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Implementing CRC16 parity code with Java

); //Output code as binary number. for (int i = 0; i for (int j = 0; J System.out.print (");              } System.out.println (); //Output code as hex number. System.out.println ("The CRC16 Code is:" + Crc16checker.tohex (b));        } } 3. Test: Case : A (ASCII = 41) Result : 410186 CRC bits : 0168 (0000 0001 1000 0110) Run program : Input hex data :A 0100 0001 0000 0001 1000 0110 The CRC16 code is :410186 Case : CRC16TEST (ASCII = 43 52 43 31 36 54 45 53 54) Result : 45524331365445

About memory Functions GlobalLock (), GlobalAlloc (), GlobalUnlock () Usage __ function

between allocating a fixed block of memory using gmem_fixed and allocating a removable memory block using gmem_moveable. (Please be more specific)Whether there are differences in their efficiency.Why in some source code, and then use the GMEM_MOVEABLE flag to allocate memory, will use the GlobalFree of the memory handle it returned to release the operation of the statement commented out, or simply do not write. Wouldn't it be necessary to do so?--------------------------------------------------

Windows network Programming notes WinSocket API CSocket casyncsocket__ Programming

notification handler code here CSocket socktemp; Socktemp.create (7803); Port is 7803, arbitrary AfxMessageBox ("Start call Listen"); Socktemp.listen (1);//Accept only one connection AfxMessageBox ("Listen function return"); CSocket Socksend; AfxMessageBox ("Start call with Accept)");//After testing, csocket::accept is a blocking function socktemp.accept (socksend); Socktemp has submitted his own pointer address to socksend, so not close AfxMessageBox ("Accept ret

On the understanding of Globalalloc,globallock,globalunlock

returned to release the operation of the statement commented out, or simply do not write. Wouldn't it be necessary to do so?--------------------------------------------------------------------------------A: Gmem_moveable is to allow the operating system (or application) to manage the memory heap, when necessary, the operating system can move the memory block to obtain larger blocks, or to merge some free memory blocks, also known as "garbage collection", it can improve memory utilization. In ge

VC in about Globalalloc,globallock,globalunlock

returned to release the operation of the statement commented out, or simply do not write. Wouldn't it be necessary to do so?--------------------------------------------------------------------------------A: Gmem_moveable is to allow the operating system (or application) to manage the memory heap, when necessary, the operating system can move the memory block to obtain larger blocks, or to merge some free memory blocks, also known as "garbage collection", it can improve memory utilization. In ge

Why only job hopping can raise wages

Saturday will leave the city of Zhuhai. Since February 2006, I have worked in 3 companies in Zhuhai. From programmer to PL, Senior SE. Has done Php,java,. NET, has done the website, the outsourcing project, the domestic project, the product. The day before yesterday, and a friend to work with a chat about the topic of "Why only a job hopping to raise wages." Of course, what I'm talking about here is a bigger raise. In the same business, 10% of the year's gains are high. I give a substantial defi

Dameng database string cutting-custom functions

--Returns the number of separated groups based on the delimiterCREATE OR REPLACE FUNCTION get_strarraylength (STR VARCHAR ( -), SPLIT1 VARCHAR (Ten) ) RETURN int as v_location int; V_start INT; V_length INT; BEGIN STR:=LTRIM (RTRIM (STR)); V_location:=LOCATE (SPLIT1,STR); V_length:=1; While V_location0LOOP V_start:=v_location+1; V_location:=LOCATE (Split1,str,v_start); V_length:=v_length+1; END LOOP; RETURN v_length; END;--Take out the nth string a

Linux Find command

Find/-name httpd.conf Find/ -name access_log 2>/dev/null find/etc-name ' *srm* ' Find /-amin-10 # Lookup in the Department Last 10 minutes of access to files find /-atime-2 # Find files accessed in the last 48 hours of the system find /-mmin-5 # Find files modified in the last 5 minutes of the system find /-mtime-1 #查找在系 The last 24 hours in the system find/ -cmin-5 # Find files that have been changed in the last 5 minutes of the systems Find/ -ctime-1 #查找在系统中最后24小时里被改变状

Vim Common Nerdtree shortcut keys

) For VIM, if you set a fold, but exit the file, whether or not to keep the file, the collapsed part will automatically disappear. This is very inconvenient. So vim gives you the means to keep records of folds, tags, bookmarks, and so on. Most of all, Vim can save up to 10 view for each file, which means you can have 10 different labeling methods for the same file, and these things will be saved as you need them. : Mkview-> Save setting : Loadview-> read record (load setting) : Mkview 2-> Sav

What is the price of an Apple 27-inch imac?

What is the price of an Apple 27-inch imac? Apple's 27-inch imac will meet you at the October 16 Apple launch, so what's the price for the new imac on the 5K screen? The following small series for everyone to reveal the Apple 27-inch imac price, together to understand the next bar.   U.S. media have exposed the upcoming sale of Apple's new 27-inch imac, up to $2000 trillion, which is said to be in Europe, but only for euros. Apple will releas

Linux Learning Notes-Search command __linux

for the last 10 days to change the properties of the file #find/var/log/-atime 10 searches the log directory for the last file accessed 10 days in the same day #find/var/log/-size 25k Search log directory file size equal to 25k files #find/var/log/-size +25m search for files with a file size greater than 25M in the log directory #find/var/log/-size-25k Search Log directory file size less than 25k files----k lowercase, M caps, the default unit is the data block (512 bytes) #find. -inum 262422 se

VC in about Globalalloc,globallock,globalunlock

statement commented out, or simply do not write. Wouldn't it be necessary to do so?--------------------------------------------------------------------------------A: Gmem_moveable is to allow the operating system (or application) to manage the memory heap, when necessary, the operating system can move the memory block to obtain larger blocks, or to merge some free memory blocks, also known as "garbage collection", it can improve memory utilization. In general, the memory heap space is managed b

Use Microsoft Ajax Minifier to help your JavaScript thin

file, its beginning content is roughly as follows, there are complete annotations and function definitions, which is useful for developers, but not for the runtime users: Let's start experimenting with the following two instructions normal-crunching and hyper-crunching: Normal-crunching:ajaxmin c:\inetpub\wwwroot\website2\hash.js–o C:\inetpub\wwwroot\WebSite2\ Hash _mini_o.js Convert the Hash.js file through-O (normal-crunching) instructions to hash_mini_o.js file: Press ENTER to displa

Install Sybase under unixware7.1.1

1. Install Sybase1, # Prtvtoc–f A/DEV/RDSK/C0B0T0D0S02, # VI A (where a content added to:) 0x4 0x200 3807410 2048000x4 0x200 4012215 20971520x4 0x201 6109372 1638400x4 0x201 6273217 819200x4 0x201 6355142 4096000x4 0x201 6764747 4096000x4 0x201 7471352 8192000x4 0x201 7993557 2048000x4 0x201 8198362 4096000x4 0x201 8607967 6291456Num 0x4 0x201 14899428 6144000x4 0x201 15513833 819200~: Wq(Establish two file system 0x200, build 10 bare equipment 0x201)3, # Edvtoc–f A/DEV/RDSK/C0B0T0D0S04, #/etc/c

The Find command is one of the most powerful commands

24小时里修改过的文件 Find/-cmin-5 # finds files that have changed state in the last 5 minutes of the system Find/-ctime-1 #查找在系统中最后24小时里被改变状态的文件 Find/-user Reda #查找在系统中属于fred这个用户的文件 Find/-not-user Reda #查找在系统中不属于FRED这个用户的文件 Find/-group Redagrp # finds files that belong to the REDAGRP group in the system Find/-gid 501 #查找系统中属于组id为501的文件 Find/-user fred-a-group redagrp Find/-user Reda-o-user Tracy Find/-nouser #查找在系统中属于作废用户的文件 Find/-empty # finds files that are empty in the system or empty folders Find/-fa

The beauty of programming: factorial computing

1. Problem Description 1) given an integer N, then the factorial N of N! How many zeros are there at the end? Example: N = 0, N! = 3628800, N! There are two 0 s at the end. 2). N! Binary represents the lowest position in 1 2. Analysis and Solution First consider, if N! = K * 10 M, and K cannot be divisible by 10, so N! There are M 0 at the end. Then consider N! Reason decomposition, N! = (2X) * (3Y) * (5Z )..., since 10 = 2*5, M is only related to X and Z. Each pair of 2 and 5 can get a 10

It instructor Han Shunping: Why did I quit my million annual salary and start my own business?

Teachers have a wealth of teaching experience and the industry's high visibility, experienced 10 years of training, including the teaching model has been tested by the market, students are recognized, learning efficiency.In order to allow the trainees to participate in the Thai beef programmer, can really become China's sought-after programmers, we first ensure that the instructor must be the industry's high-quality lecturers, some of them are industry leaders, the second we have made a full up

bzoj1455 Roma Games

1455: Roman Games time limit: 5 Sec Memory Limit: MB Submit: 1419 Solved: 585 [Submit] [Status] [Discuss] Description Roman Emperors liked to play killing games. There are n men in his army, and everyone is a separate regiment. A plane geometry test was recently held and everyone got a score. The emperor liked plane geometry, and he sniffed at those who scored very low. He decided to play such a game. It can send two kinds of commands: 1. Merger (I, J). Merge the regim

Socket Programming Practice (5) The problem and solution of--tcp sticky bag

TCP sticky packet problemBecause the TCP protocol is a byte-stream-based, non-boundary transport protocol, there is a high likelihood of sticky-packet problems, which are described below. For host A to send the M1 and M2 two each 10K data block, host B receives the data the way is indeterminate, has the following way to receive: receive M1 First, then receive M2 (the correct way) receive M2 First, then receive M1 (Error) receive 20k data at once (error) received two times, first time 15k, secon

Rotate Array Solution

QuestionRotate an array of n elements to the right by K steps.For example, with n = 7 and k = 3, the array is [1,2,3,4,5,6,7] rotated to [5,6,7,1,2,3,4] .Solution 1 Bubble RotateSimilar with bubble sort, time complexity O (k * n), Space cost O (1)1 Public classSolution {2 Public voidRotateint[] Nums,intk) {3 intLength =nums.length;4 if(k >=length)5K = k%length;6 if(k = = 0)7 return;8 for(inti = 0; I )

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