and staff 7 arranged into the 2nd office Building, the others into the Office Building No. 3rd.
First to find the original map, the request to convert to-different office buildings are not connected.
The idea is to find the complement of the connected block-obviously the complement is a dense graph, will t
The problem is to use the linked list to optimize DFS.
N
each office. Sample Input 7 161 31 41 52 33 44 54 74 65 66 72 42 72 53 56 R1 7Sample Output 31 2 4 HINT
FGD can arrange staff 4 into an office building, staff 5 and staff 7 arranged into the 2nd office Building, the others into the Office Building No. 3rd.
Source
[Submit] [Status] [Discuss]
Solving: Complement graph + link
, doing projects (5.2) Implementation of login function, interface injection, log4net use"Selfless sharing: from getting started to mastering ASP. NET MVC" starting with 0, building a framework, doing projects (5.3) Implementation of login functions, enriching data tables, establishing associations"Selfless sharing: from getting started to mastering ASP. NET MVC" starting from 0, build a framework, do projects (5.4) The implementation of login functio
Description
FGD opened a telephone company. He hired n clerks and gave each clerk a cell phone. Each employee's phone has a number of colleagues in it. As FGD's company expands, the old office building has become so narrow that FGD decided to relocate the company to some new offices. FGD wants staff to be housed in as many office buildings as possible, which will have a relatively better working environment for every employee. However, for the sake o
each office. Sample Input 7 161 31 41 52 33 44 54 74 65 66 72 42 72 53 53 71 7Sample Output 31 2 4 HINT
FGD can arrange staff 4 into an office building, staff 5 and staff 7 arranged into the 2nd office Building, the others into the Office Building No. 3rd.
Source
[Submit] [Status] [Discuss]Obviously, the answer to the question is to use all the missed edges to
number of nodes in the complete connected block in the arrayWuyi } the } - Wu intMain () { -scanf"%d%d", n, m); About for(inti =1, u, v; I //Building Map $scanf"%d%d", u, v); - Add_edge (U, v); - } - for(inti =1; I //initializes the node 1 ~ N to a list (maintaining nodes that are not in any of the connected blocks), L[0].NXT points to the header node in the current
"EditorContextMenus.CodeWindow.CreateUnitTests" is not available, you can refer to the followinghttp://dl.my/2013/create-unit-tests-function-not-available-or-disabled/or follow the steps below:Step1. Join a test caseSTEP2. New unit test fileSTEP3. Call Unit Test ListThen back to the text editor, press the right key, the magic of the event, the original anti-white selection, the seal lifted (HI).Hello, the single-yuan test has been a long time.PS. Once you have re-initiated VS, the single-elemen
Title Link: BZOJ-1098Problem analysisOnly when there are edges between the two points can they be in different buildings, that is, if there is no edge between the two points they must be in the same building.Then the request is to find the original map of the connected block.However, the number of sides of the original map is n^2 level, very large, we can not directly find the complement map.You can use a linked list to optimize the BFS approach, star
; rchild, N );}}Void depthbt (bintree T, int D, int * H){/* Calculate the depth of a binary tree */If (t){D ++;If (D> * H)* H = D;Depthbt (t-> lchild, D, H );Depthbt (t-> rchild, D, H );}}Void gradebt (bintree T, datatype CH, int D, int * n){/* Find the layer of the CH node */If (t){D ++;If (t-> DATA = CH)* N = D;Gradebt (t-> lchild, CH, d, n );Gradebt (t-> rchild, CH, d, n );}}Void main (){Datatype ch;Bintree root, T;Int D = 0, H = 0, L = 1, n = 0;Root = (bintnode *) malloc (sizeof (bintnode )
Basic operations for building a binary tree (Linked List)
Learning the data structure, I have never understood binary trees, and I have no idea how to call pointers. I learned a little about binary tree over the past two days. I first wrote the code and then learned and improved it.
# Include
# Include
Typedef char DataType;
Typedef struct node
{
DataType data;
Struct node * lchild;
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