tiling inside corners

Tri Tiling Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 2118 accepted submission (s): 1211 Problem descriptionin How many ways can you tile a 3xn rectangle with 2x1 dominoes? Here is a sample tiling of a 3x12 rectangle. Inputinput consists of several test cases followed by a line containing-1. Each test case is a line containing an integer 0 ≤ n

Tiling Time limit:1000 ms Memory limit:65536 K Total submissions:7437 Accepted:3635 DescriptionIn how many ways can you tile a 2xn rectangle by 2x1 or 2x2 tiles? Here is a sample tiling of a 2x17 rectangle. InputInput is a sequence of lines, each line containing an integer number 0 OutputFor each line of input, output one integer number in a separate line giving the

Tri TilingTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total Submission (s): 2118 Accepted Submission (s): 1211 Problem DescriptionIn How many ways can do tile a 3xn rectangle with 2x1 dominoes? Here is a sample tiling of a 3x12 rectangle.Inputinput consists of several test cases followed by a line containing-1. Each test case was a line containing an integer 0≤n≤30.Outputfor each test case, output one integer number

Links: http://acm.hdu.edu.cn/showproblem.php?pid=1143Tri tilingtime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others) total submission (s): 2799 Accept Ed Submission (s): 1585problem DescriptionIn what many ways can you tile a 3xn rectangle with 2x1 dominoes? Here is a sample tiling of a 3x12 rectangle.InputInput consists of several test cases followed by a line containing-1. Each test case was a line containing an integer 0≤n≤

Topic:In what many ways can you tile a 2xn Rectangle by 2x1 or 2x2 tiles?Here is a sample tiling of a 2x17 rectangle.Code:Import java.io.*;import java.math.*;import java.util.*;import java.text.*;p ublic class main{public static void Main (string[] args) { Scanner cin = new Scanner (new Bufferedinputstream (system.in)); biginteger[] Dp=new BigInteger [n]; dp[0]=dp[1]= biginteger.valueof (1); for (int i=2;iFOJ 1147

Tiling Time limit:1000 ms Memory limit:65536 K Total submissions:7454 Accepted:3640 DescriptionIn how many ways can you tile a 2xn rectangle by 2x1 or 2x2 tiles? Here is a sample tiling of a 2x17 rectangle. InputInput is a sequence of lines, each line containing an integer number 0 OutputFor each line of input, output one integer number in a separate line giving the

Label: poj recurrence, high precision Question: Give A 2 * n bar area and ask how many ways to place a square with 2*1 and 2*2. Train of Thought: F [I] = f [I-1] + F [I-2] * 2 Write a high-precision addition. Code: #include Poj 2506 tiling High Precision

Description: How many methods are there to build a 4 x W rectangle with a domino card of 1X2? Analysis: Classic question. It seems that I have done many series of such questions, and I finally got started ~ /* Zju2994 tiling a grid with dominoes */ # Include # Include # Define n 100 # Define l 20 # Define CLR (a) memset (A, 0, sizeof ()) Int MX [l] [l]; Void print (int A [], int N ){ Int I; For (I = 0; I Puts (""); } Int a

Poj 2663 Tri Tiling dp, poj2663 Question: For a rectangle of 3 * N (N Analysis: Same as poj2411. Code: # Include

Poj 3420 Quad Tiling-type dp, pojtiling Question: For a large rectangle of 4 * n (n Analysis: Tile laying again, But n is too big this time, and no more one grid of dp. You can first calculate the State transfer of the adjacent two rows, and then use the Matrix to accelerate the State transfer of n rows. Code: //poj 3420//sep9#include

http://poj.org/problem?id=2506 #include POJ2506：Tiling（递推+大数斐波那契）

Matrix Fast power. First, I want to work out the status of column I in each state, let the state fill up, the next column can appear. Because n is large, the matrix can be accelerated.#pragmaComment (linker, "/stack:1024000000,1024000000")#include#include#include#include#include#include#includeSet>#include#include#includeusing namespaceStd;typedefLong LongLL;Const DoublePi=acos (-1.0), eps=1e-8;voidFile () {freopen ("D:\\in.txt","R", stdin); Freopen ("D:\\out.txt","W", stdout);} InlineintRead ()

Test instructionsGiven a n*m lattice, each lattice is dyed black or white. Now to cover these squares with 1 * 2 bricks, it is required that the blocks and blocks do not overlap each other, and that all white squares are covered, but no black squares are covered. Find out how many kinds of coverage methods, the output scheme number to m after the result of the remainder.Input:N= 3M= 4The color of each lattice is as follows (. = white, x for Black).... x....Output:2Analysis:Since the black lattic

Serie A champions: Some existing 1*2 small boxes. 3*n how many rectangles to spell.Thinking:Because it is a recursive type. There's bound to be a layer of relationships. Careful observation, the study found that each layer should be set 21 layers. (The odd layer cannot be a rectangle) and the last battle from the last layer of the graphics card can be found. There are only two kinds of results ().Thatwatermark/2/text/ahr0cdovl2jsb2cuy3nkbi5uzxqvdtaxndu2otu5oa==/font/5a6l5l2t/fontsize/400/fill/i0

　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　　Tilingc[0]=1,c[1]=1,c[2]=3; c[n]=c[n-1]+c[n-2]*2; 0Java time:313ms1 ImportJava.util.*;2 Importjava.math.*;3 Public classMain4 {5 Static intms=251;6 Staticbiginteger[] ans;7 8 Public Static voidMain (string[] args)9 {TenScanner cin=NewScanner (system.in); Onecn1=NewBiginteger[ms]; AAns[0]=biginteger.valueof (1);//Notice here n==0 time, Ans=1; -Ans[1]=biginteger.valueof (1); -Ans[2]=biginteger.valueof (3); the for(inti=3;i) -Ans[i]=a

Thinking of others there is very clear, I will not elaborate. Link1#include 2#include 3#include 4#include 5 using namespacestd;6 Const intmaxn= -+5;7 intN;8 structBig9 {Ten intNum[maxn],len; One }; A Big ANS[MAXN]; - - voidDou (Big x) the { - for(intI=0; i) - { -x.num[i]=x.num[i]*2; + if(i>0) - { +x.num[i]+=x.num[i-1]/Ten; Ax.num[i-1]=x.num[i-1]%Ten; at } - } - if(x.num[x.len-1]>9) - { -x.num[x.len]=x.num[x.len-1]/Ten; -x.num[x.len-1]=x.num[x.len

Title: give you a 3*n ground, with 1*2 floor tile paved, ask there are several methods.Analysis: Combinatorial mathematics, dynamic programming. First find the ground to push the relationship.Only an even number is meaningful, and an odd total area of an odd number must not be true. Once we looked at the two columns as a unit.If, the last 2 columns constitute a whole part (3 cases, 2*3 3), then there is 3*f (n-2) method;If, the last 4 columns constitute a whole part (2 cases, upside down impleme

Topic Links:http://poj.org/problem?id=2506Title Description:There are 2*1 and 2*2 two kinds of porcelain pieces, asked how many ways to pave the 2*n graphics?Problem Solving Ideas:Using the recursive idea, the 2*n can be transferred from the state of the n-1 and a piece of vertical 2*1 porcelain, or by the state of the (n-2) plus a piece of 2*2 porcelain or two pieces of 2*1 horizontally.Recursive formula can be derived: dp[n] = dp[n-1] + dp[n-2]*2;AC Tips:(1): From the output sample can be seen

Test instructions: How many ways are there to cover N*m's chessboard with a 1*2 domino?This problem note do not follow the White Book MAXN open to 15, because every time to memset if open to 15 will tle, open to 11 can#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. UVA 11270 Tiling Dominoes (contour line DP Classic)

Test instructionsFor n two-tuple (a, b), in which the longest sequence is found, making any iAnalysis:Set Dp[a][b] represents the longest sequence length at (a) end, and a mnemonic search is available.Code:POJ 1609//sep9#include POJ 1609 Tiling up Blocks DP Getting started memory search