Determine whether a graph is a tree:
Method 1:
Topological sorting:
(1) Exclusive Ring
(2) Except for one node (Root), the inbound traffic of each node is 1.
Method 2:
Query set:
(1) Ensure that the graph is a Unicom graph (non-forest)
(2) to ensure that no rings or similar rings appear (1-> 2, 2-> 3, 1-> 3), merge eac
Find a learning URL for the tree in the smallest tree, like ~ Http://acm.nudt.edu.cn /~ The Minimum Spanning Tree of twcourse/tree.html undirected graphs can use prim.
Algorithm Or the krusual algorithm, and the Minimum Spanning Tree of the directed graph is also called the
Mainly read this articlehttp://www.geeksforgeeks.org/union-find/Summarize the current understanding of the Union-findUsed on DISJOINT-SET data structure, Disjoint-set keeps track of a set of elements partitioned into a number of disjoint (Non-ov erlapping) subsets.Union-find is an algorithm that performs and useful operations on such a data structure:1. FindDetermine which subset a particular element is in, this can being used to determin whether and the elements is in the same subse T2. UnionJo
Ultraviolet A 2038-Strategic game (minimum vertex overwrite or tree DP in a bipartite graph)
Strategic game
Description
Bob enjoys playing computer games, especially strategic games, but sometimes he cannot find the solution fast enough and then he is very sad. now he has the following problem. he must defend a medieval city, the roads of which form a tree. he ha
is considered to be index, delete } } returncount==N; }}2.DFSThe pre must be recorded in DFS to avoid a->b->a such traversal, which is considered a loop.classSolution { Public BooleanValidtree (intNint[] edges) { if(n==0)return false; List[] List=NewList[n]; for(inti=0;i) {List[i]=NewArraylist(); } for(int[] pair:edges) {list[pair[0]].add (pair[1]); list[pair[1]].add (pair[0]); } Boolean[] visited=New Boolean[n]; if(Dfs (list, visited, 0,-1))retur
General graph Max match with Flower Tree + violence:Calculate the maximum matching C1 firstIn enumerating each edge, remove the edges related to the two endpoints of the edge .... Then run Edmonds get match C2Assuming C2+2==C1, the edge is again a maximum match.Boke and TsukkomiTime limit:3000/3000 MS (java/others) Memory limit:102400/102400 K (java/others)Total submission (s): 649 Accepted Submission (s)
Graph structure exercise-Minimum Spanning Tree
Graph structure exercise-Minimum Spanning Tree
Time Limit: 1000 ms Memory limit: 65536 K any questions? Click Here ^_^
There are n cities, some of which can be built between cities, and the cost of building different roads is different. Now, we want to know how much
4 40 1 100 2 101 3 202 3 30
Sample Output
Impossible 40 0
AuthorWiskeySourceHDU 2007-10 Programming Contest_warmup
RecommendWhiskey
Analysis and Summary:
More Wonderful content: http://www.bianceng.cnhttp://www.bianceng.cn/Programming/sjjg/
The problem of the minimum tree graph of adventitious roots, the solution is to design a "virtual new root", which starts at all points, and the weights are a g
HDU 1162 Eddy's picture (graph theory-Minimum Spanning Tree), hdueddy
The questions are as follows:
Eddy's picture
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission (s): 7267 Accepted Submission (s): 3676
Problem DescriptionEddy begins to like painting pictures recently, he is sure of himself to become a painter. every day Eddy draws pictures in his small room
, A[id]. L); the //for (Vector the solve ();94 } the return 0 ; the}View CodeBecause the two possible points are definitely in the diameter of the tree (symmetrical two points), so we can answer the two points, the optimal solution must be within the 0~DIA/2.In addition to find the diameter of the method can be changed from any point to any one of the maximum depth of the point V, at the beginning of the search from the
) this.width=650; "src=" http://img.blog.csdn.net/20150719162303372 "alt=" here write a picture describing "title=" "/>The first step:Select an edge with the lowest weight650) this.width=650; "src=" http://img.blog.csdn.net/20150719162416373 "alt=" here write a picture describing "title=" "/>Step Two:650) this.width=650; "src=" http://img.blog.csdn.net/20150719162611955 "alt=" here write a picture describing "title=" "/>Step Three:650) this.width=650; "src=" http://img.blog.csdn.net/201507191627
the concept of minimum spanning tree
Objective: For n nodes and the connected graphs with weighted edges of M strips, cut off several edges to make the remaining edges weighted and minimal, and the graph is a tree (that is, a connected subgraph containing n nodes and n-1) Why the minimum spanning tree is needed
If the
Source: HDU 3726 graph and queries
Question: see the White Book
Train of Thought: Just learning treap reference White Paper
#include
HDU 3726 graph and queries treap tree
Today did a very interesting problem, although the difficulty is only moderate, but the contents of the involved is quite a lot. Among them, I learned in the inside and check this thing, although not very deep, at least an impression; and deep search, has been, deep search and wide search are my weaknesses, the understanding of this article is based on someone else's blog: lintcode178. Whether the graph valid tree
To achieve the purpose of putting all the files under the development directory, print them out in a tree-like structure. The code is as follows:Package Cn.bjsxt.io;Import Java.io.File;public class Filetree {public static void Main (string[] args) {File F=new file ("e:/useful Document"); Suppose you print all the files in this directoryPrinttree (f, 0); Starting from itself, from 0 }public static void Printtree (File f,int level) {for (int i=0;iSystem
In the textbook of data structure, there are two kinds of minimum spanning tree algorithm for graph, one is prim (premium Manaus) algorithm and one is Kruskal (Kruskal) algorithm.The two algorithms are generated in different ways:Prim algorithm:Algorithm idea:The algorithm idea is to find a distance to generate the nearest point of the collection, join, and then update the distance from the remaining points
/*Recently saw a Google pen question, "known to a undirected non-circular connected graph t all vertices and edges of information,Now you need to convert it to a tree, requiring the minimum depth of the tree, design an algorithm to find all theThe root node of the tree and analyze the space-time complexity (describing
Related concepts:Minimum spanning tree: in connected graph G, a tree that joins all vertices of the graph G with the smallest edge of the total weightIdeas:first, the edge to the right from small to large sort, immediately after enumerating each edge, if the ancestor nodes of the two nodes are different (and check set)
The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion;
products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the
content of the page makes you feel confusing, please write us an email, we will handle the problem
within 5 days after receiving your email.
If you find any instances of plagiarism from the community, please send an email to:
info-contact@alibabacloud.com
and provide relevant evidence. A staff member will contact you within 5 working days.