x86 assembly instructions

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"Assembly language" learning note 8--Basic assembly instructions

1. Basic assembly Instructions1. Delivery Instructions: MOVFormat: MOV opd,opsAction: Transfer the value of OPS to OPDPrecautions:1.OPD cannot be CS2. Not allowed to transfer between two storage units3.MOV affects all flag bits4.OPD, the data type of OPS should be consistentWhen 5.OPD is CS, OPS cannot be an immediate number  2. The stack command: PUSHFormat: PUSH OPDOperation: 1. Sp←sp-1 2. OPD the high by

Lab 1 Viewing CPU and memory, programming with machine instructions and assembly instructions

Experimental tasks(1) Using debug, the following program segments are written to the memory, executed one at a time, observing the changes in the contents of the relevant registers in the CPU after each instruction execution.  Machine code Assembly Instructions            B8 4e mov ax,4e20h         Add ax,1416hBB XX mov bx,2000hD8 Add Ax,bxC3 mov Bx,axD8 Add Ax,bxB8 1a mov Ax,001ahBB-XX mov bx,0026hXX D8 Ad

Programming with machine instructions and assembly instructions (1)

Experimental tasks(1)1. Write instructions to memory using the a command in the form of assembly instructionsExecute the Write command with the T command2. Write the machine code with the e commandThe result of execution is the same as the a command(2)Write instructions to a memory unit from 2000:0Ax=1, using 8 times jmp to figure out 2 of the 8-time Square(3)The

Lab 1 Viewing CPU and memory, programming with machine instructions and assembly instructions

Experimental tasksFirst, using Debug, use the E command and the A command to write instructions to memory in two waysMachine code Assembly InstructionsB8 4e mov ax,4e20hAdd ax,1416hBB XX mov bx,2000hD8 Add Ax,bxC3 mov Bx,axD8 Add Ax,bxB8 1a mov Ax,001ahBB-XX mov bx,0026hXX D8 Add Al,blXX DC Add AH,BLXX C7 Add Bh,alB4 XX mov ah,0XX D8 Add Al,bl9c Add al,9ch (1) Use the A command to write

Experiment 2 programming with machine instructions and assembly instructions

A to enter the 7-line command and Run Command e to modify the value from ~ 2000: F value, view the modified part MoV ax, 2000; Save the number H to the Register ax MoV SS, ax; Save the number 2000h in the register ax to the stack segment register SS MoV sp, 10; Save the number 10 h to the stack address register sp The initial stack top is, and the initial stack bottom is. 2. debug each line of Assembly commands in one step. After each command is deb

Programming with machine instructions and assembly instructions (1)

Experimental resultsGo to DOS, run debugUse the R command to view and change the contents of the CPU register.Modify the contents of the register AX with the R commandModify the contents of CS and IP with the r commandUse the D command to view the contents of memory 1000:0See what's at 1000:9List the contents of the Debug preset addressView the contents of the 1000:0~1000:9 unitView content in the same physical address with three different segment addresses and offset addressesModify the content

Experiment 2 programming with machine instructions and assembly instructions

= 6462 H Push [4]; SP = 00feh. The modified memory unit address is 2200: 00fe. The content is 3534 H. Push [6]; SP = 00fch. The modified memory unit address is 2200: 00fc content is 3736 H. Rewrite with the E command, and write with the command: Result of one-step operation: Data in the stack address: (2) observe the experiment process shown in Figure 3.19 and analyze the cause ~ 2000: will the content in F change? Figure 3.19 example of an experiment using debug A: The use of

Programming with machine instructions and assembly instructions

4. 1. Experiment conclusion 2. . After two single-step operations in Experiment 2, we found that mov ax, 2000; MoV SS, ax; MoV sp, and 10 operations were run. The results returned when only the first three operations are written and run are the same. Shows the data in the memory area when no operation is performed. The data in the corresponding memory area after two single-step operations is the same as the original value. Ax, the IP value is the same as the value in memo

Experiment 1: View CPU and memory, and program with machine instructions and assembly instructions

the memory and locate the production date as 01/01/92. (2) run the e command to modify the date and run the D command to check whether the modification failed. 4. Fill in data to the unit in which the memory starts from b8100h. Change the entered data and address, and find that a pattern is controlled by two memory units. The former controls the style and the latter controls the color. Experiment summary and experience ?No result is returned when the CPU writes data to the memory address c0

C # Reflection Assembly specific Instructions

, For example, Abc.dll has two version number (version number 1 under folder 1, version number 2 under folder 2), the program starts with the version number 1 loaded, when the use of Assembly.LoadFrom ("2\\abc.dll") load version number 2 o'clock, cannot be loaded, but return version number 1. Assembly.loadfile will not do this kind of inspection, for example, the above example replaced with Assembly.loadfile, then the version number 2 can be loaded correctly.LoadFile: Loads the contents of the

C # Reflection Assembly specific Instructions

example, Abc.dll has two version number (version number 1 under folder 1, version number 2 under folder 2), the program starts with the version number 1 loaded, when the use of Assembly.LoadFrom ("2\\abc.dll") load version number 2 o'clock, cannot be loaded, but return version number 1. Assembly.loadfile will not do this kind of inspection, for example, the above example replaced with Assembly.loadfile, then the version number 2 can be loaded correctly.LoadFile: Loads the contents of the

How do I debug arm assembly instructions?

Learning In Arm assembly language , it is necessary to debug Arm assembly instructions. As a debugger that supports multiple languages,gdb is naturally a better choice. When the debugger works, it usually constructs the trap soft interrupt instruction by modifying the content of the code snippet , realizes the program's pause and the program execution state mo

Learn the assembly instructions that the Linux kernel often encounters (1)

. This amount of displacement is added to the IP register. The displacement amount is a signed number, negative numbers indicate a forward transition, and positive numbers indicate a backward transition. The transfer range is 32768 to +32767.Third, the indirect transfer ①jmp AX (intra-segment register indirect transfer); ②jmp [BX] (Intra-segment memory indirect transfer). Sends the contents of the specified register or storage unit in the instruction to the IP.Direct transfer of JMP far PTR desi

Common ARM Assembly Instructions

Common ARM Assembly Instructions [Date: 2012-07-14] Source: Linux Community xuyuanfan77 [Font: Big Small] In embedded development, assembler is often used in very critical places, such as the initialization of the system at startup, environmental protection when entering or leaving the interrupt, and the performance requirements of the recovery.The arm instruction set ca

Some summaries of ARM assembly instructions

ARM assembly instructions are many, but the real use is not a lot, but also need to seriously think about less. More useful is MOV B BL LDR STR or through the specific assembly code to learn it. @ Disable Watch dog timer mov r1, #0x53000000// immediate number addressing mode mov r2, #0x0 str R2, [R1]MOV There is nothing to say, as long as the master a few

C function calls generate assembly instructions and data in memory condition (2)

C function calls generate assembly instructions and data in memory condition (1)The specific assembly instructions for the function call and the various variables in the memory of the specific allocation, smattering. All kinds of information are very detailed, but do not practice, do not personally check the memory of

View the assembly instructions for the Java code another weapon, Jitwatch.

Http://www.tuicool.com/articles/IRrIRb3time 2015-05-13 08:00:00 Liuxinglanyue ' s Blog Original http://javagoo.tk/java/jitwatch_code.html ThemeJDKSee the assembly instructions for the Java code another weapon, Jitwatch.Error correction 2015Then the previous article looked at the Java code corresponding assembly instructions

Learn the assembly instructions that the Linux kernel often encounters (2)

addition, the of bit is set according to the symbol of the operand and its result, if the symbol of the two operand is the same, and the symbol of the result is opposite, the of 1, or 0.OFFSET: Numeric return operator. It is preceded by a variable name or label, and the returned value is the offset address of the segment where the variable name or label resides.OPD: Textbook Symbol--the purpose of the operand.OPR: Textbook symbol--source operand.Or: A logical operator (in the operand portion of

8086 Summary of assembly instructions

) The memory size occupied by the "target" and "Source" should be the same, When the two sides explicitly know the size of memory bytes, if not the same, it cannot be compiled, If only one party knows the size of the memory byte, data processing is calculated based on the size of the memory byte of the party, When neither side knows the size of the memory byte, The Byte/word/dword ptr display statement is applied. dword ptr is only used for some special commands. (5) There are two types of trans

Small Turtle 0 Basic assembly Language learning note Fifth [BX] and loop instructions

corresponding improvements to the code:1AssumeCS:codeseg2 codeseg Segment3 movAX,0FFFFH4 movDs,ax;(DS) =0FFFFH5 6 movax,0020h7 movEs,ax;(es) =0020h8 9 movBx0 ;(BX) = 0, at this time, Ds:bx point ffff:0,es:bx refers to 0020:0Ten movCx A One A S: - movDL,[BX];(DL) = ((DS) *16+ (BX)), the data in the FFFF:BX is passed to the DL - mov es:[BX],DL;((es) *16+ (bx)) = (DL), the data in the DL is passed into the 0020:BX the - IncBX -

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