latitude 5420

/** * Calculates whether the point is within the radius of a fixed point * @ October 20, 2016 * @param a longitude 1 known * @param b latitude 1 known * @param x longitude 2 * @param y Latitude 2 * @param radius distance of R radius (m) comparison * @return Object[0] is in the known range*/ Public StaticObject[] Getmanypoint (DoubleADoubleBDoubleXDoubleYDoubleR) {object[] obj=Newobject[2]; DoublePK = th

1, theoretical support: if from the point of need to judge a ray and the number of focus of the polygon is odd, then the point in this polygon, otherwise the point outside this polygon. (Rays cannot intersect with polygon vertices) 2, Programming Ideas: The idea of the program is to make a horizontal ray (parallel to the x-axis, to the x-axis) from point A to the left to determine whether there is a focus on each side. DLon1, DLon2, DLAT1, dLat2 represent the longitude and

A recent project used latitude and longitude, according to the latitude and longitude of the map to show the corresponding position Background implementation code:HTML code: The code is as follows Copy Code Address to query: Query results (latitude and longitude): CSS code:JS Code: ============== Split Line ==============Fr

The formula is as follows, Unit meter: 1th Latitude: lng1 lat1 2nd latitude and Longitude: lng2 lat2round (6378.138*2*asin (Pow ((sqrt () LAT1*PI (180)/2), 2) + Cos (LAT1*PI ()/180) *cos (Lat2*pi ()/180) *pow (Sin ((Lng1*pi ()/180-lng2*pi ()/180)/2), 2))) *1000) Example: SELECT store_id,lng , Lat,round (6378.138*2*asin (SQRT (POW (22.299439*pi ()/180-lat*pi (/180)/2), 2) +cos (22.299439*pi ()/180) *cos ( La

How can I obtain the longitude and latitude of my current location? After knowing the longitude and latitude of the two locations, how can we calculate the distance between the two locations? Recently I am working on a public account. I need to obtain the user's latitude and longitude, and then calculate the distance between the user's

In the past, I was naive to think that it was nothing more than calculating the distance one by one, and then comparing them out. When there were a lot of users accessing the database and there was a lot of latitude and longitude information in the database, the rapid increase in computing workload can make the server completely dumb, or the experience of the old generation is richer than ours, which gives me a lot of inspiration. SQL statement query

HTML5 provides access to the geographical location of the API, it is convenient to determine the latitude and longitude of customers, we have access to latitude and longitude, you can provide the API through the Baidu map to determine the location of the user. At present, the computer is sometimes not available, the phone is still very good, in addition, to obtain the location is not very accurate, but u

PHP Code: Reprint http://www.cnblogs.com/caichenghui/p/5977431.html1 /**2 * Find the distance between two known longitude and latitude, in meters3 * 4 * @param lng1 $, lng2 longitude5 * @param lat1 $, lat2 latitude6 * @return float distance, Unit meter7 * @author www.Alixixi.com8 */9 functionGetdistance ($LNG 1,$lat 1,$LNG 2,$lat 2) {Ten //turn angle into Fox degree One $radLat 1=Deg2rad($lat 1);//the Deg2rad () function converts an angle to

Latitude algorithm $pi80 = m_pi/180; $lat 1=34.7465763; $lng 1=113.65778739999996; $lat 2=34.684795; $LNG 2=112.43594499999995; $lat 1 *= $pi; $LNG 1 *= $pi; $lat 2 *= $pi; $LNG 2 *= $pi; $r = 6372.797; Mean radius of Earth in miles $dlat = $lat 2-$lat 1; $DLNG = $lng 2-$LNG 1; $a = sin ($dlat/2) *sin ($dlat/2) +cos ($lat 1) *cos ($lat 2) *sin ($DLNG/2) *sin ($DLNG/2); $c = 2 * atan2 (sqrt ($a), sqrt (1-$a)); $km =round ($r * $c, 2);//return

First, ordinary IP is unable to obtain detailed latitude and longitude, only through network services to obtain The most useful in China is the JavaScript API provided by www.ip-look-up.com, as long as the following statements are written in the Web page He's going to return a JSON data in memory, just a little bit. iplocation = {' Latitude ': 39.9289, ' longitude ': 116.388, ' address ': {' city ': ' Be

Label:The world's 78,707 major cities information MySQL database, including latitude and longitude coordinate values, has been exported to the SQL file, because it is relatively large, there is 10M, so this is exported separately, for the upgrade failed to manually import students,This data is mainly used for weather forecast plug-in, the weather report plug-in, need to first from the library, query the city's ID, in the ID passed to the interface, re

By latitude, the database is compared stringbuffer SB = new StringBuffer () sb.append ("Select TimeKey,") Sb.append ("ROUND (6378.138*2*asin ( SQRT (POW (Sin (*pi ()/180-lat*pi ()/180)/2), 2), Sb.append (+cos (? *pi ()/180) *cos (Lat*pi ()/180) *pow (Sin ((? *pi ()/) ); Sb.append ("180-lng*pi ()/180)/2), 2)) *1000) as JL") Sb.append ("From T_news have JL Mysql takes a distance comparison between the specified lati