oid suffix

; i1]; - for(i=n-1; i>=0;-I.) sa[--u[tmp[i]]]=Y[i]; $ for(Swap (x, y), p=1, x[sa[0]]=0, i=1; ii) $X[SA[I]]=CMP (y,sa[i-1],sa[i],j)? p1:p + +; - } - Calc_h (n,x); the returnx; - }Wuyi the intMain () - { Wu intI,n; -scanf"%s", R); Aboutn=strlen (r); $ for(i=0; iR[i]; - -Get_sa (n+1, the); - A for(i=1; i"%d", sa[i]+1); +printf"\ n"); the for(i=2; i"%d", H[i]); - $ return 0; the}View CodeIn the calculation of the H array, it is not necessary t

Because Konjac Konjac azui ago Time busy preparing to save the election, and in the province selected muffled rolling big thick, blog stop for a long period.After the election of the whole people all kinds of decadent, all day playing mud or something ...The previous period of time to learn the suffix array when the Internet to check the relevant data, see that the suffix array and

Suffix family known Memberssuffix Treesuffix ArrayAutomatic suffix machinesuffix Cactussuffix prophecysuffix splay? The suffix tree is the ancestor of the suffix array and the suffix automaton? The function is still relatively powerful, it is useful in palindrome string or d

Once we've learned to build Sam, we'll start learning how to use Sam to deal with all kinds of problems.Let's start with the overall look at Sam's nature (quoted from 2015 National training Team proceedings Zhang Tianyan "suffix automata and their applications"): 1. The length of the string represented by each state s is the interval (Le n f a Span style= "Display:inline-block; width:0px; Height:2.456em; " > s ,Le n s ]

intWa[n], Wb[n], ws[n], Wv[n]intRank[n], Height[n]#此处N比输入的N要多1, a character added for manual use to avoid CMP time out of boundsvoidGetsa (int(RNint*sa,intNintMintI, J, p, *x = WA, *y = WB, *t# Buckets emptied for(i =0; I 0 #进行一次基数排序 for(i =0; I for(i =1; I 1] for(i = n-1; I >=0; i--) Sa[--ws[x[i]] = i#倍增法 for(j =1, p =1; P 2, M = p)#string [N-j. n] is a suffix that has no offset to J so the second keyword defaults to 0 #所以按照第二关

Previous article ([Algorithm Series 20] dictionary tree (Trie)) we introduced the dictionary tree in detail. With these basics, we can better understand the suffix tree.An introduction pattern matching problemGiven a text text[0...n-1], and a pattern string pattern[0...m-1], write a function search (char pattern[], Char text[]), and print out all the positions (n > m) where pattern appears in text.This problem already has two classical algorithms: KMP

/*p1860 suffix ArrayTime: 1000ms/Space: 131072kib/java class Name: MainDescribeWe define a string with a suffix of suffix (i) representing the substring from s[i] to S[length (s)].The suffix array (Suffix array) Sa[i] holds an arrangement that satisfies

Person: infix expressionComputer: suffix expressionThe infix suffix is required and then calculated. Either step requires a stack:For (3 + 4) x5-6One infix turn suffixThe stack involved is used to store symbols such as "+-x/()"Thought:Meet the digital output; Meet the symbol into the stackWhen the empty stack or symbol is the left parenthesis, it is directly into the stack;When the operator is the symbol to

PHP upload feature set suffix name and random name, php upload suffix name form.php HTML>Head> Metahttp-equiv= "Content-type"content= "text/html"CharSet= "Utf-8"> title>Upload Image title> Head>Body>formMethod= "POST"Action= "upload.php"enctype= "Multipart/form-data"> inputtype= "hidden"name= "Max_file_seze"value= "2000000"> inputtype= "File"name= "File"value= "View"> inputtype= "Submit

trademark would be at least 1 and at most C Haracters.After the last trademark, the next task begins. The last task was followed by a line containing zero.OutputFor each task, output a single line containing the longest string contained as a substring in all trademarks. If there is several strings of the same length, print the one and that is lexicographically smallest. If There is no such non-empty string, output the words "IDENTITY LOST" instead.Sample Input3aabbaabbabbababbbbbbbabb2xyzabc0Sa

Transmission Door reviewed the suffix array.First, because of the transpose we need to make a difference to the string. Consider the practice of a binary + suffix array.Two-point answer K, the continuous height[i]>=x segment grouping, if the maximum value of the SA within a group and the difference between the minimum value >=k, then K is feasible. The suffix aut

Instructions:give you a string with a length of not more than 2000 lowercase letters. Then Q asks Q no more than 10000. Each query asks how many different substrings are in an interval [l,r]. Ideas:If you are counting the number of different substrings of the whole string, the problem is the template. Just follow the method in the paper. The key is to ask how many different substrings are in a range instead of the entire string. But we can't run a suffix