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MySQL cross-tabulation has a cross-tabulation in some databases, but it is not available in MySQL. However, many friends on the Internet want to find a solution. Http://topic.csdn.net/u/20090530/23/0b782674-4b0b-4cf5-bc1a-e8914aaee5ab.html? 96198 The solution is as follows: Data sample: create table tx( id int primary key, c1 char(2), c2 char(2), c3 int ); insert into tx values (1 ,'A1','B1',9), (2 ,'A2','B1',7), (3 ,'A3','B1',4), (4 ,'A4','B1',2

The MySQL cross tabulation implements sharing bitsCN.com. The current solution is as follows: Data sample: Create table tx (Id int primary key,C1 char (2 ),C2 char (2 ),C3 int); Insert into tx values(1, 'A1', 'b1 ', 9 ),(2, 'A2 ', 'b1', 7 ),(3, 'A3 ', 'b1', 4 ),(4, 'A4 ', 'b1', 2 ),(5, 'A1', 'B2', 2 ),(6, 'A2 ', 'B2', 9 ),(7, 'A3 ', 'B2', 8 ),(8, 'A4 ', 'B2', 5 ),(9, 'A1', 'b3', 1 ),(10, 'A2 ', 'b3', 8 ),(1

Fibonacci again Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)Total submission (s): 37002 accepted submission (s): 17876 Problem descriptionthere are another kind of Maid: F (0) = 7, F (1) = 11, F (n) = f (n-1) + f (n-2) (N> = 2 ). Inputinput consists of a sequence of lines, each containing an integer n. (n Outputprint the word "yes" if 3 divide evenly into F (n ). Print the word "no" if not. Sample Input 012345 Sample output nonoyesnononoThis is a transfor

Acquisition of a regular solution to the great God href= "Http://bosidengny.tmall.com/category-907362758.htm?search=ycatName=%D0%C2%C6%B7%D7%A8%C7%F8"> New Area

Definition: Lossless join decomposition is the decomposition of a relational pattern into a number of relational patterns, through the natural joins and projections and other operations can still be restored to the original relational mode, it is said that the decomposition of non-destructive join decomposition. A judgement algorithm for nondestructive decomposition Input: A relational mode R (A1,a2,a3,...,an), a function on R is dependent on set F an

Yonyou software has multiple substations where SQL injection can run all the tables. UFIDA software second-level domain name:SQL Injection exists, and all tables can be run out. 1. SQL injection point 1-GETHttp: // **. **/servicehome/kmview. aspx? Postid = ZS20131231026 2. SQL injection point 2-POSTHttp: // **. **/AppWeb/BuDing/BuDingGJCX. aspxPOST:_ EVENTTARGET = __ EVENTARGUMENT = __ LastVIEWSTATE_SessionKey = d8f1c755-6b47-485e-873d-0094bd6f8a13 __ ContextPath =/ _ qam_dialog_control = _

many implementations within Redis, including sending buffer queues, are also used in this data structure. Queue usage Client.Enqueueitemonlist ("name", "Zhangsan"); Client.Enqueueitemonlist ("name", "Lisi"); int count= client.GetListCount ("name"); For (int i = 0; i { Console.WriteLine (client.Dequeueitemfromlist ("name")); } Stack use Client.Pushitemtolist ("name2", "Wangwu"); Client.Pushitemtolist ("name2", "Maliu"); int count = client.GetListCount ("na

Linux Regular Expressions:In short, a regular expression is a set of rules and methods that are defined for processing a large number of strings, such as assuming @ represents 123456,! for ABCDE. By defining these special symbols, the system administrator can quickly filter, replace, or output the required characters.Considerations for using Regular expressions:1.linux regular is usually handled by the behavioral unit.2.alias grep= ' grep--color=auto ', the lecture takes grep for example. (Note

Collection Sort, BinarySearch Warning:ImportJava.util.*; Public classListInterface2 { Public Static voidMain (String []args) {List L1=NewLinkedList (); List L2=NewLinkedList (); for(inti=0; i) {L2.add ("B" +i); } for(inti=0; i) {L1.add ("A" +i); } System.out.println (L2); System.out.println (L1); Collections.shuffle (L1); System.out.println (L1); Collections.reverse (L1); System.out.println (L1); Collections.sort (L1); Syst

", "Zhangsan"); Client.Enqueueitemonlist ("name", "Lisi"); int count= client.GetListCount ("name"); For (int i = 0; i { Console.WriteLine (client.Dequeueitemfromlist ("name")); } Stack use Client.Pushitemtolist ("name2", "Wangwu"); Client.Pushitemtolist ("name2", "Maliu"); int count = client.GetListCount ("name2"); For (int i = 0; i { Console.WriteLine (client.Popitemfromlist ("name2")); } Set typeIt is an unordered collection of type string. Set is im

", "Zhangsan"); Client.Enqueueitemonlist ("name", "Lisi"); int count= client.GetListCount ("name"); For (int i = 0; i { Console.WriteLine (client.Dequeueitemfromlist ("name")); } Stack use Client.Pushitemtolist ("name2", "Wangwu"); Client.Pushitemtolist ("name2", "Maliu"); int count = client.GetListCount ("name2"); For (int i = 0; i { Console.WriteLine (client.Popitemfromlist ("name2")); } Set typeIt is an unordered collection of type string. Set is im

Although ICBC has blocked the hotspot vulnerability, is it not? No, the vulnerability still exists. Although the ICBC page is not displayed, but the ICBC official page is used, you only need to construct a page to disguise the ICBC page and the page can still be phishing, because it involves the security of bank users, so I no longer announce the specific implementation method, only release examples of the vulnerability page, please test (the following code from http://www.phpobject.net/blog/ind

TopicThere is an array of length 2n {a1,a2,a3,..., an,b1,b2,b3,..., bn}, if you wish to sort {a1,b1,a2,b2,...., an,bn}, consider a solution with no time complexity O (n), spatial complexity 0 (1).Source2013 UC's School recruit Pen testIdea OneStep ①, determine the position of the B1, that is, let B1 with the A2,A3,A4 in front of it exchange:a1，b1，a2，a3，a4，b2，b3，b

The reflection mechanism of go is to be carried out through the interface, and the null interface of object like Java can interact with any type, so reflection on the basic data type is also directly used in this feature.Package Mainimport ("FMT" "reflect") type Student struct {Name string age int Sex UINT//0-female, 1-Male Address string}func (stu Student) Print () {sex: = "female" if Stu. Sex = = 1 {sex = "male"} fmt. Printf ("Name:%s, Age:%d, Gender:%s, Address:%s", Stu. Name, Stu. Age, sex,

Operating Environment:VMware Workstation10.0.1 build-1379776Ubuntukylin-14.04-desktop-amd64A. Virtual machine settings.1. Create a new virtual machine650) this.width=650; "title=" qq20141030134515.jpg "style=" Float:none "src=" http://s3.51cto.com/wyfs02/M01/4D/A4/ Wkiom1rv87jwtxpfaafprco68_o348.jpg "alt=" Wkiom1rv87jwtxpfaafprco68_o348.jpg "/>2. Select Custom (typical for normal users)650) this.width=650; "title=" qq20141030134539.jpg "style=" Float:none "src=" http://s3.51cto.com/wyfs02/M02/4D

A1= "SP2=20;SP1=34;" A2= "SP3=2;SP2=3;SP1=4;" Two sets of string data, adding the same data values in a string to get a new set of data namely "sp3=2;sp2=23;sp1=38" (P.s A simple application: Two of the original number of 20 pieces, the original number of goods 34, new stock or a new sale of 23 products, 14 items such as the type of simulation to calculate the purchase volume, sales and inventory, small invoicing system can use such a method) So how do you implement two sets of string data com

Contact (Relationship)1:1 Contact: If each entity in the entity set E1 can only be associated with one entity in the entity set E2, and vice versa, then the entity set E1 to E2 is a one-to-many contact, recorded as 1:1;1:n Contact: One to many, remember as 1:n;M:N Contact: Many-to-many links, recorded as m:n.Http://zh.wikipedia.org/wiki/%E5%85%B3%E7%B3%BB%E4%BB%A3%E6%95%B0_ (%e6%95%b0%e6%8d%ae%e5%ba%93)function dependency (Functions Dependency)definit

// Poj for the second top embedded cup preliminary round // Question# Include Int A3, B3;Void reduce (){While (A3% 2 = 0 B3 % 2 = 0){A3/= 2; B3/= 2 ;}While (A3% 3 = 0 B3 % 3 = 0){A3/= 3; B3/= 3 ;}While (A3% 5 = 0 B3 % 5

)%MoD; - if(b1)returnC*c%mod*a%mod;Else returnc*c%MoD; - } +nd ns[200000]; - intMain () { +ll n,m,a1=0, A2,A3,A4; ll K; scanf"%lld%lld%lld",n,m,k); AInc (I,1, k) scanf ("%lld%lld", ns[i].a,ns[i].b); Sort (ns+1, ns+k+1); atInc (I,1Kif(i==1|| ns[i].a!=ns[i-1].A) a1++; a2=n* (n+1)/2%mod; a3=a4=1; -Inc (I,1Kif(i==1|| ns[i].a!=ns[i-1].A) a4=a4*a3%mod,

--;Else POS ++;If (Pos = 0 | Pos = 27) onbar = 0;}};Int main (){Ant A1, A2, A3, A4, A5;Cout For (INT I1 = 0; I1 For (INT I2 = 0; I2 For (INT I3 = 0; I3 For (INT I4 = 0; I4 For (INT I5 = 0; I5 {// -------------------- Initialize five ant financialA1.orient = I1; a2.orient = I2; a3.orient = I3; a4.orient = I4; a5.orient = I5;A1.pos = 3; a2.pos = 7; a3.pos = 11; a4