This article mainly introduces jQuery's method of reading XML file content, and analyzes jQuery's skill in operating XML files, for more information about how jQuery reads the content of an XML file, see the following example. Sha
Copy Code code as follows:
strSourceFile = Server.MapPath (dataxml "/advertisement/" id "/adv.xml")
Set objxml =server.createobject ("Microsoft.XMLDOM") ' creates an XML pair like
Objxml.load (strsourcefile) ' reads the XML file into memory
Set Xml=objxml.documentelement.selectsinglenode ("advertisement") ' Sel
To read A. xml file in. Net:1. Use the xmltextreader class, such:
Xmltextreader reader = new xmltextreader (server. mappath (xmlpath ));While (reader. Read ()){If (reader. nodetype = xmlnodetype. Text){Response. Write (reader. Name + "DD" + reader. value );}}
2. Use the xpathnavigator class:
Xpathdocument xpdoc =
Web effects p/jsp.html target=_blank >jsp Tutorial Add, delete, read the content code of the specified tag in the XML file
Package XML;
Import Java.io.file;Import java.util.list;
Import org.dom4j.document;Import org.dom4j.documentexception;Import org.dom4j.element;Import Org.dom4j.qname;Import Org.dom4j.io.saxr
This article illustrates the way JS reads XML file data and displays the data in table Form. Share to everyone for your reference, specific as follows:
First look at the XML file:
aspx page code:
The above JS operation mainly avoids using childnodes (because Firefox sometimes appears childnodes[0]
Xml
The following is an example of reading the contents of an XML file and displaying it in a TextBox:
Using System;Using System.Data;Using System.Configuration;Using System.Web;Using System.Web.Security;Using System.Web.UI;Using System.Web.UI.WebControls;Using System.Web.UI.WebControls.WebParts;Using System.Web.UI.Htm
/******************************************
*jxtree object, reading external XML file data, spanning tree
* @author Brull
* @email brull@163.com
* @date 2007-03-27
*******************************************/
/*
* @param the address of the XmlURL XML file
*/
var jxtree = function (XmlURL)
{
var result = new Array ();
1. Bind dropdownlist:
Ddl_language.datasource = createdatasource ();Ddl_language.datatextfield = "languagetextfield ";Ddl_language.datavaluefield = "languagevaluefield ";Ddl_language.databind ();
2. The createdatasource () method used above:Private icollection createdatasource () {// create a data table to store the data for the ddl_langauge control datatable dt = new datatable (); // define the columns of the table DT. columns. add ("languagetextfield", typeof (string); DT. columns. add ("langu
Read XML file content
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Original: Share very useful Java program (key Code) (vi)---parse/read XML file (important)XML file Code for Java parsing:Package net.viralpatel.java.xmlparser; Import Java.io.File; I
Using system; using system. collections. generic; using system. componentmodel; using system. data; using system. drawing; using system. LINQ; using system. text; using system. windows. forms; using system. io; using system. XML; using system. XML. LINQ; namespace queryxmlbylinq {public partial class frm_main: FORM {public frm_main () {initializecomponent ();} static string strpath = "employee.
It is known that there is an XML file (bookstore. XML) as follows: 1. Insert a Xmldocument xmldoc = new xmldocument ();
Xmldoc. load ("Bookstore. XML ");/* you can modify the path as needed. If it is a winform application, xmldoc. load (application. startuppath + @ "\ XML \
directory for the log fileString fname = Directory.GetCurrentDirectory () + "\\LogFile.txt";/**/Defining File Information objectsFileInfo finfo = new FileInfo (fname);if (!finfo. Exists){FileStream FS;FS = File.create (fname);Fs. Close ();Finfo = new FileInfo (fname);}/**/Determine if the file exists and is greater than 2Kif (finfo. Length > 1024 * 1024 * 10){/**/File
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