LeetCode # Reverse Number #
LeetCode # Reverse Number #
I just memorized the word and made a question to play with it ~ Pick a soft persimmon and step on it ~ Haha
It's a simple idea, but the fun thing is that I forgot to check whether the processed data conforms to the integer data and returned it. So I can't AC
]
b: []
result:[1, 2, 3, 4, 5]
Select 5 of the A array
When we merge [2, 4, 5] and [1, 3] we can find that when we put the element k of a array into the result array, the elements of the B array that exist in result must be smaller than K. In the original array, the position of the elements in the B array must be after K, that is, k and these elements constitute the inverse pair. So when we put the elements in the a array, we can calculate th
title link : http://acm.hdu.edu.cn/showproblem.php?pid=4911The main problem : Can exchange a maximum of k times, the minimum number of reverse logarithmProblem Solving Ideas :The inverse number theorem, when the inverse logarithm is greater than 0 o'clock, if akSet primitive sequence minimum inverse logarithm =cntSo, the minimum inverse logarithm max (0,cnt-k) to
There are many algorithms for reverse order pairs. Here we will talk about the idea of Reverse Order pairs for line segment trees. Knowledge Point: Line Segment tree, reverse order pair, single point update, CIDR sum Algorithm: the precondition for the line segment tree to calculate the number of
The number of reverse order refers to the example: Array a={2,4,3,5} then One: Violent matchFor the elements in array a, I from 0 to n-1,j from I+1 to N, judging whether each is an inverse number, time complexity O (LgN). It's too simple to write code ...Two: MergeThe merge sort can solve the reverse order
Title Link: https://www.51nod.com/onlineJudge/questionCode.html#!problemId=1019Test instructions: In one arrangement, if the front and back positions of a pair of numbers are opposite the size order, that is, the previous number is greater than the number of subsequent numbers, then they are called an inverse. The total number of
By the definition of the N-order determinant, it is necessary to solve the whole permutation and reverse order number of a sequence first.
1. Full arrangementAny element of M (m≤n) from n different elements, arranged in a certain order, is called an arrangement of extracting m elements from n different elements. All permutations are called when m=n.
Algorithm principle
1. Suppose there i
Title: Segment Tree-minimum number of reverse orderDate:2018-10-12 17:19:16Tags
Acm
Algorithm
Brush questionsCategories
acm-segment Tree
OverviewThis is a simple line-of-tree problem, and, of course, there are many other practices, and even when violence can be,,,The line tree is mainly used to practice a line tree, and this time, I changed a way of writing line-segment trees,Seems
1. Calculate the number of reverse orders using a tree Array
Disadvantage: Only integers can be obtained in reverse order.
# Include "treearray. H"/* algorithm: returns reverse order pairs from a tree array. When element I is added, the value of a [I] with element I as the benchmark is + 1, from the end of the team to
The number of reverse order, that is, for n different elements, the first rule between the elements have a standard order (for example, n different natural numbers, can be specified from small to large for the standard order), so in any of the n elements of the arrangement, when a two elements of the sequence and the standard sequence is not the same, said there are 1 r
=1394Title: To a group of numbers, each time you can get the beginning of the number to the end, ask such a sequence of the number of reverse order of the smallest inverse valueTitle Analysis: First Use the tree-like array to reverse the number, the
1203: Reverse Order numberTime limit:1 Sec Memory limit:128 MBsubmit:125 solved:26[Submit] [Status] [Web Board]DescriptionIn one arrangement, if the front and back positions of a pair of numbers are opposite the size order,that is, the preceding number is not less than the subsequent number, then they are called a reverse
1019 Reverse Order numberBase time limit:1 seconds space limit:131072 KBIn one arrangement, if the front and back positions of a pair of numbers are opposite to the size order, that is, the previous number is greater than the subsequent number, then they are called an inverse. The total number of
Merge process of merging and sorting, A [p... q] And A [q... r] has been ordered. Assume that Merge has been directed to A [I... q] And A [j... r]. Consider the next step: If A [I]
In the Merge process, A [p... r], A [r... q] The number of Reverse Order pairs between them. The time complexity is also limit (n), which is the sumTime Complexity: hour (nlgn)This method is much better than the simple method r
IntroductionThe first time I learned that the reverse number is in the Advanced Algebra course. When I wanted to calculate the inverse number of a sequence, intuition was solved by the double cyclic O (n^2) violence. Now gradually the merging algorithm has a certain understanding, so decided to use C + + code to try sledgehammer. Introduction to
Test Instructions:Bobo has a sequence a1,a 2,..., a n. He is allowed to swap, adjacent numbers for no more than k times. Find the minimum number of inversions after his swaps. Note:the number of inversions is the number of pair (I,J) where 1≤i i>a J. InputThe input consists of several tests. For each tests:The first line contains 2 integers n,k (1≤n≤10 5,0≤k≤
Title Link: http://acm.hdu.edu.cn/showproblem.php?pid=1394Test instructions: The inverse number of a number is inv, and then the number of the first number of this sequence is changed to the last digit, the reverse of the number o
A sequence is given. You can move it cyclically (that is, move the following section to the Front) and ask the smallest number of backward orders that can be moved. Reverse Order can be used for sorting, and the complexity is O (nlogn). However, if you perform this operation once every time you move it, it will definitely time out. Online question solutions can be used and implemented, after thinking for a
≤ n ≤200000, ) Separated by space-the number of lasers in the energy generator and the power of the generator innokentiy wants to REAC H. OutputOutput n integers separated by spaces. I-th number should is equal to the number of receiver which the i-th laser should be directe D at. Both lasers and receivers is numbered from 1 to n. It's guaranteed that
https://leetcode.com/problems/reverse-bits/Reverse bits of a given the unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 ( Represented in binary as00111001011110000010100101000000).The simple thing is to walk through it, but this method is inefficient, and there seems to be no better way to do it.Class Solution {public: uint32
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