edx mba

: 0040823co. Text: 00408284. Text: 00408284 m_l_table = dword ptr-58 h. Text: 00408284 m_ B = DWORD PTR-18 h. Text: 00408284 M_a = dword ptr-14 h. Text: 00408284 m_k = dword ptr-10 h. Text: 00408284 m_j = dword ptr-0ch. Text: 00408284 m_ I = DWORD PTR-8. Text: 00408284 l_key = dword ptr-4. Text: 00408284. Text: 00408284 push EBP. Text: 00408285 mov EBP, ESP. Text: 00408287 add ESP, 0ffffffa8h. Text: 0040828a mov [EBP + l_key], eax. Text: 0040828d mov eax, [EBP + l_key]. Text: 00408290 mov ECx, [

program writer's quality decision.The inline assembly is passed in C + +The results of the actual discovery of 500W data are as follows:Algorithm name inline assembly algorithm time C + + algorithm timeBubble sort 5W Data slow dying 5W data slow to deathQuick sort 600ms about 500ms around------------------Why there is a fast sorting algorithm, the results of the assembly is not a C + + efficiency is high, because I write the inline assembly is not automatically generated by the compiler high ef

the quality of the high and low decision. Inline assembly is passed in C + + actually found the 500W data sorting results are as follows: Algorithm name inline assembler algorithm time C + + algorithm time Bubble sort 5W data slow to die 5W data slowly dying. Quick sort 600ms about 500ms around ------------------Why there is a fast sorting algorithm, the compiled results are not as high as C/s + + efficiency, because I write inline assembly without compiler automatic generation of high efficien

With the front: + + (-) There are too many confusing places, (i++) + (i++) and (++i) + (++i) What is the difference? If you understand it from the machine's point of view, it will be enlightened. Let's take a look at the procedure: int main() { 　　　 int i=3; 　　　 int j=(i++)+(i++); 　　　 //　　　 int j=(++i)+(++i); 　　　 printf("%d,%d\n",i,j); } (1) Under VC 6.0: for (i++) + (i++): Result: i=5,j=6 The corresponding assembly code is (with detailed comments): 8B 45 FC　　　　　　　　　　　　 mov　　　　　　　　 eax,dw

body | ---------> @ 2|------> | -------------------- +|| Decryptor || ---------> @ 3+ -------------------- +@ 1 is a call constructed by computation, because the call location must be determined by @ 2.@ 2 is an encrypted virus.@ 3 is an encryptor used to decrypt @ 2, which is transformed by code obfuscation.In this way, every time other files are infected, the re-generated code will no longer have a fixed feature, which will invalidate the feature scanning mechanism. 2.1 random number design:T

microsecondsFmt6 dB/'================================================ =========== ', 0dh, 0ah ,/'Simple ASM Program to compute PI with invalid digits. ', 0dh, 0ah ,/'Pi/4 = 12 * arctan (1/18) + 8 * arctan (1/57)-5 * arctan (1/239) (Gauss )',/0dh, 0ah, 'by G-spider @ 2010', 0dh, 0ah ,/'Computation of 10000 digits of PI ', 0dh, 0ah ,/'Total computation time :',/'% 6lld Ms', 0dh, 0ah ,/'================================================ ============ ', 0dh, 0ah, 0 . Data?X dd?Y dd?_ Sizechar dd?Lppi

layout is skipped. Next let's take a look at the virtual function calling Pt-> Foo (); Through the pointer. The resulting assembly code is as follows:01 004230f6 mov eax, dword ptr [EBP + fffff900h]02 004230fc mov edX, dword ptr [eax]03 004230fe mov ESI, ESP04 00423100 mov ECx, dword ptr [EBP + fffff900h]05 00423106 call dword ptr [edX]In row 1st, the address directed by PT is moved into the eax register,

the siteCall makefs4gbsegment; the returned FS segment can be 4 GB memory. EBX =.############# Map the code to a linear address of 80000000 H + CS * 4, avoid NTS not mapped to memory reserved by our code ############MoV eax, FS: [EBX + 800 H]; eax = Linear address up to 10 bits 400 h * 4 = 800 H, determine the location of the page Directory table pointed to in S3.And eax, 0fffff000h; remove the obtained Level 2 page table attribute bit. eax = 80000000h linear address Level 2 page table physical

check_03 sub eax, ebx jmp this_exitcheck_03: CMP Cl, '*' jnz check_04 imul ebx jmp limit: CMP Cl, '/'jnz err XOR edX, EDX idiv ebx jmp this_exiterr: XOR eax, eax this_exit: retcalc endp; var_mode: input parameter,; mode = 1, expression analysis completed, 0: there are currently four Arithmetic Operators; Return Value: none; this procedure work on global array num_arr, op_arr, num_count, op_countdo_calc Pro

Tags: Assembly atampt Addition: . Section. DataVAL: . Quad 3481219651 Val1: . Quad 6678934517 Output: . Asciz "the RES is % QD \ n" . Section. Text. Globl _ start _ Start: Movl Val, % eax Movl Val + 4, % EBX Movl val1, % ECx Movl val1 + 4, % edX Addl % eax, % ECx Adcl % EBX, % edX Pushl %

2eac4 2e9c |. 85c test eax, eax // The registration code is converted to hexadecimal 4b235264 2e9e |. 7c 12 JL short China Communications. 4 2eb24 2ea |> 59 pop ECx // false code 787878784 2ea1 |. 31f6 xor esi, ESI // ESI = 1 2fc59 = 169728894 2ea3 | gt; 8932 mov dword ptr ds: [edX], ESI4 2ea5 |. 5f pop EDI4 2ea6 |. 5E pop ESI4 2ea7 |. 5B pop EBX // EBX = 787878784 2ea8 |. C3 retn 4 A |. 8bf mov ESI, eax // ESI = A eax = 4b235264 A A2 |. 833c24 cmp

. Text: 000387c9 call kegetcurrentirql. Text: 000387c9. Text: 000387ce and eax, 0ffh. Text: 000387d3 test eax, eax. Text: 000387d5 jnz short loc_387ef. Text: 000387d5. Text: 000387d7 call sub_37b5f. Text: 000387d7. Text: 000387dc test eax, eax. Text: 000387de JZ short loc_387ef. Text: 000387de. Text: 000387e0 mov dword_4b258, 0. Text: 000387ea call sub_37b9a. Text: 000387ea. Text: 000387ef. Text: 000387ef loc_387ef:; Code xref: sub_38736 + 91 \ u0018j. Text: 000387ef; sub_38736 + 9f \ u0018j. Te

(Bbs.qianxiao.com) First, "Claw-free theory": Zhu Min has some opinions on MBA business schools. He believes that entrepreneurs are like a fast-trained Tiger. "When Tigers have claws, they will be worn out and become cats when they enter the MBA program ." He believes that there are two types of creativity: analytical, artificial manufacturing by training MBA, a

check whether your input is correct". I think those characters may be nearby, so double-click "registration failed, check whether your input is correct. 00415829 |> 66: C745 A4 D4> mov word ptr ss: [EBP-5C], 0D40036682f |. BA ADEC4900 mov edx, TextDraw.0049ECAD; Registration failed. Please check whether your input is correct00415834 |. 8D45 B8 lea eax, dword ptr ss: [EBP-48] In section 00415829, the "jump from 0000004ed" is displayed in the informat

efficiency, should be converted to assembly, the intermediate results into a separate register40.//Thanks to Menzi11 's article, let me realize that the relevant data in the program will make the CPU can not disorderly execution.41.//Here is replaced by pseudo assemblerTYPE S4 = 0;43.Register TYPE r1 = 0;Register TYPE r2 = 0;for (int i = 0; i R1 + + + a[i++];R2 + = a[i++];49.}50.Wuyi Cout52.} Several of the above versions are reasonable, but these optimizations are based on the assumption that

The test software is Splish.exe.Bytes ------------------------------------------------------------------------------------------I am sure everyone knows the beginning of searching for an algorithm. I will not talk about it here. Next I will directly discuss the assembly code and comments of the algorithm.Bytes ------------------------------------------------------------------------------------------------004015E4 55 push ebp; algorithm started004015E5 8BEC mov ebp, ESP004015E7 6A 20 PUSH 2000401

dummy1, int dummy2){_ ASM {Push EBPMoV EBP, ESPMoV eax, 152Lea edX, 8 [EBP]Int 0x2ePop EBPRET 9}} It turns out that the user space also has an ntreadfile (), which is executing the self-trapping command "int 0x2e ". Let's take a look at this Assembly Code. Here, 152 is the call number of the System Call ntreadfile (), so when the CPU falls into the system space, the register eax holds the specific system call number. The register

connect them during compilation?In this case, we can conclude that there is another secret. For more information, see ntreadfile () in msvc6/iface/native/syscall/debug/ZW. C: _ Declspec (naked) _ stdcallNtreadfile (INT dummy0, int dummy1, int dummy2){_ ASM {Push EBPMoV EBP, ESPMoV eax, 152Lea edX, 8 [EBP]Int 0x2ePop EBPRET 9}} It turns out that the user space also has an ntreadfile (), which is executing the self-trapping command "int 0x2e ". Let's t

In many network development scenarios, memory conversion is often encountered in the following scenarios: #define PACKAGE_PARSE_ERROR -1#define PACKAGE_PARSE_OK 0int parse_package( int* a, int* b, int* c, int* d, char* buf, int buf_len ){ if( !buf || buf_len This is a call in the Process of network unpacking, and the packet process is a reverse process. An application like this can be replaced by an integer forced conversion, and the efficiency will be at least doubled. To illustrate t

Reading Tips: 《Delphi Image ProcessingThe series focuses on efficiency. The general code is Pascal, and the core code is BaSm. 《C ++ Image ProcessingThe series focuses on code clarity and readability, and all uses C ++ code. Make sure that the two items are consistent and can be compared with each other. The code in this article must include the imagedata. Pas unit in "Delphi Image Processing-data type and public process. The minimum value processing of an image is centered on the current pixel