digit calc

Rightmost DigitProblem Descriptiongiven A positive integer N, you should output the most right digit of n^n.Inputthe input contains several test cases. The first line of the input was a single integer T which is the number of test cases. T test Cases follow.Each test case is contains a single positive integer N (1Outputfor Each test case, you should output the rightmost digit of n^n. Sample Input234Sample O

This Algorithm I have a search on the Internet. For now, I feel that my algorithms are the most suitable. The most recent case involves bar code printing. The request is a unique sequence. There is a date in the middle, and the last three digits are the serial number. But the number of printed sheets will exceed 999;Therefore, 26 uppercase letters are required. The requirements are as follows: 999 is a common number (001 ~ 999), then we start to use a hundred letters, that is, the last

Thought: At the beginning, I found it very tangled !! Later, I saw a person's analysis, which was converted in this way. M = n ^ N; obtain the logarithm of the two sides. log10 (m) = N * log10 (n); then, M = 10 ^ (N * log10 (n )); Then, for the integer power of 10, the first digit is 1. Therefore, the first digit depends on the decimal part of N * log10 (n ). In short, log is very powerful. In order

public class Identitynum { public static void Main (string[] args) { System.out.println (Getlastidnum ("37018319880321312")); } /** * Name: The last one to calculate the 18-digit ID card * Function: According to the first 17 ID number, please the last one * The last one of the ID card algorithm: * 1. Multiply the first 17 digits of the ID card number by the weights: 7 9 10 5 8 4 2 1 6 3 7 9 10 5 8 4 * (for example: First is multiplied b

Tags: id 18-bit check code principle Java Oracle Delphi Sanoul The citizenship number is a series of combination codes, consisting of a 17-digit ontology code and a checksum code. The order is from left to right: six digit address code, eight digit birth date code, three digit sequential code and one

Rightmost DigitTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 34329 Accepted Submission (s): 13091Problem Descriptiongiven A positive integer N, you should output the most right digit of n^n.Inputthe input contains several test cases. The first line of the input was a single integer T which is the number of test cases. T test Cases follow.Each test case is contains a single positive integer N (1Ou

Find out the rules of mathematicsOriginal question:Rightmost DigitTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 6515 Accepted Submission (s): 2454Problem Descriptiongiven A positive integer N, you should output the most right digit of n^n.Inputthe input contains several test cases. The first line of the input was a single integer T which is the number of test cases. T test Cases follow.Each test ca

The method for calculating the actual age with the last digit of the mobile phone circulating on the Internet is related to algorithms? Secret of age and mobile phone number Who did find this? Accurate. [1] check the last digit of your mobile phone number. [2] Multiply this number by 2 [3] then add 5 [4] multiply by 50 [5] add 1763 [6] In the last step, use this number to subtract the year of your bi

Leetcode 233: Number of Digit One, leetcodedigitNumber of Digit OneTotal Accepted:307Total Submissions:1853 Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n. For example:Given n = 13,Return 6, because digit 1 occurred in the following numbers: 1, 10, 1

1435-digit factorial base time limit: 1 second space limit: 131072 KBX is a positive integer of n-digit number(X=a 0a1an−) Now defineF(X)=∏i=0 n −1 ( Ai!) , such as f (135) =1!*3!*5!=720.We are given an n-digit integer x (at least one digit greater than 1,x may have a leading 0),And then we go find a positive in

Topic:Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to N.For example:Given n = 13,Return 6, because digit 1 occurred in the following numbers:1, 10, 11, 12, 13.Links: http://leetcode.com/problems/number-of-digit-one/Exercisesis a mathematical problem, the main idea is to do it by hand. There are so

Digit Counting Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld %llu Submit StatusDescriptionTrung is bored with his mathematics homeworks. He takes a piece of chalk and starts writing a sequence of consecutive integers starting with 1 toN(1 n . After this, he counts the number of times each digit