Fun (++i, I, i++, i++) questions

This is a few months ago a study brother asked me the question, should be a C2 level on a choice question, or quite interesting, and the Internet is not the answer to the question, the title is such

public class demo{public  static void Fun (A,b,c,d) {    System.out.println (a);    System.out.println (b);    System.out.println (c);    System.out.println (d);  }  public static void Main (string[] args) {   int i=1;  Fun (++1,i,i++,i++);}  }

The output is: 4,4,2,1 must have imagined it. The calculation steps are as follows:

The first is to clarify 2 questions 1. The function is executed in a right-to-left execution of 2. The calculation results are not returned immediately after the parameter calculation, but when all the values are computed, the results are returned. As the first question: Fun (++i, I, i++, i++)//------------------------------------------- Calculation phase---------------------------------------------------1). i++; (At that time I=1) because it is i++, the value will be saved in memory and the value in the memory will be returned to the fourth parameter d=12). i++;(then i=2) because it is i++, the value is saved in memory and the value in the memory is returned to the third parameter c=23). I; (then i=3) Because it is I will not log into memory and will return I value 4). ++i; (at that time i=4) because it is the ++i program will be based on I +1 and return I value so will not be recorded in memory will be directly returned I value//------------------------------ -------------return to the calculation result stage---------------------------------------------------5). Returns the value of the memory address in the fourth parameter (1) d=16). Returns the third parameter returns 2 ) in the memory address. Returns the second parameter returns the I value b=48). Returns the first parameter returns the I value a=4

But he has a derivative question. The arguments passed in the call to the fun function in the main function become this: Fun (++i, i++, i++, ++i);

The idea of solving problems is as follows:

The second question: Fun (++i, i++, i++, ++i);//------------------------------------------- Calculation phase---------------------------------------------------1). ++i; (At that time i=2) because it is the ++i program will be on the basis of I +1 and return I value so will not be recorded in memory will directly return I value 2). i++;(at that time i=2) because it is i++, the value is saved in memory and the value in the memory is returned to the third parameter c=23). i++;(at that time I =3) because it is i++, the value is saved to memory and the value in the memory is returned to the third parameter b=34). ++i; (at that time i=5) because the ++i program will be on the basis of I +1 and return I value so will not be recorded in memory will be directly returned I value//------------- ------------------------------returns the calculated result stage---------------------------------------------------5). Returns the fourth parameter returns the I-value d=56). Return the third parameter returns 2) in the memory address of the value c=27). Returns the value b=38 in the memory address in the second parameter returns 3). Returns the first parameter returns an I value a=5

Although the instance is written in Java, the actual operating environment is actually C + +, as for why. Because vs has disassembly. This one-step tracking debugging absolute confused, the disassembly is instead at a glance.

Fun (++i, I, i++, i++) questions