Since each piece is to be bought, then a piece of land is contained by another piece can not be considered. First by the long sort, remove the land not considered, the remaining land length x increment, width y decrement
DP (v) = min{dp (p) +xv*yp+1}
Assuming that DP (v) is transferred by the I transfer ratio by J (I>J), then
DP (i) +xv*yi+1 < DP (j) +xv*yj+1
Simplification (DP (i)-DP (J))/(yi+1-yj+1) >-XV
Then on the slope optimization, the monotone queue maintains a convex function
-----------------------------------------------------------------------------
#include <bits/stdc++.h>using namespace std; typedef long Long ll;const int MAXN = 50009;struct O {int x, y;inline void Read () {scanf ("%d%d", &x, &y);}BOOL Operator < (const O &o) Const {return x < o.x | | (x = = o.x && y < o.y);}} A[MAXN];int N = 0, R[MAXN], Q[MAXN];ll DP[MAXN];void init () {int n; scanf ("%d", &n);for (int i = 0; i < n; i++) a[i]. Read ();sort (A, a + N);int mx = 0;for (int i = n; i--;) {if (a[i].y > mx) r[++n] = i;mx = max (mx, a[i].y);}for (int L = 1, R = N; L < R; l++, r--) swap (R[l], r[r]);}inline double slope (int a, int b) {return (double) (Dp[b]-dp[a])/(a[r[b + 1]].y-a[r[a + 1]].y);} void Work () {int QH = 0, qt = 0;dp[q[qt++] = 0] = 0;for (int i = 1; I <= N; i++) {while (Qt-qh > 1 && slope (Q[QH], Q[QH + 1]) >-a[r[i]].x) qh++;Dp[i] = Dp[q[qh]] + LL (a[r[i]].x) * A[R[Q[QH] + 1]].y;while (Qt-qh > 1 && slope (q[qt-2], q[qt-1]) < slope (Q[qt-1], i)) qt--;q[qt++] = i;}printf ("%lld\n", Dp[n]);}int main () {init ();Work ();return 0;}
-----------------------------------------------------------------------------
1597: [Usaco2008 Mar] Land purchase time limit: ten Sec Memory Limit: 162 MB
Submit: 2398 Solved: 869
[Submit] [Status] [Discuss] Description
Farmer John prepares to expand his farm, and he is considering N (1 <= n <= 50,000) blocks of rectangular land. The length and width of each land is satisfied (1 <= wide <= 1,000,000; 1 <= long <= 1,000,000). The price of each piece of land is its area, but FJ can buy much faster land at the same time. The price of these lands is their largest length multiplied by their maximum width, but the length of the land cannot be exchanged. If FJ buys a 3x5 land and a 5x3, he needs to pay 5x5=25. FJ wanted to buy all the land, but he found that grouping to buy the land would save money. He needs you to help him find the minimum funds.
Input
* Line 1th: one number: N
* 2nd. N+1 Line: Line i+1 contains two numbers, respectively, the length and width of the land of Block I
Output
* First line: The minimum feasible cost.
Sample Input4
100 1
15 15
20 5
1 100
Input explanation:
There are 4 pieces of land.
Sample Output500
HINT
FJ 3 groups to buy these lands: The first group: 100x1, the second group of 1x100, the third group of 20x5 and 15x15 plot. The prices for each group were 100,100,300, a total of 500.
Source
Gold
Bzoj 1597: [Usaco2008 Mar] Land purchase (DP + slope optimization)