echomax

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[Linux] applet: UDP The client transmits multiple strings to the server

Or the homework of the experiment ~Total two files required, this is the client1#include 2#include 3#include 4#include 5#include string.h>6#include 7 8 #defineEchomax 2559 Ten intMainintargcChar*argv[]) { One intsock; A structsockaddr_in echoservaddr; - structsockaddr_in fromaddr; -Unsigned ShortEchoservport; theUnsignedintfromsize; - Char*Servip; - Char*echostring; - Charechobuffer[echomax+1]; + intechostringlen=0; - i

Java Socket Programming (ii) socket base __ Algorithm

Udpechoservertest.java private static final int echomax = 255; public static void Main (string[] args) throws IOException { datagramsocket socket = new Datagramsocket (7); Datagrampacket packet = new Datagrampacket (new Byte[echomax), Echomax); while (true) { socket.receive (packet); SYSTEM.OUT.PRINTLN ("Handling client at" + packet.getadd

Java Socket Programming Instance (ii)-UDP basic use _java

One. Service-side code: Import java.io.*; Import java.net.*; public class Udpechoserver { private static final int echomax = 255://Maximum size of Echo datagram public Stati c void Main (string[] args) throws IOException { int servport = 5500;//Server port datagramsocket socket = new Da Tagramsocket (servport); Datagrampacket packet = new Datagrampacket (new Byte[echomax

Java Socket Network Programming Basics Introduction Tutorial _java

, serveraddress, 7); Datagrampacket receivepacket = new Datagrampacket (new Byte[bytestosend.length), bytestosend.length); Packets May is lost, so we have to keep trying int tries = 0; Boolean receivedresponse = false; do {socket.send (sendpacket); try {socket.receive (receivepacket); if (!receivepacket.getaddress (). Equals (serveraddress)) throw new IOException ("Receive from unknown Source"); Receivedresponse = true; catch (IOException e) {tries++;

Java TCP/UDP socket programming process summary, udpsocket

differences between UDP and TCP. One is that it does not need to establish a connection, and the other is that it retains the message boundary in each message sent and received.Server Because UDP does not need to establish a connection, the process is as follows: 1. Construct an initramsocket instance and specify the local port. 2. Use the receive method of the initramsocket instance to receive the contents of the communication in the middle of DatagramPacket. DatagramPacket. 3. Use the send an

Java4android Socket Network Communication Foundation

is as follows:1. Construct the Datagramsocket instance, specifying the local port.2. The Receive method of the Datagramsocket instance receives the content of the communication in the middle of the datagrampacket.datagrampacket.3. Receive and send Datagrampacket through the Datagramsocket send and receive methods.The typical interaction process code is as follows:1. Build the Datagramsocket instance, specifying the local port. Datagramsocket socket = new Datagramsocket (servport);//2. Build Dat

Shell script loops and signals

[*]}" One EchoMax is $max A EchoMin is $minView Code1 #!/bin/bash2 re= 'WC -L $1cut"" -F1 ' 3echo $reView CodeContinue and breakContinue and break can be added after a number n, indicating that the first n-level of the current round of the end of the cycle so that directly into the next round of judgment, the most inner layer of the loop is the 1th layerContinue 2 or Break 3Loop Control Shift CommandMove the parameter list to the left, the default mo

Chapter 4 mathematical operations

12,345.6812*345 #68 Iv. mathematical functions Function Function ABS () Take absolute value Floor () Rounding Ceil () Returns an integer. Round () Rounding Min () Minimum value or the minimum value in the array Max () Returns the maximum value or the maximum value in the array. $=-123456.789;$ B=Array(1,2,3,4);EchoABS ($);Echo';EchoFloor ($);Echo';EchoCeil ($);Echo';EchoRound ($);

Example analysis of PHP array operation

' $f = $fruits; while ($elem = each ($f)) { echo$elem[' key '. '-'. $elem [' value ']. ' } echo ' $arr 5=array (2, 8, 100, 33,-18); Find the maximum minimum value Echomax ($arr 5);

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