JOBDU 7 Day of Week

Topic Description:

We now use the Gregorian style of dating in Russia. The leap years are years with number divisible from 4 but not divisible by, or divisible by 400.
For example, years, 2180 and 2400 are leap. Years, 2181 and 2300 are not leap.
Your task is to write a program which would compute the day of week corresponding to a given date in the nearest past or in The future using today ' s agreement about dating. Input:

There is one single in contains the day number D, month name M and year number Y (1000≤y≤3000). The month name is the corresponding 中文版 name starting from the Output:

Output a single line with the Chinese name of the ' the ' of the ' week corresponding to ' date, starting from the ' capital letter. All the other letters must are in the lower case. Sample input:

9 October 2001
October 2001

Sample output:

Tuesday
Sunday

Tips:

Month and Week name in Input/output:
January, February, March, April, May, June, July, August, September, October, November, December
Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday

#include <stdio.h> #include <string.h> #define ISYEAP (x) (x%4==0) && (x%100!=0) | |
(x%400==0)? 1:0 int dayofmonth[13][2]= {0, 0, 31, 31, 28, 29, 31, 31, 30, 30, 31, 31, 30, 30, 31, 31, 31, 31, 30, 30, 31, 31, 30, 30,
31,31};
  struct Date {int day; int Month; int, year; void NextDay () {day++;
   if (Day>dayofmonth[month][isyeap (year)]) {Day=1;
   month++;
    if (month>12) {month=1;
   year++;
}
  }
}
};
int buf[3001][13][32]; 
Char monthname[12][20]= {"January", "Febuary", "March", "April", "may", "June", "July", "August", "September", "October",
"November", "December"};
Char weekname[7][15]= {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"}; int main () {Date tmp; tmp.
year=0; Tmp.
month=1; Tmp.
Day=1;
int cnt=0; while (TMP. year!=3001) {buf[tmp. Year][tmp. Month][tmp.
  day]=cnt;
  Tmp.nextday ();
cnt++;
int D,y,days,mon;
Char m[15]; while (scanf ("%d%s%d", &d,m,&y)!=eof) {for (int i=0;i<12;i++) if (strcmp (m,monthname[i])
  ==0) mon=i+1;
  DAYS=BUF[Y][MON][D]-BUF[2013][2][17];
printf ("%s\n", weekname[(days%7+7)%7]);
return 0; }