HDU4742----Pinball Game 3D (three-dimensional LIS, CDQ Division)

Source: Internet
Author: User

Test instructions: N spheres in three-dimensional space, corresponding coordinates (x, y, z). Outputs the length of the LIS and the number of scenarios.

First you can sort by x, first reduce one dimension, then the left Y, Z, on y cdq divide, press Y size with the previous update behind. The z-direction discretization is then maintained with a tree-like array.

1#include <Set>2#include <map>3#include <cmath>4#include <ctime>5#include <queue>6#include <stack>7#include <cstdio>8#include <string>9#include <vector>Ten#include <cstdlib> One#include <cstring> A#include <iostream> -#include <algorithm> - using namespacestd; thetypedef unsignedLong Longull; -typedefLong Longll; - Const intINF =0x3f3f3f3f; - Const DoubleEPS = 1e-8; + Const intMAXN = 1e5+Ten; - Const intMoD =1<< -; + struct Ball A { at     intX,y,z,idx; -     BOOL operator< (ConstBall &AMP;RHS)Const -     { -         returnX < Rhs.x | | (x = = rhs.x && y < rhs.y) | | (x = = Rhs.x && y = = Rhs.y && Z <rhs.z); -     } - } BALL[MAXN],TMPBALL[MAXN]; in structDP - { to     intlen,cnt; + DP () {} -DP (int_len,int_cnt): the Len (_len), CNT (_cnt) {} * } DP[MAXN],C[MAXN]; $ intVec[maxn],idx;Panax NotoginsengInlineintLowbit (intx) - { the     returnX &-x; + } AInlinevoidUpdate (DP &AMP;DP1, DP &DP2) the { +     if(Dp1.len <Dp2.len) -DP1 =DP2; $     Else if(Dp1.len = =Dp2.len) $Dp1.cnt + =dp2.cnt; - } -InlinevoidModifyintX,DP &d) the { -      while(x <=idx)Wuyi     { the Update (C[X],D); -X + =lowbit (x); Wu     } - } AboutDP Query (intx) $ { -DP ans = DP (0,0); -      while(x) -     { A Update (ans,c[x]); +X-=lowbit (x); the     } -     returnans; $ } theInlinevoidCLR (intx) the { the      while(x <=idx) the     { -C[X] = DP (0,0); inX + =lowbit (x); the     } the } About voidCDQ (intLintR) the { the     if(L = =R) the         return ; +     intMid = (L + r) >>1; - CDQ (L, mid); the      for(inti = l; I <= R; i++)Bayi     { theTmpball[i] =Ball[i]; thetmpball[i].x =0; -     } -Sort (tmpball+l,tmpball+r+1); the      for(inti = l; I <= R; i++) the     { the         if(Tmpball[i].idx <=mid) the         { - Modify (Tmpball[i].z,dp[tmpball[i].idx]); the         } the         Else the         {94DP tmp =query (tmpball[i].z); thetmp.len++; the Update (DP[TMPBALL[I].IDX],TMP); the         }98     } About      for(inti = l; I <= R; i++) -     {101         if(Tmpball[i].idx <=mid)102         {103 CLR (tmpball[i].z);104         } the     }106CDQ (mid+1, R);107 }108 intMainvoid)109 { the #ifndef Online_judge111Freopen ("In.txt","R", stdin); the #endif113     intT, N; thescanf ("%d",&T); the      while(t--) the     {117scanf ("%d",&n);118          for(inti =1; I <= N; i++)119         { -scanf ("%d%d%d", &ball[i].x, &AMP;BALL[I].Y, &ball[i].z);121vec[i-1] =ball[i].z;122         }123Sort (ball+1, ball+n+1);124Sort (vec,vec+n); theIDX = unique (vec,vec+n)-Vec;126          for(inti =1; I <= N; i++)127         { -Ball[i].z = Lower_bound (vec,vec+idx,ball[i].z)-VEC +1;129Ball[i].idx =i; theDp[i] = DP (1,1);131         } theCDQ (1, n);133DP ans = DP (0,0);134          for(inti =1; I <= N; i++)135         {136 Update (ans,dp[i]);137         }138printf"%d%d\n", Ans.len, ans.cnt%MoD);139     } $     return 0;141}

HDU4742----Pinball Game 3D (three-dimensional LIS, CDQ Division)

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