Hdoj 4248 a famous Stone collector DP

DP: DP [I] [J] How many exclusive methods are there for the J-length series in heap I,

DP [I] [J] = DP [I-1] [J] (no I heap required ),

DP [I] [J] + = DP [I-1] [J-K] * C [J] [k] (using K stones heap I)

A famous Stone collector Time Limit: 30000/15000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)
Total submission (s): 845 accepted submission (s): 322


Problem descriptionmr. B loves to play with colorful stones. There are n colors of stones in his collection. Two stones with the same color are indistinguishable. MR. B wocould like
Select some stones and arrange them in line to form a beautiful pattern. after several arrangements he finds it very hard for him to enumerate all the patterns. so he asks you to write a program to count the number of different possible patterns. two patterns are considered different, if and only if they have different number of stones or have different colors on at least one position.
Inputeach test case starts with a line containing an integer n indicating the kinds of stones mr. B have. Following this is a line containing N integers-the number
Available stones of each color respectively. All the input numbers will be nonnegative and no more than 100.
Outputfor each test case, display a single line containing the case number and the number of different patterns mr. B can make with these stones, modulo 1,000,000,007,
Which is a prime number.
Sample Input

31 1 121 2

 
Sample output

Case 1: 15Case 2: 8HintIn the first case, suppose the colors of the stones Mr. B has are B, G and M, the different patterns Mr. B can form are: B; G; M; BG; BM; GM; GB; MB; MG; BGM; BMG; GBM; GMB; MBG; MGB. 

 
Sourcefudan local programming contest 2012

#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>using namespace std;typedef long long int LL;const LL MOD = 1000000007LL;LL C[11000][210];void getC(){    for(int i=0;i<11000;i++) C[i][0]=C[i][i]=1;    for(int i=2;i<11000;i++)        for(int j=1;j<i&&j<=200;j++)            C[i][j]=(C[i-1][j]+C[i-1][j-1])%MOD;}LL dp[110][11000];int n,a[110];int main(){    getC();    int cas=1;    while(scanf("%d",&n)!=EOF)    {        for(int i=1;i<=n;i++)            scanf("%d",a+i);        memset(dp,0,sizeof(dp));        int len=0;        dp[0][0]=1;        for(int i=1;i<=n;i++)        {            len+=a[i];            for(int j=0;j<=len;j++)            {                dp[i][j]=(dp[i][j]+dp[i-1][j])%MOD;                for(int k=1;k<=a[i]&&j-k>=0;k++)                {                    dp[i][j]=(dp[i][j]+dp[i-1][j-k]*C[j][k])%MOD;                }            }        }        LL ans=0;        for(int i=1;i<=len;i++)            ans=(ans+dp[n][i])%MOD;        printf("Case %d: %lld\n",cas++,ans%MOD);    }    return 0;}

Hdoj 4248 a famous Stone collector DP