For example such a table, I would like to count the number of records for which email and passwords are not the same
Copy the Code code as follows:
CREATE TABLE IF not EXISTS ' test_users ' (' email_id ' int (one) unsigned not NULL auto_increment,' Email ' char (+) not NULL,' Passwords ' char (+) is not NULL,PRIMARY KEY (' email_id ')) Engine=myisam DEFAULT Charset=utf8 auto_increment=6;
INSERT into ' test_users ' (' email_id ', ' email ', ' password
For example such a table, I want to count the number of records with different emails and passwords
Copy Code code as follows:
CREATE TABLE IF not EXISTS ' test_users ' (
' email_id ' int (one) unsigned not NULL auto_increment,
' Email ' char not NULL,
' Passwords ' char () not NULL,
PRIMARY KEY (' email_id ')
) Engine=myisam DEFAULT Charset=utf8 auto_increment=6;
INSERT into ' test_users ' (' email_id ', ' email ', '
--statistics on the total number of male and female studentsSelect COUNT (*) from Student where sex= ' man 'Select COUNT (*) from Student where sex= ' female '--Count the total number of each classSelect COUNT (*) from Student where classid=1--Grouping statistics: Need to Group
In DB2, the sum function used to replace the count query is to calculate and sum the column values. The www.2cto.com count function accumulates the columns that meet the conditions and adds one when the conditions are met. The count function is commonly used to count the num
Label:1. Add the user Oracle to the DB2 user group with the following command:Usermod-a-G Db2iam # adding users to a group does not change the group that is currently ownedNote: The following are not related to the topic, just list some commands about the userID user # View information such as us
aggregate Functions
Before introducing the group BY and having clauses, we must first talk about a special function in the SQL language: aggregate functions, such as SUM, COUNT, MAX, AVG, and so on. The fundamental difference between these functions and other functions is that they generally work on more than one record.
SELECT SUM (population) from BBC
The sum action here is on all population fields that
Mongodb uses aggregate, group, and match to implement the having (count (1) (1) function in mysql.
In relational databases, group deduplication is generally set to group... Having (count (1)> 1 )... The record group is selected fo
Today, DB2 9.1 is installed on the local machine.
Local Environment: Windows Server 2003 Internal ice Edition SP2 TW
Logon account: ABC \ c12345 (Administrator Group)
An account was set up for use during installation. At that time, my domain was detected in the domain, but when I entered my account, I was prompted that I could not detect the account and password for the high domain.
The default creation
Original: LINQ to SQL (Group by/having/count/sum/min/max/avg operator)Group by/having operatorScenario : grouping data to narrow the scope for us to find data.Description : An enumerable object that is assigned and returned after a group operation on an incoming parameter. To group
Linq to SQL (Group By/Having/Count/Sum/Min/Max/Avg operator ),Group By/Having Operator
Applicable scenarios: Grouping data. narrow down the scope of data for us.
Description: Assigns and returns the enumerated objects after grouping the input parameters. Group; Delay1. Simple Form:
var q = from p in db.Products
. Countingvar q = from p in db. Products Group P is p.categoryid into G Select new { G.key, numproducts = G.count () };Statement Description: Use GROUP BY and count to get the number of products in each CategoryID.Description: First by CategoryID classification, remove the CategoryID value and the number of individual products.8. With co
p.categoryid into G Select new { G.key, numproducts = G.count () };Statement Description: Use GROUP BY and count to get the number of products in each CategoryID.Description: First by CategoryID classification, remove the CategoryID value and the number of individual products.8. With conditional countvar q = from p in db. Products Group
--- Price statistics for all books
Select sum (price) total price, AVG (price) average price, max (price) highest price, min (price) lowest price
From titles
--- Count records of where conditions--- Business-type book price statisticsSelect sum (price) total price, AVG (price) average price, max (price) highest price, min (price) lowest priceFrom titles where type = 'business'
-- Count-- Returns the author
Calculate the total number of animals you own and "How many rows are there in the pet table?" Is the same problem because each pet has a record. The count (*) function calculates the number of rows, so the query for calculating the number of animals should be:Mysql> SELECT COUNT (*) from pet;+----------+| COUNT (*) |+----------+| 9 |+----------+In the front, you
MYSQL row-to-column conversion and basic aggregate function count, used in combination with group by and distinct, countdistinct
The count function is often used in statistical queries. Here, the basic MYSQL row-to-column conversion and basic aggregate function count are used in combination with
MySQL Error injection principle analysis (count (), Rand (), GROUP by)0x00 questionshave been using the MySQL Database error injection method, but why the error?Baidu Google know a bit, found that everyone is the official website of the conclusion of a hair, and then execute the SQL statement to prove a conclusion, but no one to delve into why Rand can not be used with order by, nor completely explain the t
key value as the latest timestamp, and also remove the price key value for the document.> Db.test.group ({... "Key": {"Day": true},--if it is multiple fields, {"F1": True, "F2": true}... "Initial": {"time": "0"},--initial represents the initial value of the $reduce function parameter prev. Each group has a copy of the initial value.... "$reduce": function (doc,prev) {--reduce function accepts two parameters, doc represents the current document being
lowest unit price of products in each category. Remove the CategoryID value and assign the UnitPrice value to Minprice.5. Averagevar q = in db. Products Select new {g.key, averageprice = g.average (P = p.unitprice)}; Statement Description: Use GROUP by and average to get the average unit price per CategoryID.Description: First by CategoryID classification, remove the CategoryID value and the average price of each product category.6. Summationva
1. Count:
Copy Code code as follows:
--In an empty collection, Count returns a number of 0.
> Db.test.count ()
0
--Test the return value of count after inserting a document.
> Db.test.insert ({"Test": 1})
> Db.test.count ()
1
> Db.test.insert ({"Test": 2})
> Db.test.count ()
2
--count
SQL Count () function:
SQL count (column_name) syntax: The count (column_name) function returns the number of rows that are worth the specified column (null does not count in)
Select Count from table_name
SQL coun
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