This Gamex Trojan sample was just obtained in May and is not destructive, but it is good for security analysts.
Today, I will share with you the complete analysis process of this sample.ToolsApkTool, dex2jar, and DJ Java DecompilerPython2.6 write a decryption scriptAnalysisThis sample is infected by bundling the software SD-Booster. When the infected SD-Booster is installed and running, the trojan will automaticallyInstall it in the Android system. In
, 2n vectors are divided into n vectors and N opposite vectors. n + 1 vectors are divided into n vectors and the opposite vectors of n vectors.
2. Mesh)
In each step of Pattern Search, a series of vertices called "grids" are searched. Find the points in these points that can improve the target function. GPS and Mads algorithms use the following method to generate a grid.
1. Multiply each vector VJ in the pattern by a scalar m to obtain the vector DJ
Analysis:
Test binary. The simple simulation will time out, and the optimized time is right, but the binary speed is faster. Pay attention to the following points:
(1): If a sequence D1... dn. If we calculate the sum of Di to Dj, we can calculate the sum of D1 to Dj, and the sum of D1 to Di, and the result is sum1-sum2;
(2): Then we will search for the m + sum [I] value.
As a support unit, Soundmanager and loader play a very important role in the game. Since these two things are relatively simple, they will be explained in this article.First say Soundmanager:Soundmanager and Gamemanager, just need one at the same time, so also set as singleton mode. So in the awake method and Gamemanager basically the same.It can be noted that in unity it is not entirely simple to select a sound clip and then play it, but to bind a sound to a "audiosource".Audiosource can be und
value, assuming that a document T on host a points to m documents on Host B, the M document on B contributes a total of 1 to the hub value of T, and each document contributes 1/m. I,o operation changed to the followingI Operation:O Operation:The adjusted algorithm solves the problem 2 effectively, which is called the IMP algorithm.On this basis, Monika R Henzinger and Krishna Bharat also introduced the traditional information retrieval content analysis technology to solve 4 and 5, in fact, also
| er | fr | fo | pf | gf | tf | va | ph | fj | fi | cv | fk | gm | cg | cd | co | cr | gg | gd | gl | ge | cu | gp | gu | gy | kz | ht | kr | nl | an | hm | hn | ki | dj | kg | gn | gw | ca | gh | ga | kh | cz | zw | cm | qa | ky | km | ci | kw | cc | hr | ke | ck | lv | ls | la | lb | lt | lr | ly | li | re | lu | rw | ro | mg | im | mv | mt | mw | my | ml | mk | mh | mq | yt | u | mr | us | um | as | vi | mn | MS | bd | pe | fm | mm | md | ma | mc
information requirement (that is, based on the class scale only) and the new requirement (that is, what is obtained after a division), i.e.(3)I think a lot of people see this place is not very good understanding, so my own study of the literature on this piece of the description, also contrasted with the above three formulas, the following say my own understanding.In general, for a tuple with multiple attributes, it is almost impossible to separate them with a single attribute, otherwise the de
the same connected block).Analysis: Offline, delete as insert, each use and check set maintenance connected block number.Code:1#include 2#include string.h>3#include 4 using namespacestd;5 #defineN 4000506 intn,fa[n],m,q[n],ans[n],cnt;7 inthead[n],to[n1],nxt[n1],vis[n],k;8InlinevoidAddintUintv)9 {Tento[++cnt]=v;nxt[cnt]=head[u];head[u]=CNT; One } A intFindintx) - { - intp=Fa[x]; the while(P!=fa[p]) p=Fa[p]; - while(x!=2) { - inttmp=Fa[x]; -fa[x]=p; +x=tmp; - } + r
(there are 5 numbers added at this time), several numbers are added with keyboard control.The key is to calculate the value of each item, the rest is good to deal with (but born with the defect of hand, grammar, wrong type, value is not valid, the bug has a lot of wood there, can code just a few lines have wood there ah! )Not be bird myself.Serving:1 #!/usr/bin/env python2 #-*-coding:cp936-*-3 #Enter a number to overlay4a = Int (Raw_input ("Enter a number to overlay"))5 #Input Digital Control o
information is encoded in binary. Info (d) is the average amount of information required to identify the class labels of tuples in D. Notice that at this point all of our information is just a percentage of the tuple for each class.Now suppose we want to classify a tuple in D according to a property A, where attribute A has a V different value {a1,a2,... av} According to the observation of the training data. You can use attribute A to divide d into a V partition or subset {D1,D2,..., Dv}, where
One-dimensional: Make \ (v_i\) for the difference fraction Group, then \ ([0, k]\) prefix and is \ (\sum{v_i (k+1-i)} = (k+1) \cdot \sum{v_i} + \sum{v_i \cdot (-i)} \), the tree-like array is maintained for \ (v_i\) and \ (v_i \cdot i\) . template Two-dimensional: similar to one-dimensional derivation, maintenance \ (V (i,j) \) , \ (V (i,j) \cdot i\) , \ (V (i,j) \cdot j\) and \ (V (i,j) \cdot ij\) . struct Fenwick {struct Node {int V, VI, VJ, Vij; void operator + = (const Node AM
I. Theoretical basisThe Dijkstra algorithm (hereinafter referred to as the DJ algorithm) is the theoretical basis for a simple theorem:The next shortest path is either an arc (V0, Vx), or some vertex in the middle through s, and then the path to Vx. (S is a collection of vertices known as the shortest path)(For an accurate description of the theorem, here is a direct excerpt.) As far as it is right, well, it is said that the proof of the law can be pr
free, just like other radio channels. After registering and logging into your account, you can also store your favorite music in your account. (Ladder required)
Freesound
Freesound is a collaborative database of Creative Commons licensed music that contains many sound effects, such as ambient noise, Cheng effect, or music made from instruments.
Browse, download and share music from Freesound; After registering for a free account, you can also upload your own audio to their databa
(d) is the average amount of information required to identify the class label of the tuple in D. Note that all of our information at this time is just the percentage of the tuple of each class.
Now let's say we're going to divide the tuple in D by a property A, where property A has a V different value {a1,a2,... av} based on the observation of the training data. You can use property A to divide D into v partitions or subsets {d1,d2,..., Dv}, where the DJ
with the lowest D value from the candidate list. (In this case, the data structure of V uses the priority queue to achieve the minimum value of the dequeue, preferably using Fibonacci pairs, in the previous article has been introduced, performance has a significant hint). For each edge that starts with the node, excluding the node to remove V, (i, J) belongs to A, if DJ > di + AIJ (breach of relaxation conditions),
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