveying and mapping and master a lot of professional skills, first through this professional name, everyone should be able to think, surveying is generally measured and then cartography, then in fact, it is true. Early, the mapping is what hard, of course, now may not be easy, haha, but, after continuous development, mapping also into a lot of new technology, at that time is a person holding the instrument, and then manual dr

, B) memset (A,b,sizeof (a)) - #defineEPS (1E-8) - #defineJ 10000 in #defineMoD 1000000007 - #defineMAX 0x7f7f7f7f to #definePI 3.14159265358979323 + #defineN 100004 - using namespacestd; thetypedefLong LongLL; * intCas,cass; $ intN,m,lll,ans;Panax Notoginseng LL Aans; - intA[n],f[n],q[n]; the voidGETF () + { A intI,l,r,mid; theLll=0; + for(i=n;i;i--) - { $L=0, r=lll; $ while(lR) - { -Mid= (l+r+1) >>1; the if(

0x7f7f7f7f to #definePI 3.14159265358979323 + #pragmaComment (linker, "/stack:1024000000,1024000000") - #defineN 20004 the using namespacestd; *typedefLong LongLL; $ DoubleAnss;Panax Notoginseng LL Aans; - intCas,cass; the intN,m,lll,ans; + intA[n]; A LL sum; the BOOLcmpintAaintBB) + { - returnaaBB; $ } $ BOOLjudge () - { - inti; theLL s=0; - if(Sum!=1ll*n* (n1))return 1;WuyiSort (a,a+n,cmp); the for(i=n-1; i>=0; i--) - { Wus+=i*

-#include the#include -#include -#include string.h> - //#include +#include - #pragmaComment (linker, "/stack:1024000000,1024000000") + #defineMin (a) A #defineMax (a) (a) > (b)? ( A):(B)) at #defineABS (a) ((a) >0? ( A):(-(a))) - #defineLowbit (a) (a (a)) - #defineSqr (a) ((a) * (a)) - #defineSwap (a) (a) ^= (b), (b) ^= (a), (a) ^= (b)) - #defineMem (A, B) memset (A,b,sizeof (a)) - #defineEPS (1E-8) in #defineJ 10000 - #defineMoD 1000000007 to #defineMAX 0x7f7f7f7f + #definePI 3.14159265

)-(XC-XB) (xa^2+ya^2-xb^2-yb^2)Focus:x= (XA+XB+XC)/3, y= (YA+YB+YC)/31 /****************************************************2 3 author:coolxxx4 Copyright by Coolxxx. All rights reserved.5 BLOG:http://blog.csdn.net/u0105682706 7 ****************************************************/8#include 9 #pragmaComment (linker, "/stack:1024000000,1024000000")Ten #defineABS (a) ((a) >0? ( A):(-(a))) One #defineLowbit (a) (a (a)) A #defineSqr (a) ((a) * (a)) - #defineMem (A, B) memset (A,b,sizeof (a))

#defineABS (a) ((a) >0? ( A):(-(a))) at #defineLowbit (a) (a (a)) - #defineSqr (a) ((a) * (a)) - #defineSwap (a) (a) ^= (b), (b) ^= (a), (a) ^= (b)) - #defineMem (A, B) memset (A,b,sizeof (a)) - #defineEPS (1E-8) - #defineJ 10000 in #defineMoD 1000000007 - #defineMAX 0x7f7f7f7f to #definePI 3.14159265358979323 + #defineN 100004 - using namespacestd; thetypedefLong LongLL; * intCas,cass; $ intN,m,lll,ans;Panax Notoginseng LL Aans; - structXXX the { +

from small to large to be misaligned.1 //2 //by Coolxxx3 //#include 4#include 5#include 6#include string>7#include 8#include 9#include Ten#include One#include Set> A#include -#include -#include the#include -#include -#include string.h> - //#include +#include - #defineMin (a) + #defineMax (a) (a) > (b)? ( A):(B)) A #defineABS (a) ((a) >0? ( A):(-(a))) at #defineLowbit (a) (a (a)) - #defineSqr (a) ((a) * (a)) - #defineSwap (a) (a) ^= (b), (b) ^= (a), (a) ^= (b)) - #defineMem (A, B) memse

Topic Links:http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1803Main topic:Given N,m (n,mTopic Ideas:"Analog" "math"According to the remainder of the%2016 classification. Each additional 2016 is one more option. Statistics are several times 2016, sorted by the remainder. Finally, the remainder of the enumeration i,j can be solved.1 //2 //by Coolxxx3 //#include 4#include 5#include 6#include string>7#include 8#include 9#include Ten#include One#include Set> A#include -#include -#include the#in

#include Ten#include one#include Set> a#include -#include -#include the#include -#include -#include string.h> - //#include +#include - #defineMin (a) + #defineMax (a) (a) > (b)? ( a):(b)) a #defineABS (a) ((a) >0? ( A):(-(a))) at #defineLowbit (a) (a (a)) - #defineSqr (a) ((a) * (a)) - #defineSwap (a) (a) ^= (b), (b) ^= (a), (a) ^= (b)) - #defineMem (a, b) memset (a,b,sizeof (a)) - #defineEPS (1e-10) - #defineJ 10000 in #defineMoD 1000000007 - #defineMAX 0x7f7f7f7f to #definePI 3.141592

Because of the development of information big data, all walks of life unavoidably with the information discipline to have the intersection, my study specialized for surveying and mapping engineering, the surveying and mapping profession also has many people to develop a lot of useful measurement software. So from the perspective of students, how we look at the application of these software, here on my own point of view, there may be a lot of immature places, welcome everyone to criticize.I'd lik

- #defineMAX 0x7f7f7f7f to #definePI 3.14159265358979323 + #defineN 100004 - using namespacestd; thetypedefLong LongLL; * intCas,cass; $ intN,m,lll,ans;Panax Notoginseng LL Aans; - LL E[n],sum[n],l[n],r[n]; the LL A; + CharS[n]; A intMain () the { + #ifndef Online_judge - //freopen ("1.txt", "R", stdin); $ //freopen ("2.txt", "w", stdout); $ #endif - inti,j,k; - LL x, y; the //for (scanf ("%d", cass