distance between two gps coordinates

First you need to know the GPS coordinate system. The GPS coordinate system follows the WGS-84 standard, under which the GPS chip can emit different packet formats. The GPS data can be classified into Gpgga, Gpgsa, GPGSV, GPRMC and so on, according to the different frame-frame head of the data. These frame headers iden

PHP implements the method of calculating the distance between map coordinates of Baidu, PHP coordinates In this paper, we describe the method of calculating the distance between Baidu map coordinates by PHP. Share to everyone for your reference, as follows: The following is

Php is used to calculate the distance between Baidu map coordinates. php coordinates This article describes how php calculates the distance between Baidu map coordinates. We will share this with you for your reference. The details are as follows: The following is the online

* * @param LNG * @param lat * @return */public int[] Getxy (double LNG, double lat) {///compare with reference points longitude calculate coordinates if (LNG > D34[0]) {return getXY1 (LNG, LAT);} else {return getXY2 (LNG, LAT);}} /** * The fixed point is the baseline xy coordinate */private int[] getXY1 (double LNG, double lat) {//WillLatitude converted to Gaussian projection coordinates double[] GS = Blto

PHP calculates the distance between two coordinates (longitude, latitude), coordinates longitude This example describes how PHP calculates the distance between two coordinates (longitude, latitude). Share to everyone for your reference. Specific as follows: Here we use PHP

Hope to be useful to the developers, the test error is small#pragma mark-German map GPS to coordinates//location lati, longi#define Pi 3.14159265358979324NSArray * TRANSFORMGPSTOMAMAP (NSString * Loc ation) {Nsarray * result = nil; A = 6378245.0, F = 298.3//b = A * (1-f)//ee = (a^2-b^2)/a^2; Const double A = 6378245.0; Const double EE = 0.00669342162296594323; Nsarray * Tmparr = [location

PHP searches nearby based on gps coordinates Define ('Earth _ RADIUS ', 6370.6935 ); Function vicinity ($ lng, $ lat, $ distance = 0.5 ){ // $ Distance = 0.5; // unit: 10 KM $ Radius = EARTH_RADIUS; $ Dlng = rad2deg (2 * asin (sin ($

: This article describes how to calculate the distance between two GPS points in PHP. For more information about PHP tutorials, see. The following is a function for PHP to calculate the distance between two GPS points: PHP calculates the distance between two

Calculate the Distance between the Points in PHPThere is a lot of applications where it's useful to know the distance between the coordinates. Here, you'll find a PHP function that takes the latitude and longitude of the points and returns the distance between them In both miles and metric units.You can also use this t

Android GPS obtains the coordinates of the current longitude and latitude In the APP, there may be a need to upload the coordinates of the current location to the server. Today, I provide three ways to obtain the coordinates of the longitude and latitude. The first is implemented through the Android API, the second is

using the AK Check mode for SN check. (SN generation algorithm) From source Coordinate type The values are as follows:The angular coordinates obtained by the 1:GPS device;2:gps obtained by the metric coordinates, sogou map coordinates used;3:google m

Define (' Earth_radius ', 6378.137);//Earth radius Define (' PI ', 3.1415926); /** * Calculate the distance between the two sets of latitude coordinates * PARAMS:LAT1 latitude 1; lng1 longitude 1; lat2 latitude 2; lng2 longitude 2; Len_type (1:m or 2:km); * Return m or km */ function Getdistance ($lat 1, $lng 1, $lat 2, $lng 2, $len _type = 1, $decimal = 2) { $radLat 1 = $lat 1 * pi/180.0;

Original: php+ Baidu map Api+javascript implementation of GPS coordinates and Baidu coordinate conversion examplephp+ Baidu Map Api+javascript implementation of GPS coordinates and Baidu coordinate conversion example

How to coordinate coordinates of GPS longitude and latitude Original article:Http://hi.baidu.com/myonlylovegg/blog/item/dacc24d4db648acc51da4b28.html It is easy to convert longitude and latitude to decimal.As follows:Decimal degrees = degrees + minutes/60 + seconds/3600Example: 57 ° 55 '56. 6 "= 57 + 55/60 + 56.6/3600 = 57.9323888888888114 ° 65 '24. 6 "= 114 + 65/60 + 24.6/3600 = calculate the result by you

!--? php Define (' Earth_radius ', 6370.6935); function vicinity ($LNG, $lat, $distance = 0.5) { //$distance = 0.5;//Unit 10KM li> $radius = Earth_radius; $dlng = rad2deg (2*asin (Sin ($distance/($radius))/cos ($lat)); $dlat = rad2deg ($distance *10/

Here is the function of PHP to calculate the distance of two GPS points: PHP calculates the distance between two GPS pointsMySQL calculates the distance between two GPS coordinatesJavaScript calculates the

Example One function distance ($lat 1, $lng 1, $lat 2, $lng 2, $miles = True){$pi = m_pi/180;$lat 1 *= $PI 80;$LNG 1 *= $PI 80;$lat 2 *= $PI 80;$LNG 2 *= $PI 80;$r = 6372.797;$dlat = $lat 2-$lat 1;$DLNG = $lng 2-$LNG 1;$a = sin ($dlat/2) *sin ($dlat/2) +cos ($lat 1) *cos ($lat 2) *sin ($DLNG/2) *sin ($DLNG/2);$c = 2 * atan2 (sqrt ($a), sqrt (1-$a));$km = $r * $c;Return ($miles? ($KM * 0.621371192): $km);} Example Two /*** Calculate the

/** calculate the distance between two coordinates (m) * @param float $fP 1Lat starting point (latitude) * @param float $fP 1Lon Start (longitude) * @param float $fP 2Lat end point (latitude) * @param Float $fP 2Lon end point (longitude) * @return int*/functionDistancebetween ($fP 1Lat,$fP 1Lon,$fP 2Lat,$fP 2Lon){ $fEARTH _radius= 6378137; //Angle converted to radians $fRadLon 1=Deg2rad($fP 1Lon); $fR

Currently, the coordinates of user P are: (116.63255, 39.90467), and the current database has 40 million user coordinates which are not fixed. Business Requirements: all users in the center of "P" and "1km" are sorted by distance from near to far, how do I write MYSQL, PHP, or MYSQL stored procedures (if any )?... Now there is user P whose

getjwdb (double Glat, double Glon, double distance, double angle, out double BJD, out do Uble BWD) { Double dx = distance * + math.sin (angle * math.pi/180.0); Double dy = distance * Math.Cos (angle * math.pi/180.0); Double EC = 6356725 + 21412 * (90.0-glat)/90.0; 21412 is the difference between the equatorial