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Effective Java Third edition--1. Consider using static factory methods instead of construction methods

Tips"Effective Java, third Edition" an English version has been published, the second edition of this book presumably many people have read, known as one of the four major Java books, but the second edition of 2009 published, to now nearly 8 years, but with

Sword Point of Offer (Java Edition): Minimum number of K

the topic is to ask for the smallest number of k numbers from a large amount of data, because the size of the memory is limited, it may not be able to load these massive data into memory all at once. At this time, we can assist storage space (such as disk) to read a number each time, according to Getleastnumbers way to determine whether it is necessary to put the container leastnumbers. This approach only requires memory to accommodate leastnumbers. So it fits the case that n is big and K is sm

Object-oriented Software engineering: Working with UML, schemas, and Java (3rd edition) pdf

48916.3.4 process contains how many steps 49016.3.5 need to control and monitor 4911 6.3.6 when to redefine a project objective 49216.4 law Field 49216.4.1 Royce Methodology 49316.4.2 Extreme Programming (XP) 49616.4.3 Rugby methodology 50016.5 Case study 50516.5.1 XP project: ATRAC T 50616.5.2 Local main customer: FRIEND 50816.5.3 Distributed project: JAMES 51316.5.4 Case Study summary 51816.6 recommended readings 52116.7 Exercise 521 Part 4 Appendix Appendix A design Pattern 525a.1 Abstrac T

Java Core Technology Volume 1 basic Knowledge (original book 9th edition) (complete Chinese version). Pdf__java

Download address: Network disk download Introduction to the content One of the most influential and valuable works in the Java field, with more than 20 years of experience in teaching and research of senior Java technology experts to write (won the Jolt Award), and "Java Programming ideas," the same as the more than 10-year global best-selling not decline, popul

The sword refers to the offer surface question (Java Edition): And for S two numbers vs and a continuous positive sequence for s

15, because of 1+2+3+4+5=4+5+6=7+8=15, so the result prints out 3 sequential sequence 1--5,4--6,7--8.With previous experience, we also consider using two tree small and big to represent the minimum and maximum values of the sequence respectively. First initialize the small to 1,big to 2. If the sequence from small to big and greater than s, we can remove the smaller value from the sequence, that is, increase the value of the small. If the sequence from small to big and less than S, we can enlar

Java Thread Third edition third chapter data synchronization reading notes

following:Class X { reentrantlock lock = new Reentrantlock (); // ... public void M () { assert lock.getholdcount () = = 0; Lock.lock (); try { //... method body } finally { lock.unlock ();}} }return:The number of times the current thread holds this lock, assuming that the lock has not been persisted by the current thread. Then returns 010. DeadlockA deadlock occurs when two or more thread waits for two or more two locks to be released. and the program'

Sword Point of Offer (Java Edition): The penultimate K-node in a linked list

, their hearts a happy, soon wrote the code. But a few days later, is not an offer, but refused to believe, so think not the solution. In fact, the reason is very simple, is that their code is not robust. The interviewer can find 3 ways to break the code.1. Enter the head pointer null. The program crashes because the code tries to access the memory that the null pointer points to.2. The total number of nodes in the list with head node is less than K. Because the k-1 step moves forward in the For

The sword refers to the offer surface question one (Java Edition): the integer number of values of the square

as 16 times put on the basis of the square once on it. and 16 times the square is 8 square. So and so on, we ask for 32 times only need 5 times of the powers: first squared, on the basis of the square of 4, on the basis of 4 to seek 8 square, on the basis of 8 to seek 16, and finally on the basis of 16 on the side of 32.That means we can use the following to find the n-th side of a:This formula is the formula that we discussed when we first used O (LOGN) time to find the Fibonacci sequence, and

JAVA programming ideology (Fourth Edition) Study Notes ---- 11.10 Map, programming ideology ---- 11.10

JAVA programming ideology (Fourth Edition) Study Notes ---- 11.10 Map, programming ideology ---- 11.10 Previously, we learned the List interface at the Collection level. The List hierarchy is relatively simple. Except for the CoppyOnWriteArrayList class related to multi-thread security, this class is used to learn more when it involves multi-thread-related knowledge, in addition to outdated Vector In norma

Adapter Mode (Java Edition)

an implementation class for the target interface and to invoke a method of the appropriate interface in the implementation class. So as to achieve the purpose of adaptation.Example:Target rolepublic interface target{public void request ();}SOURCE rolepublic class adaptee{The original businesspublic void dosomething () {System.out.println ("a b C");}}Adapter rolepublic class Adapter extends Adaptee implements target{public void request () {Super.dosomething ();}}Object Adapter Mode:By wrapping a

Introduction to Java from getting started to giving up: object-oriented concepts (Entry edition ),

Introduction to Java from getting started to giving up: object-oriented concepts (Entry edition ), To know what object orientation is, you must first have an object · Okay, we are joking. We need to explain what object orientation is. Example: "Silly, what did you eat for

To all the brothers who just learn Java and often come to this edition

To all the brothers who just learn Java and often come to this edition On the jar, often (note, is often, and is very often!) Encountered some not difficult problems, even on the same day there are many similar problems, I think as a moderator, I can not just to answer the question for everyone (let alone there are many problems I do not understand), but need to talk about how to learn

The sword refers to the offer surface question (Java Edition): Do not add subtraction

to add a carry, the result is a binary 10, the third step to add the results of the first two steps, the result is 10110, the conversion to decimal is just 22, this shows that the three-step strategy for the binary is also applicable.Next we will try to replace the binary addition with the bitwise operation. The first step does not consider the rounding to add to each bit. The result of 0+0,1+1 is that the result of 0,1+0 is 1. The result of 0+1 is 1, and we notice that this is the same as the

The sword refers to the offer surface question (Java edition): Print binary tree from top down

10,5,7. Next we take the node with a value of 10 from the data container. Notice that the node value of 10 is 5, 7, the node is placed in the container first, and then the two nodes are removed first, this is what we usually say first in first out, so it is not difficult to see that this container should be a queue. Because nodes with a value of 5,7,9,11 have no child nodes, they can be printed in turn.By analyzing specific examples, we can find the

Webdriver--api--(Java edition) the second part

"); //Droplist.selectbyindex (3). GetText () method error, accounting for what reason, are quoted Droplist.getfirstselectedoption (). GetText () to assert//assert.assertequals ("Hawthorn", Droplist.selectbyindex (3). GetText ()); //selected by option text, Droplist.selectbyvisibletext ("Lychee"). GetText () error;//assert.assertequals ("Litchi", Droplist.selectbyvisibletext ("Litchi"). GetText ());ListNewstring[]{"Peach", "Hawthorn", "lychee", "Orange

Sword Point (Java Edition): Adjust the array order so that the odd digits precede the even number

number of questions in the group according to the size of the two parts, all negative numbers in the front of all non-negative, how to do?If we change the subject, we can divide the number of the array into two parts, and the number divisible by 3 is in front of the number that cannot be divisible by 3. What to do?This is where the interviewer is examining our understanding of extensibility. It is hoped that we can give a pattern in which the existin

Fool method to find all subsets of a set problem (Java edition)

is printed. Refer to the Print method.Summary: This approach is easier to understand. can also adapt to arbitrary length of the problem of the subset.According to this approach, another problem can be solved--01 knapsack problem (There are five items numbered a,b,c,d,e respectively. Their weights are 2,2,6,5,4, and their value is 6,3,5,4,6. Now give you a backpack with a weight of 10. How to make the items loaded in the backpack have the maximum value sum? Believe very easy to see, the above me

"Java from getting started to giving up" Javase: Network Programming (Starter Edition)

/M02/A5/CA/wKioL1nDWzizH3DqAAAdegLMUa8760.png "title=" 11. PNG "alt=" Wkiol1ndwzizh3dqaaadeglmua8760.png "/>Run the client again to see that the server-side content has changed650) this.width=650; "src=" Https://s3.51cto.com/wyfs02/M01/07/19/wKiom1nDW9zQWpbWAAAjBpnMi-k530.png "title=" 12. PNG "alt=" Wkiom1ndw9zqwpbwaaajbpnmi-k530.png "/>Then switch to the client's output window650) this.width=650; "src=" Https://s3.51cto.com/wyfs02/M00/07/19/wKiom1nDXAzAcF5hAABHB78MZ7I848.png "title=" 13. PNG "w

"Leetcode Brush problem Java Edition" Reverse Words in a String

Given an input string, reverse the string word by word.For example,Given s = " the sky is blue ",Return " blue is sky the ".Click to show Clarification.Clarification: what constitutes a word? A sequence of non-space characters constitutes a word. could the input string contain leading or trailing spaces? yes. However, your reversed string should not contain leading or trailing spaces. how about multiple spaces between? reduce them t

Selenium common face questions and Answers (Java edition)

example, a landing page, using the PO mode, will create a LoginPage class, the class will define the user name input box, password input box, login button webelenentFor the corresponding element to implement the corresponding method, the input box is used to input, you need to create a user name and enter the password method, so that the real page consistent, so the design concept is PO mode. The pagefactory belongs to the PO mode, which is used to initialize the page Class of each PO pattern i

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