perl read xml file

The following example shows how to read the content in the XML file and display it in textbox: Using System; Using System. Data; Using System. configuration; Using System. Web; Using System. Web. Security; Using System. Web. UI; Using System. Web. UI. webcontrols; Using System. Web. UI. webcontrols. webparts; Using System. Web.

Use JS to read XML files, here only consider IE browser Step1 Create a DOM object Copy Code code as follows: function CreateDOM () { var xmldoc = null; try {//ie if (typeof arguments.callee.activeXString!= ' string ') { var versions = [ "MSXML2. domdocument.6.0 ", "MSXML2. domdocument.3.0 ", "MSXML2. DOMDocument ", "Microsoft.XMLDOM" ]; var i, Len for (i = 0, len =

Dom|xml 1, need the name spaceUsing System.Text;Using System.IO;Using System.Xml;2, there are 001.jpg pictures in the folder3. Generate a Docsave.xml file //******************Try{XmlDocument myxmldoc = new XmlDocument ();Myxmldoc.loadxml (" XmlElement elem = myxmldoc.createelement ("image"); Open a picture file and use the picture to construct a

Java read XML file (1)ReadXml.java PackageRead;ImportJava.io.IOException;ImportJava.util.ArrayList;ImportJavax.xml.parsers.DocumentBuilder;ImportJavax.xml.parsers.DocumentBuilderFactory;ImportJavax.xml.parsers.ParserConfigurationException;ImportOrg.w3c.dom.Document;ImportOrg.w3c.dom.Node;ImportOrg.w3c.dom.NodeList;ImportOrg.xml.sax.SAXException;//----------------

() {LoadXml (); XmlNodeList XNL=xmldoc.selectsinglenode ("User"). ChildNodes; foreach(XmlNode xninchxnl) {XmlElement XE=(XmlElement) xn; if(XE. GetAttribute ("name")=="Inventions") { //XE. RemoveAttribute ("name");//Remove the Name propertyXe. RemoveAll ();//Delete the entire contents of the node Break; }} xmldoc.save (Server.MapPath ("User.xml"));//Save } Private voidShowit () {LoadXml (); XmlNode xn=xmldoc.selec

Web effects p/jsp.html target=_blank >jsp Tutorial Add, delete, read the content code of the specified tag in the XML file Package XML; Import Java.io.file;Import java.util.list; Import org.dom4j.document;Import org.dom4j.documentexception;Import org.dom4j.element;Import Org.dom4j.qname;Import Org.dom4j.io.saxr

The RSS 2.0 version of PHP generated class is used in the project. You can generate an XML file and output it through a function simply by inputting it into the data structure. /** * RSS Generation module * @author jerryli (@lijian @dzs.mobi) * @see Protocol Description RSS specification follows 2.0 * http://jyjsjd.iteye.com/blog/1543483 * HT tp://rayleeya.iteye.com/blog/372802 */final class crssbuilder{/*

Suppose we now want to read the following Info.xml fileXML version= "1.0" encoding= "gb2312"?>Root> DataID= "1"> name>Ceunname> Age>21st Age> Data> DataID= "2"> name>Zhang San]]>name> Age>22 Age> Data> DataID= "3"> name>Jakename> Age>23 Age> Data> DataID= "4"> name>Helloname> Age>20 Age> Data> DataID= "5"> name>Paulname> Age>25 Age> Data>Root>Next, read and traverse the Info.xmlDOCTYPE HTML PUBLIC "-//

The XML file is as follows:XML version= "1.0" encoding= "UTF-8"?>Tokenxml> Tokenspec> SpecID= "TOTP01"> Otplen>6Otplen> IntervalTime>60IntervalTime> Updateresplen>0Updateresplen> Puk1len>0Puk1len> Spec> Tokenspec> tokenlist> tokenSN= "rere0000000000"Specid= "TOTP01"> seed>ddc31a7804a2dbd200bd12c9e752a5e5556ff4c28760da8a92d368b4b07d7e5bseed> IV>8cac8153f5af7bce0f9baf

nodesfor (int i = 0; i Get the node for each corresponding position INode Node1 = Childnodes.item (i);if ("Account". Equals (Node1.getnodename ())) {If the name of the node is "account", the Account element property type is outputSystem.out.println ("\ r \ n found an account. Owning area: "+ node1.getattributes (). getNamedItem (" type "). Getnodevalue () +". ");Get the node under NodeList nodedetail = Node1.getchildnodes ();Traverse for (int j = 0; J Get Node detail = Nodedetail.item (j);if ("

Write an XML file: 1 var 2 IXMLDoc : IXMLDocument; 3 XMLNode, xNodeItem: IXMLNode; 4 begin 5 IXMLDoc := NewXMLDocument(); 6 try 7 XMLNode := IXMLDoc.AddChild(‘ConfigInfo‘); 8 9 xNodeItem := XMLNode.AddChild(‘VideoDB‘);10 xNodeItem.Attributes[‘Host‘] := VideoSQLConfig.strAddress;11 xNodeItem.Attributes[‘UserName‘] := VideoSQLConfig.strUserName;12 xNodeItem.Attributes[‘PassWord‘]

C # Read and write XML filesIt is known that an XML file (Bookstore.xml) is as follows:Code 1. Insert a CodeXmlDocument xmldoc=new XmlDocument ();Xmldoc.load ("Bookstore.xml");XmlNode Root=xmldoc.selectsinglenode ("bookstore");//Find XmlElement xe1=xmldoc.createelement ("book");//Create a Xe1. SetAttribu

Web site configuration information is generally written to the XML, the following is a simple read and write operation of XML, for reference only.read operation: XmlDocument xmldoc=NewXmlDocument (); XmlReaderSettings Settings=Newxmlreadersettings (); Settings. Ignorecomments=true;//Ignore comments inside the document varPath = HttpContext.Server.MapP

XML File Authoring Copy Code code as follows: L T;parameter> . aspx page Professional: Lt;asp:dropdownlist id= "Y_zhuanye" runat= "Server" width= "144px" > . aspx.cs page Copy Code code as follows: protected void Page_Load (object sender, EventArgs e) { if (! Page.IsPostBack) { FileName = Server.MapPath ("Zhuangye.xml"); This.

Read XML file content 15GE500746 C D16013100130 15GE500746 C D16013100115 15GE500746 C D16013100117 15GE500746 C D16013100120 15GE500746 C D16013100133 15GE500746 C D16013100122 15GE500746

This is the case, now I need to use jquery ajax to request a PHP file to get the content of an XML file, which needs to be loaded into JSON data issued Because of not familiar with PHP, ask this function and JS receive the JSON data after how to parse code, by reference, the more detailed the better, thank you! The following is the contents of the

Why the/N or/r/n read from an XML file cannot be wrapped in the MessageBox In an XML file, there is a string that contains some/r/n strings, but it was found that after reading it, it was found that it could not be displayed in the MessageBox at all, and the following reason

This example describes the PHP read configuration file class instance. Share to everyone for your reference. as follows: /** * For PHP configuration, such as the configuration file *config.php 1. INI is a bit outdated??2. XML is better,3. Yaml is good, but it is not standardized after all.4. txt to or

In general, we will write some configuration information to the configuration file in order to make changes to some points of the program without modifying the source code. Here's a way to read the XML configuration file in spring, with the basic idea of defining a Java class that defines some static variables correspo

ObjectiveYou need to read the time to write a generic component XML file, but consider the component distribution easier, so that in a third-party small reference jar package. Therefore, the direct JDK built-in XML parsing method. There may be no third-party components that are powerful.Imported Files:Import Org.w3c.do