information system security notes

sleep for%d seconds\n ", getpid (), delay);Sleep (delay);printf ("Child-done. About to exit\n ");Exit (27);}void Parent_code (int childpid){int WAIT_RV;int child_status;int High_8, low_7, bit_7;WAIT_RV = Wait (child_status);printf ("Do waiting for%d. Wait returned:%d\n", Childpid, WAIT_RV);High_8 = Child_status >> 8; /* 1111 1111 0000 0000 */Low_7 = child_status 0x7F; /* 0000 0000 0111 1111 */bit_7 = child_status 0x80; /* 0000 0000 1000 0000 */printf ("status:exit=%d, sig=%d, core=%

IP. \192.168.0.234, enter the username BC, password 123456 and then OK, you can access the virtual machine's files. Then extract the required files to the shared folder BC. Enter the virtual machine, enter the./install.sh on the command line, and the setup script will automatically establish the directory and configure the compilation environment. Configure environment variables use VI in a virtual machine modify the PATH variable in the/root/.bash_profile file to path= $PATH: $HOME/bin:/op

expressed in the desired floating-point form.1. Rounding to even numbersRounds a number up or down so that the lowest effective number of the result is even.2. Rounding to 03. Rounding up4. Rounding Down34 you can see the upper bound.Rounding to even gets the closest match.4. Floating-point arithmeticFloating-point addition: exchangeable, non-associative, satisfying monotonicityFloating-point multiplication: exchangeable, non-associative, non-assignable, satisfies the following monotonicityFloa

2018-2019-1 20165228 "The foundation of Information security system Design" experimental report on Buffer Overflow Vulnerability Experiment Introduction:Buffer overflow attack: by writing to the program's buffer beyond its length content, causing buffer overflow, thereby destroying the program's stack, causing the program to crash or to make the program to execut

Chapter fourth Processor Architecture section Y86 instruction set architecture One, programmer visible State 1. Meaning:Each instruction will read or modify portions of the processor state2. "Programmer":It can be the person who writes the program with the assembler code, or the compiler that produces the machine-level code.3. Specific processor status: similar to IA32 There are 8 program registers ,%EAX,%ECX,%EDX,%EBX,%ESI,%EDI,%ESP,%EBP Each program register of the processor store

/12 20/200 Learn the contents of system level I/O and understand the intrinsic function Tenth Week 407/1035 1/13 30/230 Analyze and debug your code, system-level I/O content 11th Week 714/1749 2/15 40/270 Understanding anomalies and their types 12th Week 0/1749 4/19 30/300 Review the contents of t

Beijing Institute of Electronic Technology (BESTI)Real inspection report Course: Information Security system Design Basic class: 1352 Name: LussonStudy number: 20135229 20135234 score: Instructor: Lou Jia Peng Experimental Date:: 2015.11.10Experiment level: Preview degree: Experiment time: 15:30-17:30Instrument Group: Compulsory/Elective: compulsory test

2018-2019-1 "Information Security system design basics" x-week study summary of learning ContentsSummarize what you learned this week as simple as possible.Try not to transcription, waste timeRead it, do not understand, learn to remember the experienceProblems in teaching materials learning and the solving process(a template: I read this paragraph of text (quoted

2018-2019-1 20165325 summary of the fifth week of Information Security System Design 1. Storage Technology Memory can be divided into volatile memory and non-volatile memory,Volatile memoryWhen the computer is shut down or accidentally shut down, the data in the computer will be lost, just like the memory.Non-volatile memoryIn this case, data will not be lost, su

2018-2019-1 20165329 summary of the fifth week of Information Security System Design Basics Summary of teaching material learning content 1. Random Access to memory is divided: Static RAM (SRAM): Each bit is stored in a bistable memory unit, and each unit is implemented by a six transistor circuit. Dynamic RAM (Dram): each bit of

FeelingsJust beginning to touch Java, feel both confused and hard, because they have not been in a self-learning way to contact a new programming course, long time to find more difficult. I think, teacher and student relationship is eldest brother and brother! Why do you say that, because the teacher experienced the student age and more understanding of the situation of students, leading students to learn and impart some experience, so that students less detours, and exchange ideas with students

after the completion of Y86 in the pipe folder input./PSIM-T-G. /y86-code/asum.yoEnter Y86-code, Generate Asuml.yoI try to knock the code out of the book, and then enter the following commandmake cleanmake 251pp.yoYou can then view the　　Code Managed Links: http://git.oschina.net/Zziyang/CS04Learning progress Bar lines of code (new /Cumulative) Blog volume ( new/cumulative) Learning time (new/cumulative) Important growth Goal 5000 row

process.The multithreaded execution model is similar in some ways to a multi-process execution model.Each process starts its life cycle as a single thread, which is the main thread. At some point, the main thread creates a peer thread, starting at this point in time, and two threads are running concurrently with each other.A POSIX thread is a standard interface for processing threads in a C program.To terminate a process:1. When the thread routine of the when top layer returns, the line Cheng t

function, which can be seen as a buffer version of the UNIX read function. When calling Rio_read requires reading n bytes, there are rp->rio_cnt unread bytes in the read buffer. If the buffer is empty, the read system function is called to fill the buffer. This read call is not an error if it receives an insufficient value, except that the read buffer is partially populated. Once the buffer is non-empty, Rio_read copies N and rp->rio_cnt from the rea

information is accessed relative to the frame pointer. Program register groups are the only resources that can be shared by all processes. 根据惯例寄存器%eax,%edx,%ecx被划分为调用者保存寄存器。 %ebx,%esi,%edi被划分为被调用者保存寄存器。 %ebp,%esp 惯例保持 %eax用来保存返回值 The call command has a target, which indicates the address of the instruction at the beginning of the called process, and the effect is to put the return address into the stack and jump to the beginning of the

20145326 Cai "The basis of information security system design" 12th Week study summary of learning Contents Summary of the Nineth Week learning content Summary of the tenth week learning content Summary of the 11th Week learning content Video learning and practice pointers and statementsThe declaration of a variable in the C language consist

not, then change the machine to ...) ） Super Terminal information Experiment Box Results show The problems encountered during the experiment and the solutions. (1) Related software and driver installation problems We used a computer that already has ads and Jtag installed, which leads us to fail the first time we try to install ads, so ads need to be uninstalled and installed before they

RET instruction pops the address from the stack and jumps to that position.3.7.3 Register Usage ConventionsYou must guarantee that when a caller invokes the callee, the callee does not overwrite the value of a register that the caller will later use.Two ways to achieve the above requirements:• Before calling Q, the value of y is stored in its own stack frame, and when Q returns, process P can remove the value of y from the stack, that is, the caller holds the value of Y.• Save the value of Y in

autowrite(aw) set AutoArchive, default not open Enter or in command line :set background=dark mode light , set the background style Command line mode input :set backup(bk) set automatic backup, default not open Command line mode input : set cindent(cin) set C language style indent 3.Linux System Programming(1) Use of GCCcompiler use of GCC Second, the problems encountered and sentiment:Early groping vim time with too much, followed t

shared. 10.7 redirectsI/O redirection: Use the DUP2 function:#include int dup2(int OIDFD,int newfd); Returns: a non-negative descriptor if successful, or1 if an error occurs10.8 Standard I/OStandard I/O library (LIBC): Advanced input-Output functions#include extern FILE *stdin;/* standard input, file descriptor 0*/ extern FILE *stdout;/* Standard output, file descriptor 1*/ extern file *STDERR;/* standard error, file descriptor 2*/ The standard I/O library m