Title Link: http://acm.hdu.edu.cn/showproblem.php?pid=4022
There are n points on a graph, followed by M operations, one row per operation or one column. Eliminate all of the points in this row or column. The number of points each time the output of the operation is eliminated.
Ideas:
Since the data range is large, the first thing to think about is to maintain the number of columns in each row after discretization, but found that such an offline approach can only maintain the current state, updated into a problem. Later in the thinking there is no way to maintain all the line coordinates within the limits of O (LGN) without exceeding the data range. Want to go, at first want to use Map<int, vector<int>>, but vector scan is O (n). Then consider a nonlinear structure, and finally think of the red and black trees. Or the--std::multiset<int> that holds the repeating element.
So this problem becomes a water problem.
1#include <algorithm>2#include <iostream>3#include <iomanip>4#include <cstring>5#include <climits>6#include <complex>7#include <fstream>8#include <cassert>9#include <cstdio>Ten#include <bitset> One#include <vector> A#include <deque> -#include <queue> -#include <stack> the#include <ctime> -#include <Set> -#include <map> -#include <cmath> + - using namespacestd; + A #defineFr First at #defineSC Second - #definePB (a) push_back (a) - #defineRint (a) scanf ("%d", &a) - #defineRll (a) scanf ("%i64d", &a) - #defineRs (a) scanf ("%s", a) - #defineFRead () freopen ("in", "R", stdin) in #defineFWrite () freopen ("Out", "w", stdout) - #defineRep (i, n) for (int i = 0; I < (n); i++) to #defineFor (I, A, n) for (int i = (a); I < (n); i++) + #defineCls (a) memset ((a), 0, sizeof (a)) - #defineFull (a) memset ((a), 0x7f7f, sizeof (a)) the * Const intMAXN =100010; $ intN, M;Panax Notoginseng intX[MAXN], Y[MAXN]; - intHX[MAXN], hxcnt; the intHY[MAXN], hycnt; + intSX[MAXN], SY[MAXN]; Amap<int, multiset<int> >xx; themap<int, multiset<int> >yy; +multiset<int>:: iterator it; - $InlineBOOLScan_d (int&num) { $ Char inch;BOOLisn=false; - inch=GetChar (); - if(inch==eof)return false; the while(inch!='-'&& (inch<'0'||inch>'9'))inch=GetChar (); - if(inch=='-') {isn=true; num=0;}Wuyi Elsenum=inch-'0'; the while(inch=getchar (),inch>='0'&&inch<='9'){ -num*=Ten, num+=inch-'0'; Wu } - if(IsN) num=-num; About return true; $ } - - intGetIDint* H,intHCNT,intx) { - returnLower_bound (H, h+hcnt, X)-h; A } + the intMain () { - //FRead (); $ intC, D; the while(~SCANF ("%d%d", &n, &m) && n +m) { the Cls (SX); Cls (SY); Xx.clear (), Yy.clear (); the Rep (i, n) { the Scan_d (X[i]); Scan_d (Y[i]); -Hx[i] = X[i]; Hy[i] =Y[i]; in Xx[x[i]].insert (Y[i]); the Yy[y[i]].insert (X[i]); the } AboutSort (HX, hx+n); Sort (hy, hy+n); thehxcnt = Unique (HX, hx+n)-HX; thehycnt = Unique (hy, hy+n)-hy; the Rep (i, n) { +Sx[getid (HX, hxcnt, X[i])]++; -Sy[getid (hy, hycnt, y[i])]++; the }Bayi Rep (i, m) { the Scan_d (c); Scan_d (d); the if(c = =0) { -printf"%d\n", Xx[d].size ()); - for(It =Xx[d].begin (); theIt! = Xx[d].end (); it++) { theyy[*It].erase (d); the } the xx[d].clear (); -Sx[getid (HX, hxcnt, d)] =0; the } the Else { theprintf"%d\n", Yy[d].size ());94 for(It =Yy[d].begin (); theIt! = Yy[d].end (); it++) { thexx[*It].erase (d); the }98Sy[getid (hy, hycnt, d)] =0; About yy[d].clear (); - }101 }102printf"\ n");103 104 } the return 0;106}
[HDOJ4022] Bombing (discretization of +stl)