leetcode java

character is positive or negative, not the words or only the sign to run abnormal, and then began to traverse Ah, transformation ah. The focus is on the transformation. We can use switch for common conversions. But the source is not yo. For 128 to 127 is the cache good number, in addition to do a stirng to int conversion, in this int conversion to the char directly into int and then to the operation of Unicode, this is dug too deep, we do not need to delve into, Do some swtich conversion.The co

Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode035. Search for a Range (Medium)links：Title: https://leetcode.com/problems/search-for-a-range/Code (GitHub): Https://github.com/illuz/leetcodeTest Instructions：Finds a range of numbers in an ordered array. (because the number is duplicated)Analysis：Or two-point searc

Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode009.palindrome_number (Easy)links：Title: https://oj.leetcode.com/problems/palindrome-number/Code (GitHub): Https://github.com/illuz/leetcodeTest Instructions：Determines whether a number is a palindrome number.Analysis：Just write as you want. You can first co

Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode025. Reverse Nodes in K-group (hard)links：Title: https://oj.leetcode.com/problems/reverse-nodes-in-k-group/Code (GitHub): Https://github.com/illuz/leetcodeTest Instructions：A list is divided into a group of each k, which is flipped within each group.You can use only

Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode026. Remove duplicates from Sorted Array (easy)links：Title: https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array/Code (GitHub): Https://github.com/illuz/leetcodeTest Instructions：To an ordered sequence, delete the repeating element.Analysis：If you can

Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode016.3sum_closest (Medium)links：Title: https://oj.leetcode.com/problems/3sum-closest/Code (GitHub): Https://github.com/illuz/leetcodeTest Instructions：Finds three numbers in a given sequence, making and closest to target.Analysis：With 015. 3Sum (Medium) is similar, ev

Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode006.zigzag_conversion (Easy)links：Title: https://oj.leetcode.com/problems/zigzag-conversion/Code (GitHub): Https://github.com/illuz/leetcodeTest Instructions：Arranges a string in a line that is written in horizontal order.Analysis：Direct simulation on the line.Code:

Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode002.add_two_numbers (Medium)links：Title: https://oj.leetcode.com/problems/add-two-numbers/Code (GitHub): Https://github.com/illuz/leetcodeTest Instructions：A new list that is generated by adding two lists.Analysis：Direct simulation is possible.Code：C++:Class Solution

Follow to "Search in rotated Sorted Array":What if duplicates is allowed?Would this affect the run-time complexity? How and why?Write a function to determine if a given the target was in the array.Problem Solving Ideas:Refer to Java for Leetcode 033 Search in rotated Sorted Array to modify the following code, Java implementation is as follows: public boolean s

Given an integer n, generate a square matrix filled with elements from 1 to n2 in Spiral order.For example,Given N = 3 ,You should return the following matrix:[[1, 2, 3],[8, 9, 4],[7, 6, 5]]Problem Solving Ideas:Refer to Java for Leetcode 054 Spiral Matrix, modify the following code, Java implementation is as follows:static public int[][] Generatematrix (int n) {

Description: Choose Java, heavy in the experience, performance is not optimal. Welcome reprint: http://www.ming-yue.cn/leetcode-java-solutions/.First give a leetcode already have the answer, why come up directly to answer, because this many answers written are very concise, not too easy to understand, or suggest to do

Follow up to Problem "populating Next right pointersin each Node".What if the given tree could is any binary tree? Would your previous solution still work?Note: Constant extra space. For example,Given The following binary tree, 1 / 2 3 /\ 4 5 7After calling your function, the tree is should look like: 1, NULL / 2, 3, null /\ 4-> 5, 7, NULLProblem solving idea One:The difficulty of the subject is that it needs t

Given an array where elements is sorted in ascending order, convert it to a height balanced BST.Problem Solving Ideas:First of all to understand, what is called height balanced BST Java for Leetcode balanced Binary Tree, then it is very easy, Java implementation is as follows:Public TreeNode Sortedarraytobst (int[] nums) {return Sortedarraytobst (nums, 0, nums.le

Topic:Given a binary tree, return the inorder traversal of its nodes ' values.For example:Given binary Tree {1,#,2,3} , 1 2 / 3Return [1,3,2] .Train of thought: In the topic, the rule uses the loop instead of the recursive solution, uses the auxiliary stack to store the traversed node, if not empty then the stack, otherwise the stack assigns the value, and points to its right node.Code: Public classSolution { PublicListinordertraversal (TreeNode root) {ListNewArraylist(); if(Root

"Leetcode" single Number Problem solving report (Java Python) [Leetcode] Https://leetcode.com/problems/single-number/Total accepted:183838 Total submissions:348610 difficulty:easy Question Given an array of integers, every element appears twice for one. Find is single one.Note:Your algorithm should have a linear runtime. Could you implement it without using ex

Title: https://leetcode.com/problems/3sum-closest/"Label" Array; Pointers"Personal Analysis"This question and its sister problem 3Sum very similar, will not say more, specific analysis can refer to [leetcode][015] 3Sum1 Public classSolution {2 Public intThreesumclosest (int[] Nums,inttarget) {3 intresult =Target;4 intLen =nums.length;5 if(Len ) {6 return0;7 }8 Arrays.sort (nums);9 for(inti = 0

GivenNnon-negative integersa1 ,a2 , ...,an , where each represents a point at coordinate (I,ai ).NVertical lines is drawn such that the both endpoints of lineIis at (I,ai ) and (I, 0). Find lines, which together with X-axis forms a container, such that the container contains the most water.Note:you may not slant the container.This problem is very violent, equivalent to find two "planks", of which the short height of that * two between the distance. So our first thought was the Brute force O (n^2

,num2, initially set to the maximum value. Traversing the array, if there is smaller than the NUM1, the num1 into that element, if there is larger than the NUM1 and smaller than the num2, the num2 replaced, these two steps are actually in the simulation of the No. 300 element of the replacement. Finally, when there are larger numbers than NUM1 and num2, then you can return true directly, which is equivalent to simulating list.size () = = 3.JavaclassSolution { Public BooleanIncreasingtriplet (int

=Rearnode.next; Rearnode=Newhead; } } Public Static voidMain (string[] args) {//TODO auto-generated Method StubListNode First1 =NewListNode (0); ListNode rear1=First1; for(inti=1;i) {ListNode Q=NewListNode (i); Rear1.next=Q; Rear1=Q; } ListNode Q=First1; while(q!=NULL) {System.out.print (Q.val+ ","); Q=Q.next; } System.out.println (); Reorderlist RL=Newreorderlist (); Rl.reorderlist (FIRST1); ListNode P=First1; while(p!=NULL) {System.out.print (P.val+

the 6th student of A is shorter than the 7th classmate of B, that if the two classes in the overall order, that Class A 6 students must be standing in the Class B 7th, up to a class 6th standing in the Class B 7th, up to the whole row of 12th, how can not turn his platoon first k=13. So you can put the Class A top 6 lost, in the remaining two queues inside to find. But it is no longer to find the first K, but to find the first k-x. Because X did the cardinality was lost. of course, the above ex