given data into a string, and then appends or inserts the character of the string into the string buffer. The Append method always adds these characters to the end of the buffer, while the Insert method adds characters at the specified point. For example, if z refers to a string buffer object where the current content
: abcgoogleaba, two input files, one is goog and the other is ABA.
# Include "stdafx. H "# include
2. Unify the even odd numbers
How can we unify it?
We can insert a special character between each character in this way.
For example, the above string: abcgoogleaba. You can perform the following operations: # A # B # C # G # O # G # L # e # A # B # #
In this way, the strings in the reply are all odd, so you do not need to consider the even number.
I
This article from: http://www.cnblogs.com/kejie/p/5971773.htmlPublic dictionary{ Converts a string into an array of characters. Char[] Chararray=str. ToCharArray (); Defines a dictionary with key keys as the number of characters to be taken out, and value as the corresponding character. Dictionaryfor (int i=0;i If the current dictionary does not have this character, add a new one, or increment the corresponding value of the current chara
// Declaration: getlogicaldrivestrings (nbufferlength: DWORD; {buffer size} lpbuffer: pansichar {buffer}): DWORD; // The buffer result is stored as follows: for example, drive a is represented as a: \ separated by an empty character, followed by backward; // Therefore, each drive occupies 4 bytes.
// Example: Procedure tform1.formcreate (Sender: tobject); var pstr: pchar; drivearr: array [0 .. 4*26] of ch
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