Today, my friend asked a particularly tangled question:
In a table in the database, the table duplicates a field in the table and sorts the remaining data according to another field,
Create a table as follows:
Create table TEST_DISTINCT (ID integer not null,NAME varchar (20) not null);
Insert into TEST_DISTINCT values (0, 'A ');Insert into TEST_DISTINCT values (1, 'bb ');Insert into TEST_DISTINCT values (2, 'cc ');Insert into TEST_DISTINCT values (3, 'dd ');Insert into TEST_DISTINCT values (4, '
gcmc, gkrq having
Count (*)> = 1 order by GKRQ)
Select * from gczbxx_zhao where viewid in (select max (viewid) from gczbxx_zhao group
Gcmc) order by gkrq desc --- this is feasible.
One question says: the efficiency of distinct deduplication is very low. I saw this article on the Internet as if it was very efficient to use group by having?
In a test, I have a product table with 0.26 million records. Only the product number is indexed and the brand nam
Php 3D array deduplication (sample code ). Suppose it is called array $ my_array; copy the code as follows: create an empty array. $ tmp_arrayarray (); $ new_arrayarray (); 1. loop all rows. ($ val is a row) suppose it is an array $ my_array;
The code is as follows:
// Create an empty array.$ Tmp_array = array ();
$ New_array = array ();
// 1. loop all rows. ($ val is a row)Foreach ($ my_array as $ k => $ val ){
$ Hash = md5 (json_encode ($ va
", "list remove finish." Size now is 50! "); Jsondata= Utilshelper.beanconverttojson (NewMessage (0, "Success", list)); }Else{LOG.D ("Cachethread", "list size is 0!"); } //save JSON characters locally so you can browse offline without a network if(Jsondata! =NULL) {utilshelper.savejsontextinlocalfile (jsondata); }Else{LOG.D ("Cachethread", "Jsondata is NULL!!"); } } }This will only intercept up to 50 joke messages to avoid slow read and write p
-15 8765487654 15-1Remove the elements from the original list in a linked list and put them in a new list.#include #defineMAXN 10000+50#defineMAXV 100000+50using namespacestd;intAbsoluteintx);BOOLVIS[MAXN];//pairvectorint,int> >Resulting;vectorint,int> >removed;//Pairpairint,int>ARR[MAXV];intMain () {memset (Vis,false,sizeof(VIS)); intstartaddress, num; scanf ("%d%d", startaddress, num); for(inti =0; i i) { intCuraddress, Val, nextaddress; scanf ("%d%d%d", curaddress, val, nextaddress);
The array_unique () function of PHP allows you to pass an array, remove duplicate values, and return an array with unique values, this article describes how to implement PHP array de-duplication quickly. For more information, see this article.
The array_unique () function of PHP allows you to pass an array, remove duplicate values, and return an array with unique values. This function works well in most cases. However, if you try to use the array_unique () function in a large array, it will ru
Php array deduplication function code example
/**
* Function for removing repeated values in the array
* By bbs.it-home.org
*/
Function array_assoc_unique ($ arr, $ key ){
$ Tmp_arr = array ();
Foreach ($ arr as $ k =>$ v ){
If (in_array ($ v [$ key], $ tmp_arr )){
Unset ($ arr [$ k]);
} Else {
$ Tmp_arr [] = $ v [$ key];
}
}
Sort ($ arr );
Re
This article mainly introduces the php two-dimensional array merging and deduplication methods. The example analyzes the php techniques for merging arrays and deleting repeated items, for more information about how to merge and deduplicate two-dimensional php arrays, see the example in this article. Share it with you for your reference. The specific implementation method is as follows:
$ Arr = array_merge ($ labels, $ label); // merge the two arr
); - //registering a merge class $Job.setcombinerclass (Reduce.class); the //Register Reducer Class theJob.setreducerclass (Reduce.class); the //registering the output format class theJob.setoutputkeyclass (Text.class); -Job.setoutputvalueclass (Text.class); in //setting the input and output path theFileinputformat.addinputpath (Job,NewPath (otherargs[0])); theFileoutputformat.setoutputpath (Job,NewPath (otherargs[1])); About the //Run the
var New Array (); if ($ ("input[name= ' type ']"). val ()! = "") {= $ ("input[name= ' type ')"). Val (). Split ("," ); if (SelectedValue! = "" $.inarray (SelectedValue, valuearr) = =-1) { valuearr.push (selectedvalue); } $ ("input[name= ' type ']"). Val (Valuearr.sort (). join ());JavaScript strings are transferred to and from arrays, and data
Deduplication of javascript Arrays
// Remove the Array of numeric elements function sortnum (a, B) {return a-B;} Array. prototype. unique1 = function () {this. sort (sortnum); var newnumbers = [this [0]; for (var I = 0; I
Python refresh question-use stdin for input and output-random array deduplication, pythonstdin
Original question address:
Explicit Random Number
The rules for input of a given variable may vary in different websites and different given questions. Generally, the most common input method is the sys. stdin method.
For example, this simple question:
1.Input description:Input Multiple rows, enter the number of random integers, and then enter the correspond
Private Static voidcheck (string[] array) {//what are the string arrays that contain non-repeating strings? The number of each repetitionmap//① Traversal MapSystem.out.println ("Traverse key and Value by Map.keyset ():"); for(String key:map.keySet ()) {System.out.println ("The array is:" + key + "=" +Map.get (key)); } //②mapset (). Iterator ()SYSTEM.OUT.PRINTLN ("Traversal of key and value through Map.entryset () iterator ()"); IteratorMap.entryset (). iterator (); while(It.hasn
Detailed explanation of the javascript array deduplication problem, detailed explanation of the javascript Array
First, I want to create another result array to store non-duplicated data in the original array. Traverse the original array and compare it with the elements in the result array to check whether the elements are repeated. As a result, I wrote the following:Code:
Array.prototype.clearRepetitionA = function(){ var result = []; var isRepet
Array. prototype. unique1 = function (){Var arr = [];For (var I = 0; I // Check whether there are any arrays in it. If not, put them in.If (arr. indexOf (this [I]) =-1 ){Arr. push (this [I]) } }Return arr;}Array. prototype. unique2 = function (){Var arr = [],Json = {};For (var I = 0; I // Use a hash table and use keywords to determine deduplication// If no current entry exists in the hash tableIf (! Json [this [I]) {Json [this [I] = true;Arr. push (th
Array deduplication
Src: http://yiminghe.javaeye.com/blog/524716
This is a classic problem. After removing the repeated elements in the array, I searched the internet and found that most of them are the solution regardless of reposted or original:
Solution:Js Code
Function uniq (array ){
Var map = {};
Var re = [];
For (var I = 0, l = array. length; I
If (typeof map [array [I] = "undefined "){
Map [array [I] = 1;
Re. push (array [I]);
}
}
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