There are several identical records in thousands of records. How can I use SQL statements to delete duplicates?
1. Search for redundant duplicate records in the Table. duplicate records are determined based on a single field (peopleid ).
Select *
1 package Huawei trial; 2 // C ++ input: A string consisting of digits and letters, for example, 333aaabb55ppin 3 // output: if a number appears consecutively (two or more) the same character (number or character), delete one. If it is not a number,
2. Obtain the largest and identical substrings in two strings. The first action: print the short string with a child string whose length is reduced once.
"Cvhellobnmtanop"
"Andefc"
Ideas:
1. Obtain the short substring in descending order of length.
2
// Cyclically shifts the string a [n] and n-1 to obtain n strings, which are equal to the number of original strings. // For example: byebye // Number of identical strings 2 times // loop 0 times Byebye // cycle 1 time yebyeb // cycle 2 times ebyeby
Removes adjacent identical strings from the string. For example, abcddddffff returns abcdf.
The solution I wrote is as follows. I don't know if you have any good solutions. String Strinputdata = This . Textbox1.text. Trim (); Char []
I wrote this in Ajax.$ ("#subbutton"). Click (function () {var machinecode_1=$ ("#machineCode_1"). Val ();var machinecode_2=$ ("#machineCode_2"). Val ();var machinecode_3=$ ("#machineCode_3"). Val ();var machinecode_4=$ ("#machineCode_4"). Val
File input is not allowed to be assigned for security reasons, even if it is empty, although it can be emptied by assigning a value to innerHTML, it seems to be used only under IE.Because of the lack of an empty method, the change is not triggered
When multiple identical attributes and elements are implemented to expand and collapse, the event should be bound with the element or class attribute, and the corresponding method should be called using the prev () and next () methods.For example,
1. PrefaceBecause comparing two pictures is the same, if you feel slower by Pixel point comparison, the efficiency is much lower when many images are compared. Since each file MD5 is essentially unique, it is used to determine whether the file is
Today in writing JS, encountered a strange problem, obviously two strings equal, with alert () print out all the same, typeof the result is a string,Look carefully, there are no spaces.But judging by a==b is not equal.Later on the Internet to check
Ditto:chens-macbook-air:~ chen$ MD5/USERS/CHEN/DOWNLOADS/IPHONE_5.5_11.0_15A372_RESTORE.IPSWMD5 (/USERS/CHEN/DOWNLOADS/IPHONE_5.5_11.0_15A372_RESTORE.IPSW) = 0473f217af0f20e138649385de6db6c7GM version of MD5chens-macbook-air:~ chen$
Find adjacent same stringvar found = false;function F (str) {if (found) {return;} var len = Str.length;var a = str.substring (0,LEN/2), var b = str.substring (Len/2,len), if (a = = B && a!= "" && a!=undefined) {Console.log ("found:" + a+b); found =
arr=[' 1 ', ' 1 ', ' 2 ',, ' 3 ', ' 4 ', ' 5 ', ' 5 ', ' 6 ', ' 7 ', ' 8 ', ' 9 ', ' 1 ', ' 9 ', ' 10 ', ' 6 ']; now there is an array where the requirement is to combine the same elements into a new array, what is the simpler wayThat is, the final
Topic linksTest instructions: Input N (2 Idea: Put all the strings in the middle of the delimiter, note: The delimiter only need and input characters are different, and different can be, there is no need to be the smallest character;The connection
var obj = document.getelementsbyname ("abc");for (var i = 0;iObj[0].remove ();//remove is the jquery method. Need to load }The key to solving the problem is knowing that obj gets and deletes the elements of obj that are synchronous, that is, when
Scenario One: If the project is not just an individual page with multiple name validations,Then use prototype to write, add this code in the JS initialization of the page you want to use multiple nameif ($.validator) {$.validator.prototype.elements =
Cause: Today an AAR package runs normally in a test environment, returns normally with the Soapui test, and runs in the local environment to keep the database connection exception checked because of a lack of OJDBC-related jar packages in the
Time limit: 10000msSingle point time limit: 1000msMemory Limit: 256MBDescribeGiven an array of n integers, a. Your task is to rearrange the a so that any two equal integers are not adjacent to each other in the array.If there are multiple reflow
/* function, give two strings to find the longest same part */Char *longestsame (char*,char*);int main (){Char *a = "AAAABBCCCC";Char *b = "BCCC";Char *ret = Longestsame (A, b);printf ("%s\n", ret);}Char *longestsame (char*a, char* b){Char
This post was last edited by myths621 from 2013-03-1912: 04: 11 in the case of adding the same element in the multi-dimensional array. I took the five-dimensional array from redis and needed to process the addition, as follows: $ a & nbsp; array (0 &
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