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Python code example for constructing a graph using an adjacent matrix, python Matrix Problem How to use the list structure diagram Method of the adjacent matrix Python sample code #! /Usr/bin/env python #-*-encoding: UTF-8-*-# author: LiYanwei # version: 0.1 # '''a --- B \ | |\| | c |/e --- d/if an edge exists between an undirected graph vertex, the value is 1, o

P3390 [TEMPLATE] rapid matrix power, p3390 MatrixBackground Rapid matrix powerDescription Given n * n matrix A, evaluate A ^ kInput/Output Format Input Format: The first line, n, k The number of n rows from 2nd to n + 1. The number of j rows in I + 1 indicates the elements in column j of row I in the matrix. Output F

HDU 4965 Fast Matrix Calculation (Matrix Fast power)HDU 4965 Fast Matrix Calculation Question Link Multiply the matrix by AxBxAxB... by nn, it can be changed to Ax (BxAxBxA ...) xB: returns nn-1 in the middle. In this way, a matrix in the middle is only 6x6, so that we can u

POJ 3233 Matrix Power Series (Matrix optimization) Ask S [k] = A + A ^ 2 +... + A ^ k Using the rapid power of A matrix, we can quickly obtain the k power of A matrix, but this question is A sum. If we still follow the original method, we will calculate k times, which is unacceptable in complexity. We can construct A

Topic将正方形矩阵顺时针转动90Java codePackage com.lizhouwei.chapter8;/** * @Description: Rotates the square matrix clockwise * @Author: Lizhouwei * @CreateDate: 2018/4/28 22:16 * @Mo Dify by: * @ModifyDate: */public class Chapter8_2 {public void rotate (int[][] matrix) {int TR = 0; int TC = 0; int DR = matrix.length-1; int DC = matrix[0].length-1

The matrix multiplication is realized by programming, and the optimization method is considered when the matrix scale is large: (1) The general solution: Matrix multiplication, 3 for loops to fix void Mul (int** Matrixa, int** matrixb, int** Matrixc) {for (int i = 0; i for (int j = 0; J (2) Strassen algorithm (block + divide-and-conquer idea): Al

Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 5015 Because it is a two-dimensional recursive formula, we didn't expect to construct a matrix like this. From the column, the current column is obtained by recursion of the previous column. Construct a matrix based on this point. B [I] represents column I, which is a matrix (n + 2) * 1, that is, B [1] = [1,233 ...

[BZOJ 2738] matrix multiplication and bzoj2738 Matrix Multiplication2738: Matrix Multiplication Time Limit: 20 Sec Memory Limit: 256 MBSubmit: 841 Solved: 351[Submit] [Status] [Discuss]Description This gives you a N * N matrix, which does not involve matrix multiplication, b

HDU 3376 -- Matrix Again [maximum cost flow Classic Graph creation], hdu3376 -- matrix Matrix Again Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 102400/102400 K (Java/Others)Total Submission (s): 3457 Accepted Submission (s): 1020 Problem DescriptionStarvae very like play a number game in the n * n Matrix. A

HDU5015-233 Matrix (Matrix Rapid power), hdu5015-233matrix Question Link Given the number of 0th to n columns in a matrix, each number starts from 1st in the first row and is 1st ........, calculates the number of m in the nth row. Train of Thought: shift the number of the first row to the right, and use the previous column to roll out the next column to constr

3240: [noi2013] matrix game time limit: 10 sec memory limit: 256 MB Submit: 613 solved: 256 [Submit] [Status] Description Tingting is a matrix-loving child. One day she wants to use a computer to generate a huge N-Row M-column matrix (you don't have to worry about how she stores it ). The matrix she generated satisfi

Network, relationship and other data into the adjacency matrix (red represents two nodes is a person, there is a link between), but the resulting matrix will be due to the order of the problem of the different arrangement, in the first will find that because there is a clustered block area and easily divide the data into two parts, Then according to the specific meaning of the data to know the meaning of it

, if there is an remainder, you can simulate it in a few steps ). Note that any replacement can be expressed as a matrix. For example, replacing 1 2 3 4 with 3 1 2 4 is equivalent to the following matrix multiplication:Replacing K/M is equivalent to multiplying the k/M matrix. We can calculate the k/M power of the matrix