random ssn generator

; - returnRec; - } + - structMaxtrix { +ll a[2][2 ] ; A Maxtrix () { atMemset (A,0,sizeof(a)); - } - voidprint () { - for(inti =0; I 2; i + + ) { - for(intj =0; J 2; J + + ) { -cout " " ; in } -cout Endl; to } + } - }; the * Maxtrix Multi (Maxtrix M1, Maxtrix m2) { $ Maxtrix Rec;Panax Notoginseng for(inti =0; I 2; i + + ) { - for(intj =0; J 2; J + + ) { the for(intK =0; K 2; K + + ) { +rec.a[I [j] + =multi (m1

Today with the doctrine in preparation for a party, there is a random number lottery to make the link, want me to make a random number generator, preferably the kind of start after the number of jumps, the key after the pause.This thing has no technical content, put in C + + is also a random thing, I can not give someo

This article describes how to implement a random password dictionary generator in python. if you need a dictionary generator, you can refer to all the passwords you want to use. the algorithm is either nested too deep, or memory consumption (will overflow ). later, I selected an algorithm with a low probability of simple repetition. the code is as follows:

}View Code 3671: [Noi2014] random number generator time limit:50 Sec Memory limit:256 MB submit:774 solved:374 [Submit] [Status] [Discuss] DescriptionInputThe 1th line contains 5 integers, followed by x_0,a,b,c,d, describing the random seed required by the random number generation algorithm used by sm

Code: /* This is a free program, you can modify or redistribute it under the terms of GNU * Description: Specifies a random number generator, such as 1000, random numbers between 1 and 1000 are required, and the probability of any number between 1 and 1000 is equal, all of which are 1/1000 * language: C ++ * Development Environment: vc6.0 * Author: wangzhicheng

identifier token that is saved to the session and is written back to the form as a hidden element, and the token attribute in the session is deleted after the form is processedAfter the user submits the form, the server authenticates:1, whether there is a token element, there is the next step, do not process the form2, if there is a token attribute in the session, proceed to the next step, do not process the form3, the token attribute value in the session is the same as the user commits, the ne

1 #/bin/python32 ImportSYS3 Import Time4 ImportRandom5STRs = [i forIinchRange (32,128)] #产生密码的ASCII码的序列6Length =10 #生成密码长度7#下面这个函数用来生成Length长度的密码8 defrandomstr (strs,length):9Liststr = []Ten forIinchRange (length): One liststr.append (Random.choice (STRs)) A returnListstr - defstrings (): -String ="" thechar =randomstr (strs,length) - forIinchChar: -string+=chr (i) - returnstring +#上面这个函数将调用randomstr函数, returns a string password - +Start =Time.time ACount =1

Password Management Tools After searching, I found that all the password management software I could find could not meet my own requirements. Therefore, I finally made up my mind to write my own password management tools. One of the reasons why I chose to write a password management tool by myself is to quickly generate random passwords. Of course, the highest priority is to create incredible and complex enough passwords, because I want to manage them

=shared--enable-disk_cache=shared--enable-mem_cache=shared-- enable-proxy=shared--enable-proxy_connect=shared--enable-proxy_ftp=shared--enable-proxy_http=shared-- enable-file_cache=shared--enable-charset_lite=shared--enable-case_filter=shared--enable-case_filter_in=shared- -enable-ssl=shared--WITH-APR=/USR/LOCAL/APR--with-apr-util=/usr/local/apr-utilMakeMake installNot that the first method must have a problem, I have also encountered the first installation is available, if you are the first way

) - { - if(n1) in { -ans_matrix[0][0]=KSC (ans_matrix[0][0],matrix[0][0]); toans_matrix[1][0]= (KSC (ans_matrix[1][0],matrix[0][0]) +matrix[1][0])%m; + } -n>>=1; thell TMP1=KSC (matrix[0][0],matrix[0][0]); *ll tmp2= (KSC (matrix[1][0],matrix[0][0]) +matrix[1][0])%m; $matrix[0][0]=tmp1,matrix[1][0]=TMP2;Panax Notoginseng } - } the + voidInit () A { thescanf"%lld%lld%lld%lld%lld%lld",m,a,c,x0,n,g); +matrix[0][0]=a%m,matrix[0][1]=0, matrix[1][0]=c%m,matrix[1][1]=1;

\[\begin{eqnarray*}x_i=x_{i-1}+x_{i-2}\\x_i^2=x_{i-2}^2+x_{i-1}^2+2x_{i-2}x_{i-1}\\x_{i-1}x_i= (X_{i-3}+x_{i-2}) (x_{i-2}+x_{i-1}) \ \=2x_{i-3}x_{i-2}+x_{i-2}x_{i-1}+x_{i-3}^2+x_{i-2}^2\end{eqnarray*}\]Therefore, the transfer matrix can be constructed $a$ recursive.If you wish to set $n\geq m$, you can preprocess $a^0,a^1,..., a^n$ and $a^n,a^{2n},..., a^{nn}$.So the complexity of querying a number is $8^3$.Total time complexity is $o (n (8^3+\log N)) $.#include 　　BZOJ4471:

, LL AMP;GCD) {if(!B) {x=1,y=0, Gcd=a;return; } EXGCD (B,a%b,y,x, GCD);y=y-a/b*x;} ll Get_inv (LLx, ll MOD) {ll x,y,gcd; EXGCD (x, MOD,X,Y,GCD);return(X%mod+MOD)%mod;} void Bsgs (ll a,ll b,ll C) {init (); llm=(int) Ceil (sqrt(C)); ll k=1; for(intI=0;im; i++) {intflag=1; for(intJ=head[k%mod];j!=-1; J=edge[j].Next) {if(edge[j].val==k) {flag=0; Break;} }if(flag) Edgeadd (k%mod, i,k); K=k*a%c; } ll Invk=get_inv (K,C); ll invd=1; for(intI=0; im; i++) {ll tmpb=b*INVD%c; for(intJ=head[tmpb

Question :..... Take a long look. First, since the Lexicographic Order of the sorted sequence is the smallest, You must select as few numbers as possible. Then T is 1 ~ The M * n sequence does not exist. (At the beginning, I missed this condition) Okay, this question is greedy.Select the minimum point that is not marked each time, and mark both the lower left and the upper right corner (remember to mark the duplicate break, otherwise it will be down) Note that if two int values are opened fo

Huawei WS318 predictable random number generator Vulnerability Release date:Updated on: Affected Systems:Huawei WS318Huawei WS318Description:Bugtraq id: 71787 Huawei WS318 is a wireless router product. A predictable random number generator vulnerability exists in the implementation of Huawei WS318. After successful

Matrix Fast power ... + fast multiply on OK--------------------------------------------------------------------------------------#include using namespace std;typedef long Long ll;ll MOD, A, C, X, N, G;ll MUL (ll A, ll b) {ll ans = 0;for (; b; b >>= 1) {if (b 1) ans + = A;if (ans >= mod) ans-= mod;a if (a >= mod) A-= mod;}return ans;}struct Matrix {ll x[2][2];Matrix () {memset (x, 0, sizeof x);}inline void Unit () {x[0][0] = x[1][1] = 1;x[0][1] = x[1][0] = 0;}Matrix operator * (const matrix o) {

Implement the random generator of famous quotes Based on JQuery and AJAX, jqueryajax This is a small application I made when I first got started with AJAX. The main functions are as follows: 1. click the button to randomly generate a famous saying and its author name. If there is no author name, "Unknown" is displayed ".2. click the button to share the famous saying on Twitter or Weibo. HTML: JQuery: $(doc

Installation:# yum-y Install expectParameters:-L: Password length, default is 9;-D: The minimum number of digits in the password, the default is 2;-C: The minimum number of lowercase letters in the password, the default is 2;-C: The minimum number of uppercase letters in the password, the default is 2;-S: The minimum number of special characters in the password, the default is 1;-V: Back with user, modify user's password to a random password,-2: Guara

1. Seeds and distribution Five types of distributions are introduced here, including the following: (a), and (). Parameters required for distribution and use are provided. 2. Test the random number generator. This section contains only one simple example, which is not described in detail. The following is the procedure for getting a random number from the example

A whole bunch of borders was not known at first, and after a few random sentences, WAHelpless to download the data, and then crazy to judge all kinds of strange boundariesTo gouge out the boundary problemFirst we consider the situation of a=1X1+k*b=t (mod p)EX_GCD can be solvedConsider the situation of a>1Make s=x+b/(A-1)The original is becoming a geometric series.S1*a^k= (t+b/(A-1)) (mod p)BSGS solution after moving the itemAll other boundaries can b

Php random password generator Function auth_pwgen (){ $ Pw = ''; $ C = 'bcdfghjklmnprstvwz'; // consonants cannot hard to speak ones $ V = 'aeiou'; // vowels $ A = $ c. $ v; // both // Use two syllables... For ($ I = 0; $ I $ Pw. = $ c [rand (0, strlen ($ c)-1)]; $ Pw. = $ v [rand (0, strlen ($ v)-1)]; $ Pw. = $ a [rand