learning javascript data structures and algorithms

simple; An ordered array can be found using two points; The logarithm of base a of B (probably) is the number of times the B is removed before the result of drizzle 1; The time required for linear lookups is proportional to the number of data items in the array; The time required for binary lookup is proportional to the logarithm of the number of data items in the array; The large O not

of red-Haishi. But they can't all be full, so the height of the 2-3-4 tree is roughly log2 (n+1) and log2 (n+1)/2. Reducing the height of the 2-3-4 tree makes it shorter to find than red-Haishi.On the other hand, each node has more data items to view, which increases the lookup time. Because a linear search is used in a node to view data items, the multiple of the lookup time is proportional to M, which is

){ if(Array[j] key) {Array[i+ +] = Array[j];//A[i] = a[j]; i + = 1; Break; }; } for(; i ){ if(Array[i] >key) {Array[j--] =Array[i]; Break; }}} Array[i]=key; Sort (0, i); Sort (i+ 1, numsize); }} sort (0, Array.Length); returnArray;}There is also an easy-to-understand approach:Set two empty arrays left and right, traverse the entire array, and push in to leave if it encounters less critical

First, the program design1. Design function System--data table design, data table creation statement, connection database way, coding abilityIi. basic knowledge of the framework1. The basic principle of MVC framework-principle, common frame, working principle of single entry, understanding of template engine2, the characteristics of the common framework--php framework differences and advantages and disadvan

when the display, but, The next time the element is inserted, the new element will replace the position of the last element.3) Find optimization--two points to findpublic int find (int value) { int start = 0; int end = Number-1; while (End>start) { int index = (end + start)/2; if (array[index]==value) { return index; } else if (Array[index] >value) { end = index-1; } else { start = in

　　 Packagecom.test.sort.insertion; Public classBinaryinsertsort {/** * @paramargs*/ Public Static voidMain (string[] args) {//TODO auto-generated Method StubSYSTEM.OUT.PRINTLN ("Binary Insert sort sort function implementation")); int[] arr = {23, 54, 6, 2, 65, 34, 2, 67, 7, 9, 43 }; Binaryinsertsort Sort=NewBinaryinsertsort (); System.out.println ("Sort before sequence:"); Sort.printarr (arr); Sort.bininsertsort (arr,0, Arr.length-1); System.out.println ("Sort after sequence:");;

of its parent node.This situation is the most difficult to solve, because no matter how it can not be adjusted with a discoloration or a single rotation, this situation is usually used in conjunction with Case 5, first of all, the parent node of the insertion node is the axis left-handed.Before adjustmentAfter adjustmentCase 5: The parent node of the current node is red, the Uncle node is black, and the current node is the left child node of its parent node.In case 4, the parent node of the ins

The essence of enumeration method is to search for the correct solution from all candidate answers, and the algorithm needs to satisfy two conditions: 1, the number of candidate answers can be determined first; 2. The range of candidate answers must be a definite set before solving. Enumeration is the simplest, most basic, and least efficient algorithm for enumerating the advantages of the enumeration method: 1. Enumeration hassuper-Unbeatable accuracy, as long as the time is enough, the correct

1. Select the principle of sorting2. Code implementationdefSelection_sort (alist): N=Len (alist)#requires a n-1 selection operation forIinchRange (n-1): #Record minimum positionMin_index =I#Select the minimum data from the i+1 position to the end forJinchRange (i+1, N):ifALIST[J] Alist[min_index]: Min_index=J#If the selected data is not in the correct location, swap ifMin_index! =I

Method Public BooleanDeleteLongvalue) { intj =find (value); if(j==Nelems) { return false; } Else { for(intK=j; k) {A[k]= A[k+1]; } nelems--; return true; } } //Binary Method Search Public intFindLongSearchkey) { intlowerbound = 0; intUpperbound = nElems-1; intCurin; while(true) {Curin= (lowerbound + upperbound)/2; if(a[curin]==Searchkey) { returnCurin;//found it } Else if

Data structure: The way in which it is arranged in the computer's storage space.Algorithms: Software programs manipulate the data processes of these structures.Data structure Type1. Arrays:Advantages: Fast insertion, direct subscript can be accessed quickly.Cons: Find slow, delete slow, fixed size.2. Ordered arrays:Pros: Faster than no need for array lookups.Cons: Delete and insert slow, fixed size.3. Stack

-operation Traversal, we first recursively use the post-traversal to access the Saozi right subtree, the last access to the root node root node, right subtree, left dial hand tree def postorder (self, Root): "" " recursive implementation of subsequent traversal" " if root = = None: return self.postorder (root.lchild) Self.postorder (root.rchild) print (Root.elem)Breadth-first traversal (hierarchical traversal)From the root of the tree, from top to bottom, from l

satisfied will remain unequal. This is known as shallow equality (e.g.).We can create deep equality (such as) – judged by value equality, unlike references – by overriding __eq__ methods.__eq__is another standard method that exists in all classes. __eq__ The method compares two objects when the value is equal and returns True otherwise False .In the Fraction class, we implemented a __eq__ method to compare fractions by a conventional comparison method (see Listing 7). It's worth noting that the

Simple single-linked list implementation, the data type is defined as an int, if you want to be generic, you need to change to a template class, and then slightly modified to the next.List.h#include Main.cpp#include "List.h" #include Output:There are some features not implemented, such as the insertion of elements in the specified location, linked list search, etc., because there is no iterator, with index do not be too good, simply do not write forge

integers with n elements, at least one repetition number, that is, there may be multiple repetitions, and O (n) time to find any one of the repetitions. For example, array "" = {1,2,2,4,5,4}, then 2 and 4 are repeating elements. Bitmap method. Use the size of the N bitmap to record whether each element has occurred, and once it encounters an element that has already appeared, it is output directly. Time complexity is O (n), spatial complexity is O (n) Array sorting method. First, t

() {arr = new LONG[10];elements = 0;Front = 0;end =-1;}/*** Construction method with parameters, size of parameter array*/Public mycyclequeue (int maxsize) {arr = new Long[maxsize];elements = 0;Front = 0;end =-1;}/*** Add data, insert from end of team*/public void Insert (Long value) {if (end = = arr.length-1) {end =-1;}Arr[++end] = value;elements++;}/*** Delete data, remove from team header*/Public long R

. The algorithm is then filtered up.Note: Up and down, filtering up is only compared with a parent node and stops filtering when it is smaller than the parent node.　　5. Complete Java Heap CodeFirst we need to know some of the main points of using arrays to represent heaps. If the index of the node in the array is x, then:The left child node of the node is 2*index+1,The right child node of the node is 2*index+2,The parent node of the node is (index-1)/2.Note: When the "/" symbol is applied to an

;}return successor;}/*** Pre-sequence traversal*/public void Frontorder (Node localnode) {if (Localnode! = null) {Accessing the root nodeSystem.out.println (Localnode.data + "," + localnode.sdata);Pre-sequence Traversal ZuoziFrontorder (Localnode.leftchild);Pre-sequence traversal right subtreeFrontorder (Localnode.rightchild);}}/*** Middle Sequence traversal*/public void Inorder (Node localnode) {if (Localnode! = null) {Middle Sequence Traversal ZuoziInorder (Localnode.leftchild);Accessing the r

Java data structures and algorithms (Robert lafore) Chapter 4 /* Write a method in the queue class of the program job 4.1 For the queue. Java program (listing 4.4) to display the queue content. Note that this is not a simple display of the array content. It is required to display data from the first inserted

Second=Head; //The second node moves backwards K-1 step for(inti = 0;i ){ //determine if the second is empty if(second==NULL){ Throw NewNullPointerException (); } Second=Second.next; } //two nodes move backwards until the end of the linked list while(second!=NULL) { First=First.next; Second=Second.next; } returnfirst.date; }We can see that at the beginning of the direct judgment K equals 0, we directly judge whether he is empty