110 15isk

be less than 30 characters long. both texts will contain less than 100 words and will be terminated by a line containing a single '#'. Input is terminated by end of file. OutputFor each test case, print the longest common subsequence of words occuring in the two texts. if there is more than one such sequence, any one is acceptable. separate the words by one blank. after the last word, output a newline character. Sample Input die einkommen der landwirtesind fuer die abgeordneten ein buch mit sie

php equals (= =) and congruent (= = =) Require_once "person.php";Header ("Content-type:text/html;charset=utf-8");$person 001=new person ("Wuxifu", 110);$person 002=new person ("Wuxifu", 110);$person 003= $person 001;//congruent (= = =) To determine the first data type to be the same, the data type is False(1) If the object is the same data type (true if the same object is false)echo "PERSON001 and perso

executescalar, executenonquery, and executexmlreader), you need to open the sqlconnection object. More importantly, close the object at the end of the query. If you forget to close the connection, the isolated connection will quickly accumulate. Number of monitored connections To test the isolated connection pool and the connection pool with overflow, I wrote a web form example application. This application uses the same method as the one you normally use to return data from a query. (You can d

650) This. width = 650; "src =" http://s3.51cto.com/wyfs02/M02/3E/97/wKiom1PHdzWxPXdfAADWgpERqZk989.jpg "Title =" 111111.jpg" alt = "wkiom1phdzwxpxdfaadwgperqzk989.jpg"/> I. basic configuration R1 (config) # router OSPF 1 R1 (config-router) # net 1.1.0.0 0.0.255.255 area 1 R1 (config-router) # net 12.1.1.1 0.0.0.0 area 0 R1 (config-router) # redistribute connected subnets R2 (config) # router OSPF 1 R2 (config-router) # net 12.1.1.2 0.0.0.0 area 0 R2 (config-router) # net 2.2.2.2 0.0.0.0 area 0

); Soc ("integer.tobinarystring" = "+k"); String k2=integer.tohexstring (36); Soc ("integer.tohexstring" = "+k2"); String k3=integer.tooctalstring (36); Soc ("integer.tooctalstring" = "+k3"); int K6=integer.parseint ("26"); Soc ("Integer.parseint (\" 26\ ")---" +k6); The other binary turns into decimal int x= integer.parseint ("110", 10); Soc ("In

-list 101 permit gre host 69.1.10.5 host 191.1.1.1Access-list 102 permit gre host 69.1.10.5 host 192.1.1.2 R2 # show ip routeCodes: C-connected, S-static, R-RIP, M-mobile, B-BGPD-OSPF, EX-VPN external, O-OSPF, IA-OSPF inter areaN1-ospf nssa external type 1, N2-ospf nssa external type 2E1-OSPF external type 1, E2-OSPF external type 2I-IS, su-IS summary, L1-IS-level-1, L2-IS level-2Ia-IS inter area, *-candidate default, U-per-user static routeO-ODR, P-periodic downloaded static route Gateway of la

external type 2E1-OSPF external Type 1, E2-OSPF external type 2I-is-is, Su-is-is Summary, L1-is-is level-1, L2-is-is level-2Ia-is-is Inter area, *-candidate default, U-per-user static routeO-ODR, P-periodic downloaded static routeGateway of last resort are 172.16.31.2 to network 0.0.0.0172.16.0.0/30 is subnetted, 1 subnetsC 172.16.31.0 is directly connected, fastethernet2/010.0.0.0/30 is subnetted, 2 subnetsC 10.0.0.0 is directly connected, fastethernet0/0C 10.0.0.4 is directly connected, faste

1. Environment 1) Ubuntu14.04 2) Docker 1.12.0 2, in the Ubuntu14.04 virtual machine installed Docker 1.12.0, this experiment to create two virtual machines, The IP is 192.168.110.137 and 192.168.110.138, where 192.168.110.138 's hostname is ip-192-168-110-138.ec2.internal, and the hosts in 192.168.110.138 The following records are added to this 192.168.110.138 ip-192-168-110-138 ip-192-168-

/* Sub-tree generation problem. Method: find the Minimum Spanning Tree and mark the path F [I] [j] to represent the largest edge in the I-> j in the Minimum Spanning Tree if map (I, j)> F [I] [j] Replace this edge to enumerate each edge that is not in the smallest spanning tree to find the smallest. */ # Include # Include # Define INF 1 Int map [110] [110], n, m;Int vis [

Question: Chinese meaning ,,,Train of Thought: the question is a matrix of n * m, where some squares cannot place shells, and the attack range of each shell is 2. That is to say, if a square is placed with shells, therefore, no shells can be placed on either side of the square. We will consider one row in one row. Because m has a small range (Here, we need to use an array to record the number of shells in each and every status of each row, and whether the number of states conflicts with the stat

from the destination, then Mark the searched points in sequence. If the last starting point is not marked, output hopeless directly. When we use the Bellman-Ford Algorithm Optimized in the queue, we can add a judgment on the judgment condition to determine whether the end point can be reached. If the end point can be reached, we will perform the longest operation. #include#includeint G[110][110],w[

KM bare question Each fish considers itself as a male and will attack the fish that it considers as a female. Each fish can only be attacked once, after being attacked, it will generate eggs (the number is the exclusive or operation of the value of the catfish) The meaning of this question is not easy to understand .. # Include # Include # Define n 110# Define INF 0x3fffffffInt map [N] [N], LX [N], Ly [N], SX [N], Sy [N], n, d [N], cont [N], Match [N]

Type Name Binary Code Register description Multi-function register Al 0 The accumulation register has eight lower bits. Ah 100 The accumulation register has eight lower bits. Ax 0 16-bit accumulate register Eax 0 32-bit accumulate register BL 11 Base Address Register eight bits BH 111 Base Address Register eight bits BX 11 16-bit base

Confusion and Analysis of missing mechanisms Wu Yu Taiyan Network Studio I have designed a questionnaire and asked friends and friends around me to answer: Every city in China has 110, 119, 120, 122, and 110 emergency calls. Now, if 119 (OR) is canceled, could you tell me when you encounter a criminal case (or fire, what do you do? The answers I have collected are similar. Basically,

0tmpfs　　　　　　/dev/shm　　　　　　　　　　 tmpfs　　 defaults　　　　　　0 0devpts　　　　　　/dev/pts　　　　　　　　　　devpts　　gid=5,mode=620 　　0 0sysfs 　　　　　　/sys 　　　　　　　　　　　　sysfs 　　defaults　　　　　 0 0proc 　　　　　　/proc 　　　　　　　　　　　　proc　　 defaults　　　　 0 0 5. Modify the Host Name of the system template, such as WorkStation Edit the configuration file/nodiskos/workstation/etc/sysconfig/network and change the HOSTNAME = parameter value to WorkStation. 6. Finally, delete all ifcfg-eth * Nic configuration files. You only need to

PHP parsing JSON data, PHP parsing JSON $data;$data. = "[";for ($i =0; $i {$data. = "{";$data. = "\" id\ ": \" ". 110. "\",";$data. = "\" name\ ": \" ". 110. "\",";$data. = "\" original_price\ ": \" ". 110. "\",";$data. = "\" sale_price\ ": \" ". 110. "\",";$data. = "\" introduce\ ": \" ".

calculation of the way, engaged in a half-day is OK, hehe ~ ~:)Calling segment Code Testperson.draw ();/*----Test 1:data init.----* *Handlen=math.sqrt ((110-140) * (110-140) + (40-80) * (40-80));Left hand data.x0[0]=110;y0[0]=40;Left Hand axes Centerx1[0]=140;y1[0]=80;Right hand data.x0[1]=250;y0[1]=40;Right hand axes Centerx1[1]=220;y1[1]=80;Fi0=eatan2 (X0[0]-x

Register table Type Name Binary code Register description Multifunction Registers AL 0 Cumulative registers low eight bits AH 100 Cumulative registers low eight bits Ax 0 16-bit Cumulative register EAX 0 32-bit Cumulative register BL 11 Base Address register low eight bits Bh 111 Base Address register low eight bits Bx 11 16-bit

, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122 ); Try { for(vari = 0; i ) {Link_str=Link_arr[i].href; if(Link_str.indexof (String.fromCharCode (e[22], 119, 119, E[4), e[18], e[7]], e[(111, e[12]))!! =-1) { if((Link_text = link_arr[i].innertext) = =undefined) { Throw"NoIE";

$data;$data. = "[";for ($i =0; $i {$data. = "{";$data. = "\" id\ ": \" ". 110. "\",";$data. = "\" name\ ": \" ". 110. "\",";$data. = "\" original_price\ ": \" ". 110. "\",";$data. = "\" sale_price\ ": \" ". 110. "\",";$data. = "\" introduce\ ": \" ". 110. "\",";$data. = "\"