python empty string

occurrences as the value.The Code is as follows: you can modify it according to your needs. This removes leading and trailing spaces of the string and does not count empty strings.PS: I changed it again, so the effect will be better.# -- Coding: GB2312 --Dic ={}# define a dictionary typeFp = open('data.txt ') # open the file to be queriedFor line in fp: # Read rows from fp. This method can be used to avoid

The Template-type string Template usage in the string module of Python, pythontemplate String. Template ()Add replacement characters in string. Template (), use the "$" symbol, or use the "$ {}" character in the string. Use the

; Format (text,'')'Hello World'>>> Format (text,'^20')'Hello World'>>> Format (text,'*>20')#other padding characters that are extra empty can be specified before the alignment'*********hello World'>>> Format (text,'=')'Hello world========='>>> Format (text,'%^20')'%%%%hello world%%%%%'>>>#when multiple values are formatted, the formatting code code can be used in the format () method>>>'{: >10} {: >10}'. Format ('Hello',' World')'Hello World'>>>‘{: >1

example width = input('Enter number here:')price_width = 10item_width = width - price_widthheader_format = '%-*s%*s'content_format = '%-*s%*.2f'print '='*widthprint header_format % (item_width,'Item',price_width,'Price')print '-'*widthprint content_format % (item_width,'Apples',price_width,0.4)print content_format % (item_width,'Pears',price_width,0.5)print content_format % (item_width,'Banana',price_width,8)print content_format % (item_width,'Tomato',price_width,6)print '='*width Outp

---restore content starts---Capitalize () method to capitalize the first letter of the string# Convert the first letter of a string to uppercase Text = ' Alet 'ret = text.capitalize () print (ret) Alet　　Casefold () method to capitalize the first letter of the string# converts all uppercase letters of a string to lowerc

elements of the list x to build a dictionary, the key value is the list of each element, value is None4. Get (key) to find value based on key5. Hash_key (x) find if the dictionary contains a key value x6. Update (x) updating another dictionary with one dictionary7, Popitem () delete the last element and return8, Pop (key) delete the key value corresponding to the element9. Items () Converts the dictionary to a list and returns10, Iteritems () Convert dictionary to list, return iterator11. Key (

Python determines whether a string contains a sub-string. This example describes how to use python to determine whether a string contains a sub-string. Share it with you for your reference. The details are as follows: The

disadvantage is that it affects performance by stitching strings, modifying strings, and so on. Because it is immutable, it is not a inplace operation to modify a string , to create a new object. This is why it is not recommended to use the + and join ()when stitching multiple strings. Join () calculates the length of all the strings, then copies them all, and then only new objects. You need to be careful of the pits , not all strings will use the i

','Information',"']>>> >>> words = [i forIinchXifi]>>>words['Python','3','6','1','v3','6','1','69C0DB5','Mar',' +',' .',' -',' A',' $','MSC','v','1900',' -','bit','AMD64',']',' on','Win32\ntype','Copyright','credits','or','License',' for',' More','Information']>>>Use the S.join () method to splice:>>>#concatenation of Strings>>> >>>Help (Str.join)-on Method_descriptor:join (...) S.join (iterable)-str Return a stri