Questions about the divisor, divisor, quotient, and remainder in programming

Examples are as follows:

Class test{

System.out.println ("1/10=" +1/10);

System.out.println ("1%10=" +1%10);

System.out.println ("2/10=" +2/10);

System.out.println ("2%10=" +2%10);

}

The results are as follows

1/10= 0

1%10= 1

2/10= 0

2%10= 2

Self-summary analysis: In programming if "dividend" is less than "divisor", "quotient" (that is,/) is all 0, "remainder" (that is,%) is "dividend".

A programming problem that extends from this

public class Test {

public static void Main (string[] args) {


int i = 0;
while (true) {
i = (i+1)%10;//divisor is 10, the remainder will never exceed 10, so the output number will always be less than 10.
System.out.println (i);
}

}

}

This is a programming question with an infinite output of 10 or less digits.

Because the divisor is 10, so no matter how much I grow, the rest of the number is not more than 10, so the result is always controlled between 0-9.

Examples are as follows: I =10, i%10=0;

i=23,i%10=3;

i=36,i%10=6;

I=100023,i%10= 3;

No matter how big the dividend, the remaining number is the number on the rightmost single digit in the quotient.

Like 1/10, it's 01,2/10, it's 02.

10/10 the above is 10 bits for a bit 0, so the quotient is 0

32/10, above 10 bit is 3, digit is 2, therefore 32%10=2;

Never find out why this is to be calculated, just do a little analysis according to the rules, busy record down.

If someone finds a mistake, make sure to leave a message.

Questions about the divisor, divisor, quotient, and remainder in programming