The question is very simple: calculate the number of the n-th ononacci. If the number of the first four and the last four are output in the middle of the Eight-bit output..., otherwise, the number of Fibonacci is directly output.
The last four
FFT and Power spectral estimation
Power Spectrum---Periodic graph method for signal extraction using Fourier transform
ClFfs=1000;n=256; The length of the nfft=256;% data and the length of the data used by the FFTTime series used by
This article mainly introduces a concise summary of MySQL mathematical functions. This article summarizes most of the commonly used MySQL mathematical functions and provides examples for use. For more information, see
1. ABS (x): returns the
Source: http://www.cnblogs.com/stonehat/p/3603267.htmlHere, worship the original author heheWe know that the number of bits of integer n is calculated as: log10 (n) +1So the number of n! is log10 (n!) +1If the specific value of n! is required, the
Mathematical functions are mainly used to deal with numerical data, the main mathematical functions are: absolute value function, trigonometric functions (including sine function, cosine function, tangent function, cotangent function), logarithmic
How many factorial digits are there in 1000? How many consecutive zeros are there?There is a factorial FormulaFor example, 1000 factorial digits:Log10 (1) + log10 (2) + · + long10 (1000) is rounded up and then added to 1OrLog (N !) = LnN! /Ln10=
http://acm.hdu.edu.cn/showproblem.php?pid=1568FibonacciTime limit:1000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 3947 Accepted Submission (s): 1817Problem Description2007 year has come. After 2006 years of
This problem is actually water problem come, beg Fibonacci number of the first 4 and the last 4, in n==40 here demarcation open. After 4 bit is not difficult to seek, because N reached the scale of the 10^18, so can only use the matrix fast power to
http://acm.hdu.edu.cn/showproblem.php?pid=1018The number of digits of the factorial of a numberFormula LOG10 (n!) =log10 (1) +log10 (2) +log10 (3) +log10 (4) ... +log10 (n)With this formula, everything looks a lot simpler.#include
Ask for a number n How many bits, usable log10 (n) +1, so, ask N! How many bits log10 (1*2*3*......*n) =log10 (1) +log10 (2) +......+log10 (n) +1#include #includeusing namespacestd;intMain () {intn,i,m,j; DoubleD; while(cin>>N) { for(i=0; i)
Problem DescriptionIn Many applications very large integers numbers are required. Some of these applications is using keys for secure transmission of data, encryption, etc. In this problem you is given a number, you has to determine the number of
Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 1018
Problem solving Report: Enter N and ask n! Number of digits.
First, the number of digits x = (INT) log10 (x) + 1;
So n! The number of digits = (INT) log10 (1*2*3 * ...... n) + 1;
For me to wait for a mathematical color pen, right should broaden the knowledge of number theory .. It is estimated that nothing will come to mind during the competition .... Orz
1. Fibonacci series.
This series is well-known and came out when
Description
2007 is coming. After one year of practice in 2006, zouyu, a mathematical prodigy, finally ranked 0 to 100000000 In the Fibonacci series.(F [0] = 0, F [1] = 1; F [I] = f [I-1] + F [I-2] (I> = 2 )) all the values are backed up.Next,
http://acm.hdu.edu.cn/showproblem.php?pid=1018Test instructions: Gives a number n, the number of bits of the factorial of the output nKhan Σ (° °| | |) ︴At first, we were prepared to multiply the multiplication of large numbers, but the factorial
"Intro" RMQ (Range minimum/maximum Query) Question:For series A with length n, answer a number of questions RMQ (A,I,J) (I,jMethod1, simple (that is, search), O (n)-O (qn) online. 2, line tree, O (n)-O (Qlogn) online. 3, ST (essentially
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