obj socks

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How to use socks proxy for internetopen

1. Related functions: Hinternet winapi internetopen ( Lpctstr lpszagent, DWORD dwaccesstype, Lpctstr lpszproxy, Lpctstr lpszproxybypass, DWORD dwflags ); Bool winapi internetsetoption ( Hinternet, DWORD dwoption, Lpvoid lpbuffer, DWORD dwbufferlength ); 2. Related Structure Typedef struct { DWORD dwaccesstype; Lpctstr lpszproxy; Lpctstr lpszproxybypass; } Internet_proxy_info, * lpinternet_proxy_info; 3. Use a Proxy Server (1) set dwaccesstype to internet_open_type_proxy. (2) Set lpszproxy (A)

Rtcp. py works with lcx to forward port 3389, which is much faster than socks reverse proxy on port 80.

Rtcp. py works with lcx to forward port 3389, which is much faster than socks reverse proxy on port 80. Only port 80 (aspx webpage) is mapped to an intranet server ). Originally, I wanted to use regeorg as a Web page socks proxy. The result was very slow. Now it is found that the single port forwarding is good, and the transfer of 3389 is acceptable even when the screen gets stuck. Therefore, lcx is upl

rtcp.py with LCX 3389 port, the socks reverse proxy that is much better than 80 port

An intranet server was encountered and only 80 ports (ASPX Web pages) were mapped.Originally wanted to use regeorg to do a Web socks agent, the results of the speed is odd slow.Now found that the single port forwarding is good, 3389 turn out the screen is still able to accept.So I uploaded lcx to do the forwarding.Which public network machine to accept it? Choose Linux instead of win, because win will probably need to login to the 3389 GUI just fine,

BZOJ2038 [2009 Countries Training team] small Z socks (hose) (Mo team algorithm)

R is assumed to reach the farthest in the last piece, that is up to N times--r back to the target, a total of √n blocks, so the R change number is at most (n+n) *√n. The cost of the new answer is X, so the time complexity is O (x*n*√n)! This problem, set each interval [l,r] Each color of the socks number is $a,b,c,d,\dots$, each interval [l,r] The answer is $ (c_a^2+c_b^2+c_c^2+c_d^2+\cdots)/c_{r-l+1}^2$, expand to simplify:$$ (A^2+b^2+c^2+d

Configuring SOCKS 5 Agent under Linux

background : Recently the development department needs a proxy server to simulate the customer site environment. Well, then choose Socks5.Environment : Centos6.6 X64Socks Introduction:What is Socks: the firewall Security session Translation protocol (Socks:protocol for sessions traversal across firewall securely) Socks protocol provides a framework for clients in TCP and UDP domains/ Server applications mak

HYSBZ 2038 small Z Socks (hose) (Mo Team Algorithm primer)

plus 1temp+= (Long Long) num[a[r]]*Num[a[r]]; } while(l>M[i]. L) {L--; Temp-=(Long Long) num[a[l]]*Num[a[l]]; NUM[A[L]]++;//A[l] The number plus 1temp+= (Long Long) num[a[l]]*Num[a[l]]; } while(r>M[i]. R) {Temp-=(Long Long) num[a[r]]*Num[a[r]]; NUM[A[R]]--;//A[l] The number minus 1temp+= (Long Long) num[a[r]]*Num[a[r]]; R--; } while(lM[i]. L) {Temp-=(Long Long) num[a[l]]*Num[a[l]]; NUM[A[L]]--;//A[r] The number minus 1temp+= (Long Long) num[a[l]]*Num[a[l]]; L++; } ans[m[

bzoj2038: [2009 countries Training team] small Z socks (hose)

1#include 2#include 3#include 4#include 5#include 6 using namespacestd;7 #defineMAXN 500058typedefLong Longll;9ll ans=0, ANS[MAXN],BNS[MAXN];Ten intn,m,sum[maxn],a[maxn],block[maxn],temp; One structtsegment{ A intId,l,r; - }QS[MAXN]; - voidprepare () { thetemp=sqrt (n); - for(intI=1; i1)/temp+1; - } - BOOLComp (tsegment x,tsegment y) { + if(block[x.l]==BLOCK[Y.L]) { - if(block[x.l]%2==1)returnx.rY.R; + Else returnX.r>Y.R; A } at returnblock[x.l]BLOCK[Y.L]; -

UVA 10277 boastin ' Red Socks

1#include 2#include 3#include 4 5 using namespacestd;6 7Unsignedintr,sum,p,q;8Unsignedintst[50010][2];9 Ten unsigned gcd (unsigned a,unsigned b) One { A returnB?GCD (b,a%b): A; - } - /*Hash Linked list*/ the Const intHash=50007; - intHead[hash],next1[hash]; - intHASH1 (unsignedints) - { + returns%HASH; - } + intInsertints) A { at intH=HASH1 (st[s][0]); - intu=Head[h]; - while(u)//The end of the list is always 0, so s cannot be 0 -u=Next1[u]; -NEXT1[S]=HEAD[H];//the original

HYSBZ 2038 small Z Socks (hose) (Mo team algorithm)

Test instructions: Chinese question.Analysis: The very famous MO team algorithm, the first expression of this probability, should be the molecule: C (x1, 2) + C (x2, 2) + C (X3, 2) + ... + c (xn, 2) Denominator: C (n, 2), and then the expression of fractions, [X1 (x1-1) +x2 (x2-1) +...+XN (xn-1)]/(n (n-1)) then the simplification is obtained (Sigma (XI*XI)-N)/(n (n-1)), then the operation of each interval, offline, so that the sequence is divided into sqrt (n) block, and then with two pointers,

Setting up an HTTP proxy via socks tunnel

1. Create tunnel on the server using SSHSSH 10080 -f-c-q-n [email protected]112.34. 113.35 -D: Let SSH on the specified port (1025-65536-----n:tells SSH That no command would be sent once the tunnel is up# the last specified is the SSH user and the currently established tunnel server IPRun in the background after execution, you can view the process through PS2. Configure SOCKS5 proxy locally via puttyOpen Putty,1) Session, fill in the Host Name is just the server IP, port is 22 (note that this

"bzoj2038-Little Z socks" mo team algorithm

[I].R); theb[i].k=b[i].l/sq; -B[i].id=i;Wuyi } theSort (b +1, b+m+1, CMP1); -memset (SUM,0,sizeof(sum)); Wu intL=1, r=1; sum[a[1]]=1; ans=0; - for(intI=1; i) About { $ while(L1); l++;} - while(LGT;B[I].L) {Revise (L-1,1); l--;} - while(R1,1); r++;} - while(RGT;B[I].R) {Revise (r,-1); r--;} AB[i].fz=ans;b[i].fm= (LL) (b[i].r-b[i].l+1)) * ((LL) (B[I].R-B[I].L))/2; +Gcd=GETGCD (b[i].fz,b[i].fm); theB[i].fz/=gcd;b[i].fm/=gcd; - if(b[i].fz=

Bzoj 2038 2009 Country Training Team Small Z socks (hose) MO Team Algorithm

The main topic: given n points, each point has a color, m inquiry, each asked a range randomly selected two points the same probability of the same numberOtz-mo Team algorithm ...The specifics of this, whether it's a block or a Manhattan minimum spanning tree, I'm not going to talk about it.The practice of this problem is to record a CNT array representing how many of each color in the current intervalAdd a point with a color of x on ans+=cnt[x] and cnt[x]++Reduce the point of a color x to cnt[x

In the VPS with 3Proxy set up HTTP proxy and socks agent (Ubuntu Environment) _ Server Other

3Proxy is developed by the Russians (how are the Russians, front nginx), the homepage in www.3proxy.ru. 3Proxy supports a variety of platforms such as Windows and Linux. Download the installation directly under Windows, Linux needs to compile itself below. Although it is compiled and installed, it is effortless. download, compile, install: wget http://www.3proxy.ru/current/3proxy-0.7-devel.tgz Tar zxf 3proxy-0.7-devel.tgz CD 3proxy-0.7 Make–f Makefile.linux Make–f Makefile.linux Install

iphone uses the SOCKS agent on your Mac

Step 1. Make sure the SOCKS tunnel on your work computer allows LAN connections so your iphone/ipod Touch can connect to it.ssh -N -g -D 1080 [emailprotected]Step 2. Create a text file and insert the following code:function FindProxyForURL(url, host){ return "SOCKS 192.168.xx.xx:yyyy";}Replace The X ' s with your IP and the Y's with the port used after the-d in your SSH commandStep 3. Save the text fil

MO Team algorithm [country training team] small Z Socks

Topic Link Windam https://www.luogu.org/problemnew/show/P1494Probably say what you understand.The formula for calculating the probability first∑c ( 2,f (i ) ) /c (2r l+ 1) f (i) is the number of socks for each color in the interval The last formula to be introduced is ∑f (i) *f (i)-(R? L+1)/C(2,r? ) L+1) (I don't know how to push it.) given by others); The mere violence does not say O (n*n*n);The Next and O (n*n);Mo team is O (n*sq

Illustrator design svg Christmas socks font icon Drawing Tutorial

To give you illustrator software users to detailed analysis of the design of SVG Christmas socks font icon to draw a tutorial. Tutorial Sharing: Well, the above information is small set for you illustrator of this software users brought to the detailed design of the SVG Christmas socks font icon of the drawing tutorials to share the full content of the You see the users her

Torque Runtime "Qmgr obj=xxx svr=default:unauthorized Request msg=error in Permissions (perm_xxx)" Problem resolution

After installing Torque4.1.2, run "sudo./torque.setup ================================================================================ Initializing TORQUE ... You are have selected to start Pbs_server in Create mode. If the server database exists it would be overwritten. Do your wish to continue y/(n)? y root 28100 1 1 04:03? 00:00:00 pbs_server-t Create Max open servers:9 qmgr obj= svr=default:unauthorized Request msg=error in permissions (P

2038: [2009 countries Training team] small Z socks (hose) MO Team Algorithm

Topic Link: Click to open the linkFirst, the query is processed into Manhattan's smallest spanning tree.Then you can run violently on the tree.Can use MO team situation should be for inquiry [L,r], [l ', R '] cost must be ABS (L-L ') + ABS (R-R ')#include 2038: [2009 countries Training team] small Z socks (hose) MO Team Algorithm

Using Webshell to build socks agents [dark clouds]

https://github.com/sensepost/reGeorgExamples of use:python reGeorgSocksProxy.py -p 8080 -u http://upload.sensepost.net:8080/tunnel/tunnel.jspStep 1. Upload a script (aspx|ashx|jsp|php) to the Web server. Step 2. Execute the regeorgsocksproxy.py script to connect the shell listening port. * * If you use tools such as nmap need to use Proxychains. Step 3. Hack the planetThis article from "Lonely Moon Cold City" blog, declined reprint!Using Webshell to build so

Object.assign () {... obj} JSON. The difference between several copies of Parse, etc.

Let obj = {age:10}Let obj1 = {grade:1, name: {first: ' Bob '}}Let Objs = Obj1let Obja = object.assign (obj, obj1) Let OBJJ = Json.parse (json.stringify (obj1)) Let OBJK = {... obj1}Console.log (Obja) console.log (OBJJ) console.log (OBJK)Obj1.grade = 9obj1.name.first = ' Chris 'Console.log (OBJS) console.log (obja) console.log (OBJJ) console.log (OBJK) printing results:{age:10, grade:1, name: {first: ' Bob '

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