UVa 488 triangle Wave (water ver.)

488-triangle Wave

Time limit:3.000 seconds

Http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=94&page=show_problem &problem=429

In this problem your are to generate a triangular wave form according to a specified pair of amplitude and Frequency.

Input and Output

The input begins with a single positive integer in a line by itself indicating the number of cases following, each of them as described below. This are followed by a blank line, and there are also a blank line between two consecutive.

Each input set would contain two integers, each in a separate line. the amplitude; The second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases is separated by a blank line.

For the output of your program, you are printing wave forms each separated by a blank line. The total number of waves forms equals the Frequency, and the horizontal ' height ' of each wave equals the amplitude. The amplitude would never be greater than nine.

The waveform itself should is filled with integers on each line which indicate the ' height ' of this line.

Note: There is a blank line after each separate waveform, excluding the last one.

Sample Input

1

3
2

Sample Output

1
333
1

1
333
1

Complete code:

/*0.065s*/
  
#include <cstdio>
  
int main (void)
{
    int T, A, F;
    int I, j, K, L;
    scanf ("%d", &t);
    for (i = 0; i < T; i++)
    {
        if (i)
            putchar (' \ n ');
        scanf ("%d%d", &a, &f);
        for (j = 0; J < F; J +)
        {
            if (j)
                Putchar (' \ n ');
            for (k = 0; k < A; k++)
            {for
                (l = 0; l <= k; l++)
                    Putchar (' 1 ' + K);
                Putchar (' \ n ');
            }
            for (k = A-2 k >= 0; k--)
            {for
                (l = 0; l <= k; l++)
                    Putchar (' 1 ' + K);
                Putchar (' \ n ')
            ;
    }} return 0;
}

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