edi 837

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Skills to be mastered by virus analysis

injected in a very much way5. Counter-debug technology anti-virtual machine detection Flower Instruction solution IDC Script network data analysis debugging method6. A certain compilation of knowledge1.mov edi,ediis a two-byte NOP, which is the same as NOP in the program.Then why use MOV edi,edi not two NOP?Because NOP CPU clock cycle is longer than with MOV

The relationship between function recursion and stack

First, through the anti-assembly language, let's look at the simplest recursive function and the relationship between the stack.How to get anti-assembly language, in Visual Studio 2008, in the debug environment, you can view the post-disassembly languages in debug/windows/disassembly. Now let's take a look at factorial n! The implementationIts C language implementation code is as follows[CPP]View Plaincopy #include int factorial (int n); int main (void) { int fact; Fact = factor

function calling convention

..Parameter Pass Order1. Right-to-left in the stack: __stdcall,__cdecl,__thiscall,__fastcall2. From left to right into the stack: __pascalMain description __stdcall and __cdecl difference1...__stdcall The called function itself is responsible for stack balancing2...__CDECL Call function is responsible for the stack balance of the functionThe __stdcall function itself is responsible for stack balancing *********************////////////////Int__stdcalla (intv1,intxx) {return5;} Intmain () {intt=a

In-depth study of the C ++ Object Model

009616a9 push EDI 009616aa Lea EDI, [ebp-1E8h] 009616b0 mov ECx, 77 H 009616b5 mov eax, 0 cccccccch 009616ba rep STOs dword ptr es: [EDI] 009616bc mov eax, dword ptr [___ security_cookie (96a0a8h)] 009616c1 XOR eax, EBP 009616c3 push eax 009616c4 Lea eax, [ebp-0Ch] 009616c7 mov dword ptr fs: [00000000 H], eax Ivtbl * pvtbl = NULL; 009616cd

At&t compilation Study Notes

", "O" -- indicates the memory unit "R" -- indicates any register "Q" -- indicates the registers eax, EBX, ECx, one of edX's "I" and "H" -- represents the direct operands "E" and "F" -- represents the floating point "G" -- represents any "A", "B ", "C", "D" -- indicate that registers eax, EBX, ECx, and EDX "S" are required ", "D" -- requires the use of register ESI or EDI "I" -- represents a constant (0-31) In addition, if an operand requires the sam

Solve the Chinese problem of the MASM programming dialog box

The ustring macro in the Dialog. inc file in MASM32 is faulty. As a result, a problem occurs when a Dialog box containing Chinese characters is displayed using a macro related to the Dialog box. The original code is as follows: ; ------------------------------------------------ ; write unicode string at current location in EDI ; ------------------------------------------------ ustring MACRO quoted_text LOCAL asc_txt .data

GCC _ ASM _ example

most cases, \ n is followed by a \ t, where \ n is for line feed, \ t is to empty a tab width space) to separate them. For example: _ ASM _ ("movl % eax, % EBXSTIPopl % EDISubl % ECx, % EBX "); _ ASM _ ("movl % eax, % EBX; STIPopl % EDI; subl % ECx, % EBX "); _ ASM _ ("movl % eax, % EBX; STI \ n \ t popl % EDISubl % ECx, % EBX "); All are legal statements. If you place the instruction in multiple pair quotation marks, a semicolon (;) or (\ n) must be

One of the basics of assembly language-Introduction to CPU architecture and register types

commands can only be used in specific registers. For example, the in and out commands are hardware-fixed and can only be used in the eax registers. ECx is used for cyclic counters, and EDI and ESI are used for index commands and string commands. The addressing mode can only be used in specific registers. The i-386 family has six General registers, eax, EBX, ECx, EDX, EDI, ESI. each register starts with t

How to Understand the const source and var dest in the move Parameter

], 4 );Move (XX, a [0], 4 );End; By the way, explain the Pascal source code of move (Windows XP SP2 DELPHI6 + update2 ): Procedure move (const source; var DEST; count: integer );{$ Ifdef purepascal}VaRS, D: pchar;I: integer;BeginS: = pchar (@ source );D: = pchar (@ DEST );If S = d then exit;If Cardinal (d)> Cardinal (s) Then // essence 1: Be careful, don't overwrite SourceFor I: = count-1 downto 0 doD [I]: = s [I]ElseFor I: = 0 to count-1 doD [I]: = s [I];End; {$ Else}ASM{-> Eax pointer to sourc

SSDT table concepts and ssdt concepts

called Based on the address of the System Service stored in this SSDT item. For example, the system service corresponding to the address stored in the KeServiceDescriptorTable [105 h] is called, that is, NtQuerySystemInformation under Ring0. Differences between Zw and Nt functions in the kernel Lkd> u ZwQuerySystemInformation Nt! ZwQuerySystemInformation: 84456c38 b805010000 mov eax, 105 h // put 105 h into Register eax 84456c3d 8d542404 lea edx, [esp + 4] 84456c41 9c pushfd 84456c42 6a08 pus

Delphi Image Processing-USM sharpening

positive and negative differences; 7. The original pixel is added with the positive difference value minus the negative difference value, and the sharpening is completed. The following is the USM sharpening code, including the Gaussian fuzzy code (for details about Gaussian blur, see the article 《Delphi Image Processing-Gaussian blur, The following Gaussian fuzzy code is also copied from this article ): Procedure crossblur (var dest: timagedata; const Source: timagedata; weights: pointer; radiu

Relationship between function recursion and stack

First, through the disassembly language, let's take a look at the relationship between the simplest recursive function and the stack. In Visual Studio 2008 and debug environments, you can view the language after disassembly in debug/Windows/disassembly. Now let's take a look at factorial n! Implementation The C language implementation code is as follows: #include The language after disassembly is as follows: Main Program int main(void){00DB1FD0 push ebp 00DB1FD1 mov ebp,esp

Problems related to the pressure stack of C-language function call parameters

at the disassembly below:C code same as above Ubuntu +Bit disassembly:intMain () {804846D: - Push %EBP 804846E: theE5 mov%esp,%EBP 8048470: theE4 f0 and $Xfffffff0,%esp 8048473: theEcTen Sub $0x10,%esp Test (1, 2); 8048476: C7 - - Geneva Geneva xx xxMovl $X2,0x4(%esp)804847D:xx 804847E:c7Geneva - on xx xx xxMovl $X1, (%esp)8048485: E88A FF FF call8048414return 0;804848A:b8xx xx xx xxmov $x0,%eax}intTestintAintb) {8048414: -

C + + function call process in-depth analysis < go >

of instruction (below) are to assign a value of 0CCCCCCCCh to the memory area of the 48h that was just left out.00401039 Lea edi,[ebp-48h]0040103C mov ecx,12h00401041 mov eax,0cccccccch00401046 Rep stos dword ptr [edi].The next three stack instructions, respectively, Ebx,esi,edi into the stack, which is also part of the "protection scene", these are part of the

Assembly Language Rep Movsd The use of detailed _c languages

MOV Esi,offset @s1MOV Edi,offset @s2MOV ecx,10CldRep Movsd1.Rep Movsd every ecx! =0 executes Movsd, then ecx=ecx-1 movsd move Ds:[si] to Es:[di], in 32-bit assembler can replace the Si,edi with ESI instead of Di 2. at the same time because in general exe DS = ES program starting position so another ESI = offset @s1 can find the variable s1, edi= offset @s2 can f

"An operating system implementation"--pmtest1.asm detailed

locate the memory segment Descriptor mov es, ax xor edi, edi mov edi, (up to ten +) //screen 10th, No. 0 column br> mov ah, 0ch //0000: Black bottom 1100: Red word mov al, ' G ' mov [es:edi],ax jmp $nbs P LenOfCode32 equ $-label_code32 =================================== The approximate meaning of this piece of code is:First in the 16-bit code segment

Shellcode analysis of a lattice disk

edi.data:0040605f 8B mov ecx, [eax].data:00406061 8B mov EDX, [eax+4];. data:00406061;; Save String "Createfi". data:00406064 C7 FC xx 00+ mov [ebp+processor_architecture], 0.data:0040606b 4D F8 mov [Ebp+szcrea], ecx.data:0040606e, MOV [Ebp+sztefi], edx.data:00406071 64 A1 xx eax, large Fs:30h; Get _peb.data:00406077 8B 0C mov eax, [eax+0ch]; Get ldr_peb_ldr_data.data:0040607a 8B 1C mov esi, [eax+1ch]; Get inloadordermodulelist (First-NtDll loadinfol

AT/T assembly Language Program example

. section. DataOutput: . ASCII "The processor Vendor ID is ' xxxxxxxxxxxx ' \ n". Section. Text.globl _start_start: MOVL $%eax cpuid # Create a pointer to handle an output variable declared in memory using this pointer # The memory location of the output tag is loaded into the EDI register # contains three registers of the vendor ID string fragment The content of the device is placed in the correct position o

About the invocation of a compiled language function (iii)

Lea edx,[ebp-14h]0040142b Push edx0040142c push 15h0040142e push 14h00401430 push 13h00401432 call @ILT +15 (Fnnakedcall) (00401014) 00401437 add esp,10h0040143a mov dword ptr [ebp-18h],eax133:You can see that the calling convention conforms to the __CDECL convention, so keep a look:68:69: __declspec (naked) int __cdecl fnnakedcall (int arg1, short arg2, char arg3, void *arg4): {004012d0 push EBP71://1. The value of all

When should you use the Web service "turn, recommend"

the key to successful business-to-business integration. With Web service, your company can expose critical business applications to designated suppliers and customers. For example, if you expose your electronic billing system and electronic invoice system, your customer can send you a purchase order electronically, and your supplier can send you an electronic invoice to purchase the raw materials. Of course, this is not a new concept: Electronic document interchange (

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