pacman squares

Approximation by a progression Time Limit: 500MS Memory Limit: 65536KB 64bit IO Format: %i64d %i64u Submit StatusDescriptionYour is given a sequence of integersa1,..., an. Find an arithmetic progressionb1,...,Bnfor which the Value∑ (AI?Bi)2is minimal. The elements of the progression can be non-integral.InputThe first line contains the numberNof elements in the sequence (2≤N≤104). The second line given the integersa1,..., an; Their absolute va

1. Polynomial-fitting function:Y= A0 + a1x + a2x^2 + ... + akx^k (where k is fit times)When the k=1 is linear fit, the k=2 is a two-time polynomial ... Three-time polynomial.2. Least squares principle matrix algorithm principle:X*a=yA= ((X ' *x)-1) *x ' *y|-X1 x1^2 ... x1^k| |y0||-X2 x2^2 ... x2^k| |a0| |y1||... | |a1| |. ||... | |. | = |. ||... | |ak| |. ||-Xn xn^2 ... xn^k| |yn|where x is the initial Vandermonde matrix, A

This is just a description of how the least squares method is used to solve the linear regression problem of a function in the R language.The code is as follows: (data above a blog) (not very simple????)> xThe results are as follows:$coefficientsIntercept X 0.8310557 0.9004584Description: Intercept: Interceptx: Coefficient of variable XThat is, for the one-dimensional function intercept equation: y=0.9x+0.83Results of the previous blog's Calculations

1. Make a square with a borderIf you set the width and height of the box container to 0 and set a thicker width value for each edge and a different color from each other, you will end up with four triangles, each pointing to a different color.HTML code: CSS3 Code:#square {width:0;height:0;border-width:100px;Border-style:solid;Border-color:red Blue green yellow;Line-height:99em;Overflow:hidden;Cursor:pointer;margin:30px Auto;}Display effect:Visible from the diagram, the four triangles point in di

Four squared sum theorem, also known as Lagrange's theorem:Each positive integer can be represented as a sum of squares of up to 4 positive integers.If 0 is included, it can be represented as a sum of 4 squares.Like what:5 = 0^2 + 0^2 + 1^2 + 2^27 = 1^2 + 1^2 + 1^2 + 2^2(^ symbol denotes the meaning of a exponentiation)For a given positive integer, there may be multiple representations of the sum of squares.Ask you to sort 4 numbers:0 And for all poss

NET and MATLAB--the least square line fitting (C #) is first A. m file drawgraph.m to make sure it runs in MATLAB. Here I am the least squares line fitting procedure. % Least squares linear fitting%created by Safirst C. Ke 2007.8.29 Wed 14:51 function Drawgraph (coords)% incoming arguments are two rows of vectors, first behavior x coordinates, and second behavior coordinates. %axis ([0 100 0 100]);Grid on;H

A square chart with n*n (n Someone from a point in the upper left corner of the picture, you can walk down, or to the right, until you reach the lower right corner of point B. On the way, he can take the number in the squares (the squares will change to the number 0). This person from point A to point B to walk two times, try to find out 2 such paths, so that the sum of the obtained number is the largest.

Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, ...) which sum to N. For example, given n = A, return 3 because 12 = 4 + 4 + 4; Given n = 13, return 2 because = 4 + 9. IdeasGiven an integer, I want to get the number of squares that can be added with the sum of squares to give this integer the least number.Using dynamic programming, use R[i] to save the re

1 #import "RootViewController.h"2 #import3 4 @interfaceRootviewcontroller () 5 @end6 7 @implementationRootviewcontroller8 9- (void) Viewdidload {Ten [Super Viewdidload]; One AJscontext *context =[[Jscontext alloc] init]; -[Context Evaluatescript:@"var square = function (x) {return x*x;}"]; -Jsvalue *squarefunction = context[@"Square"]; theJsvalue *ninesquared = [Squarefunction callwitharguments:@[@9]]; -NSLog (@"9^2:%@", ninesquared); - - } + - @endUse JavaScriptCore to achieve the fo

Question: Can you put a given figure in a 4x4 square with no more than 6 2x2 square paper?Topic Analysis: Violence to cite P (9,6) species (worst case) program can be.The code is as follows:# include　　UVA-12113 overlapping squares (backtracking + violence)

A matrix of N * m is given. Each lattice has a non-negative number, And a number must be selected to maximize the sum. The number in the lattice with adjacent edges cannot be selected at the same time. First, I never thought about this network stream ...... Because the number of squares (1) is a State compression ...... I understood it after reading the question: Due to the large data range, the status cannot be compressed. You need to use a network s

[LINK] I am a link. Click me :)Question] Enter the question here [Question] Pay attention to the number of asterisks...Then v x y is connected from (Y, x) to (Y + 1, x.H x Y is the line from (x, y) to (x, y + 1 ).(X, Y) is used as the upper left corner of the enumeration. [Code] #include Exercise 4-2 uva201 squares

The so-called least square method is to fit a series of two-dimensional observations in a straight line. Assume that the straight line is y = kx + B, so how can we judge whether this line fits all observations well? The least square method is that if K and B minimize the sum of squares of the difference between the value y calculated from the straight line and the observed value Yi, then we can consider that the straight line can fit the observed valu

Hdu1569: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 1569 Question: Chinese. Problem: Classic problems. First, divide all vertices into two parts: X and Y according to (I + J) % 2 = 1 and (I + J) % 2 = 0. For the X, and y parts respectively, any two numbers are not adjacent, so they can be arbitrarily removed. The number of queries in Question X and the number of queries in question y are the final sum and maximum values. Therefore, if I and j are adjacent, one side is established between I

Question connection Analysis: I have been entangled in this question for a long time and cannot write dynamic equations. After reading the human code, I will use a three-digit array DP [I, j, k], indicates the maximum value that can be obtained from the number of squares that can be eliminated from the number I to the number J. Then there are: DP [I] [J] [k] = DP [I] [r-1] [0] + (LEN [R] + k) ^ 2; len [R] indicates the number of consecutive identical

(int i = 1; I //cout // }//cout LL ans =0; for(inti =1; I i) { for(intj = i +1; J j) {structNode t[8]; t[0].x = Arr[i].y-arr[j].y +arr[i].x; t[0].Y = arr[j].x-arr[i].x +arr[i].y; t[1].x = Arr[j].y-arr[i].y +arr[j].x; t[1].Y = arr[i].x-arr[j].x +arr[j].y;//cout //cout //for (int k = 0; k //cout // }//cout if(t[0].x 0].x = = arr[i].x t[0].y arr[i].y) {t[0].x = Arr[j].y-arr[i].y +arr[i].x; t[0].Y = arr[i].x-arr[j].x +arr[i].y; } if(t[1].x 1].x = = arr[j].x t

(Hdu step 3.1.2) the bone board is paved with squares (simple recursion: calculate the number of solutions to overlay 2 * n grids with a 2*1 bone board), hdu3.1.2 Make an advertisement for yourself before writing a question ~.. Sorry, I hope you can support my CSDN video courses at the following address: Http://edu.csdn.net/course/detail/209 Question: Bone plate shop Square Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536

intersection of the two straight lines, it is easy to know the number of straight lines after the intersection, But if you directly divide the distance from the intersection to a certain point by the width, this will not work, because it may be less than 1, or add 1, SO ~> We can use a straight line as the standard. Here we have the red line as an example (the Green Line is the same): we use the orange line of 135 degrees as the standard, if the number of two points on both sides of the orange

The subject requires the implementation of a function that determines whether any given integer N satisfies the condition: it is a total square number, and at least two digits are the same, such as 144, 676, and so on.function Interface Definition:int IsTheNumber ( const int N );These N are the parameters that the user passed in. If the N condition is met, the function must return 1, otherwise 0 is returned.Example of a referee test procedure:#include Input Sample:105 500Sample output:cnt = 64-7

//OnPaint void OnPaint(HWND hWnd, UINT nMsg, WPARAM wParam, LPARAM lParam) { PAINTSTRUCT ps = { 0 }; HDC hDC = BeginPaint(hWnd, ps); int marc = 0; //控制棋盘所在位置 for (int i = 0; i 10; i++) //画九格横线 { Span class= "Typ" >movetoex ( hdc Marc + 50 Marc + 50 + i * 50 NULL LineTo(hDC, marc + 500, marc + 50 + i * 50); } for (int j = 0; j 10; j++) //画九格直线 { Span class= "Typ" >movetoex ( hdc Marc + 50 + J * Span