2048 javascript

)); Int N; bool mark; scanf ("% d % * C", N ); Fillbox (n); print (N ); While (true) {char ch; scanf ("% C % * C", Ch); If (CH = 'A') {mark = left (n );} else if (CH = 'D') {mark = right (n);} else if (CH = 'W') {mark = up (n );} else if (CH ='s ') {mark = down (n);} else {continue;} system ("CLS"); printf ("Move: \ n "); print (n); If (! Mark) {continue;} fillbox (n); printf ("fill: \ n"); print (N ); If (isover (N) {printf ("\ n \ Ngame over! \ N "); break;} return 0 ;} /* Method Descriptio

2048 waiting to write Java version

#include int main (){int i,j,n,m;__int64 a[22]={0,0,1,2},s;float b[22];b[2]=0.5;b[3]= (float) 1/3;for (i=4;i{a[i]= (i-1) * (A[i-1]+a[i-2]);S=1;for (j=1;jS*=j;b[i]= (float) a[i]/s;//There is no parentheses here at a[i]/s because it causes errors in the first calculation.}scanf ("%d", n);while (n--){scanf ("%d", m);printf ("%.2f%%\n", b[m]*100);}return 0;}Copyright notice: This article Bo Master original articles, blogs, without consent may not be reproduced. Hangzhou Electric

Tecardsprite (int flag); Random generation of the regular generation of numbers to move upward is generated in the following Private:int Firstx,firsty,endx,endy; Touch point coordinates cardsprite *CARDNUM[4][4]; Create an array object with digital energy 4*4}; Class Cardsprite:public Cocos2d::ccsprite{public: virtual bool init (); static cardsprite* createcardsprite (int numbers,int width,int height,float cardspritex,float CardSpriteY); Create_func (cardsprite); int GetNumber ()

cell is followed by a line-break - if(0= = (I 3)) { thePutchar ('\ n');Bayi } the } the - //read input from keyboard - if(! W2)) { theRead (0, k,3); theS (1, k[(K >> X)%4]); the T (); the } - } the the int theMain (void)94 { the //Uses Stty to clear the screens in preparation for the game theSystem ("Stty Cbreak"); the 98 /*intializes random number generator*/ About Srand ((unsigned) time (NULL)); - 101 T ();102 103 //Game have finished by this point104 //If win, displ

the number of test instances, followed by the C row of data, each line containing an integer n (1Output for each test instance, export the percentage that this occurs, the output of each instance is a row, and the result retains two decimal places (rounded), in the exact format, refer to sample output.Sample Input1 2Sample Output50.00%AUTHORLCY////According to the test instructions, the total number of n=, c= the result of the wrong formula, d=n the whole arrangement; results =c/d; The problem

, representing the number of test instances, followed by the C row of data, each line containing an integer n (1Output for each test instance, export the percentage that this occurs, the output of each instance is a row, and the result retains two decimal places (rounded), in the exact format, refer to sample output.Sample Input12Sample Output50%AuthorlcyThe source recursive Solution topic exercise (for beginner) describes itself. n individual n votes, ask everyone to take the wrong vote method

map,Now we have to add a vector (set) to hold all the blocks.GameScene.h:vectorAnd then. In Init. We created the lattice, and then, with a number block,It's going to produce a random block.Add a method--newnumbertiledThis function is to create a new block:void gamescene::newnumbertiled () {//Create an instance of a number block auto tiled = Numbertiled::create ();//Find a location with several spare int freecount = 16-m_allt Iled.size (); int num = rand ()% freecount;int row = 0,col = 0,count =

This isWritten in C + +, in fact, using the input and output of C + +, the rest is all C contentThe code is detailed, very simple, welcome to learn from and exchange#include 2048 Console Edition

Simple DP. DP [I] [J]: in the position I, the status of decline is J, and the maximum profit is obtained. Enumeration status. If the number X to be added is greater than the minimum number X, the status changes to X. If X is smaller than the smallest, the status is J + X. If X is equal to the smallest value, it is incremented sequentially until the smallest value is greater than X. # Include Zoj-3802-Easy 2048 again

Scroe:HTML+CSS+JS implementation 2048

= Event.gety ( ); Break;case MotionEvent.ACTION_UP:offsetX = Event.getx()-startx;offsety = Event.gety ()-starty;if (Math.Abs (OffsetX) >math.abs (OffsetY)) {if (offsetxImport Android.content.context;import Android.view.gravity;import Android.widget.framelayout;import Android.widget.textview;public class Card extends Framelayout {public Card (context context) {super (context); label = new T Extview (GetContext ()); Label.settextsize (+); Label.setbackgroundcolor (0X33FFFFFF); Label.setgravity (

Write a more hurried, more simple function, the interface is ugly, the operation of the number of steps should also be optimized.Ultimately, it is to write AI, but it seems not so simple, write a few about the pattern evaluation function, you have to continue to learn ...Left and RIGHT ARROW key operation.Source:Import Java.awt.borderlayout;import java.awt.color;import Java.awt.font;import Java.awt.gridlayout;import Java.awt.event.*;import Java.util.random;import Javax.swing.jframe;import Javax.

1. Capturing keyboard events"2048" The operation of the game mainly depends on the keyboard on the top, bottom, left and right to complete, first we need to capture the keyboard response in the Game.js file event.$ (document). KeyDown (function (event) {switch (event.keycode) {case 37://leftbreak;case 38://upbreak;case 39:// Rightbreak;case 40://downbreak;default:break; }});After the keyboard event is captured, we need to complete the specific game

#include Bug version ConsoleApplication6.cpp: Defines the entry point of the console application. There are Bug#include "stdafx.h" #include C + + write 2048

God, God, and Jesus Christ. http://acm.hdu.edu.cn/showproblem.php?pid=2048 Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others) Problem Description HDU 2006 ' ACM Contest Awards Party Grand start! In order to enliven the atmosphere, the organizers held an innovative, the prizes of the rich lottery, the specific requirements of this activity is: first of all, all the participants in the party will be a note of their own n

, Bluetooth 4.0 Bluetooth Yes OTG Yes, USB-OTG Hdmi N/A Fm N/A Multi-Media: Audio player Amr/mp3/wma/wav/midi/etc. Video player Wmv,rm,avi,rmvb,mp4,mpg,mpeg, FLV, support 4K Video Play Picture Format Jpg/bmp/png/gif,etc.

of this, so that the implementation of the Code feel better understanding, but there are great problems in efficiency, such as the user's operation recorded a lot of memory occupancy rate will be higher (no actual detection of how many), power consumption will certainly increase a lot, I think that's one of the reasons why some versions of 2048 offer only a few steps to undo functionality. If you have any better ways to achieve, welcome messages or p

Cocos2d-x 3.2-2048-Article 3 OK. update it now. To put it short, go straight to the topic, article 3: -- Create a digital block class What is a digital block? -- That is, the number you slide, and the number that appears randomly. First, create a NumberTiled class that inherits from Node: NumberTiled. h: # Ifndef _ test2048_NumberTiled_H __# define _ test2048_NumberTiled_H __# include cocos2d. hUSING_NS_CC; class NumberTiled: public Node {public:

, score):d IRCT = Raw_input ("Step:%d Score:%d (%s):"% (Step, score, declare)) DIRCT = Dirct.lower ()if dirct = ="Q":Breakelif DIRCT = =Aor DIRCT = ="h":d IRCT =0elif DIRCT = ="S"or DIRCT = ="J":d IRCT =1elif DIRCT = ="W"or DIRCT = ="K":d IRCT =2elif DIRCT = ="D"or DIRCT = ="L":d irct =3elif DIRCT = ="B":If Len (mtr_stk) = =1:print "Can ' t back ..." else:mtr_stk.pop () scr_stk.pop () mtr = copy.deepcopy (Mtr_stk[ -1]) score = Scr_stk[-1]step-= 1 Continueelse:print illegal Continuetmp = Copy.de