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C Language for s (n) = A+aa+aaa+aaaa+...+aa. The value of a, where a is a number, and N is the number of bits of a, for example: 2+22+222+2222+22222 (at this time n=5), N and a are all input from the keyboard.

Ask S (n) = A+aa+aaa+aaaa+...+aa. The value of a, where a is a number, and N is the number of bits of a, for example: 2+22+222+2222+22222 (at this time n=5), N and a are all input from the keyboard.#include int main (){int n;int A;int sum = 0;int k = 0;int temp = 1;scanf ("%d,%d", n, a);for (int i = 0; iK = A;temp = 1;for (int j = 0; jTemp *= 10; Once per cycle t

c language; The sum of the first 5 items of sn=a+aa+aaa+aaaa+aaaaa where A is a number for example: 2+22+222+2222+22222

/* For the sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222*/#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Output Result:224690This article is from the "Rock Owl" blog, please be

DataSet is swapped for generic collection 222

(Convert.isdbnull (value)) {return NULL; } Type Innertype= Type. GetGenericArguments () [0]; ObjectInnervalue =Dynamicconvert (value, Innertype); returnType. InvokeMember (NULL, Bindingflags.createinstance,NULL,NULL,New Object[] {innervalue}); } //if it is a value type, and the current value is an empty string, or DBNull, the default value is returned

Java evaluates the value of S=A+AA+AAA+AAAA+AA...A, where a is a number. For example 2+22+222+2222+22222 (a total of 5 numbers are added at this time), several numbers are added by the user control.

System.out.println ("Please enter a number between 1-9:"); Prompts the user to enter a number between 1--9 Scanner sc=new Scanner (system.in); int shu=sc.nextint (); Accept the user input number as the "radix" int a=shu in the topic; Defines a variable a equals the number of user input. int sum=0; Define variables to be added as numbers and System.out.println ("Please enter the number of

S = a + AA + AAA + AAAA + AA... A, where A is a number. For example, 2 + 22 + 222 + 2222 + 22222 (a total of 5 numbers are added at this time), and the addition of several numbers is controlled by the user.

Package COM. hanqi; import Java. util. *; public class yonghukongzhi {public static void main (string [] ARGs) {// todo automatically generated method stub system. out. println ("enter a number:"); required jishu = new partition (system. in); int A = jishu. nextint (); system. out. println ("Enter the number:"); export Geshu = new partition (system. in); int B = Geshu. nextint (); int sum = 0; string c = ""; for (Int J = 0; j S = a + AA + AAA + AAAA + AA... A, where A

Find the sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222

/* For the sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222*/#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Output Result:224690Press any key to continueThis article is from the "

c language; The sum of the first 5 items of sn=a+aa+aaa+aaaa+aaaaa where A is a number for example: 2+22+222+2222+22222

Program:The sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Results:224690Press any key to continueThis article is from the "Rock Ow

The value of S=A+AA+AAA+AAAA+AA...A, where a is a number. For example 2+22+222+2222+22222 (a total of 5 numbers are added at this time), several numbers are added by the user control.

PackageLianxi;ImportJava.util.*; Public classDiejia { Public Static voidMain (string[] args) {System.out.println ("Please enter a cardinality:"); Scanner Jishu=NewScanner (system.in); intA =Jishu.nextint (); System.out.println ("Please enter the number of added numbers:"); Scanner Geshu=NewScanner (system.in); intb =Geshu.nextint (); intsum = 0; String C= ""; for(intj = 0; J ) { //A to String typec = C +string.valueof (a); //Show cardinality increment changeSystem.out.println

Find the sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222

Just use a For loop to achieve the purpose #includeFind the sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222

JS two number A, B, to find the value of S=A+AA+AAA+AAAA+AA...A, where a is a number. Add a total of B numbers, such as user input 2,5 s=2+22+222+2222+22222

JS two number A, B, to find the value of S=A+AA+AAA+AAAA+AA...A, where a is a number. Add a total of B numbers, such as user input 2,5 s=2+22+222+2222+22222

C language: The sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222

#include C language: The sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222

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