Finding the shortest sequence for the inverse FizzBuzz problem and the fizzbuzz shortest sequence
Problem description
FizzBuzz Problems: If a natural number greater than 0 can be divided into 3, "Fizz" will be output; if it can be divided into 5, "Buzz" will be output; if it can be divided into 3 and 5, "FizzBuzz" will
60 characters to solve Fizzbuzz problem:For x in range (101):p rint "Fizz" [x%3*4::]+ "Buzz" [X%5*4::]or XThe following is solved with TensorFlow, compared with the above is very complex, but very interesting, and suitable for learning tensorflow, Divergent thinking, expand the scope of TensorFlow application.TensorFlow Application FizzbuzzReprint Please specify address: http://www.cnblogs.com/SSSR/p/5630497.htmlThe direct code is as follows:For speci
Quote callback:
Write a program to print the numbers 1 to 100. However, when the number is a multiple of 3, "fizz" is printed to replace the number, and "Buzz" is used to replace the number of 5, which is both a multiple of 3 and a multiple of 5 to print "fizzbuzz ".
# Include
The step count is used to replace multiple remainder operations on each number. The statistical result of the program is: Total fizz = 33, total buzz = 20, and total
:
Write a program, print the numbers 1 to, and print "Fizz" in multiples of 3 to replace this number, and print "Buzz" in multiples of 5 ", print "FizzBuzz" for numbers that are multiples of 3 and multiples of 5 ".Here is a short way to solve this problem:
For x in range (101): print "fizz" [x % 3*4:] + "buzz" [x % 5*4:] or x
15. Set
Counter database used
Copy codeThe Code is as follows:From collections import CounterPrint Counter ("hello ")>>> Counte
Atwood promoted a simple programming exercise called FizzBuzz. The problem is referenced as follows:
Write a program, print the numbers 1 to, and print "Fizz" in multiples of 3 to replace this number, and print "Buzz" in multiples of 5 ", print "FizzBuzz" for numbers that are multiples of 3 and multiples of 5 ".
Here is a short and interesting way to solve this problem:
for x in range(101): print"fizz"[x%3
The following are the useful points of knowledge and some tools that are summarized in python over the years. Hope to help you!Exchange variable valuesx = 6= 5=print x>>> 5print y>>> 6inline if statementPrint " Hello " if Else " World ">>> HelloJoinNFC = ["Packers","49ers"]AFC= ["Ravens","Patriots"]PrintNFC +AFC>>> ['Packers','49ers','Ravens','Patriots'] PrintSTR (1) +" World">>> 1 WorldPrint' 1 ' +" World">>> 1 WorldPrint1," World">>> 1 WorldPrint
multiples of 5 ", print "FizzBuzz" for numbers that are multiples of 3 and multiples of 5 ".
Here is a short and interesting way to solve this problem:
for x in range(101):print"fizz"[x%3*4::]+"buzz"[x%5*4::]or x
Set
In addition to the built-in python data types, the collection module also includes some special use cases, and Counter is very useful in some cases. If you have been to Facebook HackerCup for
program, print the numbers 1 to, and print "Fizz" in multiples of 3 to replace this number, and print "Buzz" in multiples of 5 ", print "FizzBuzz" for numbers that are multiples of 3 and multiples of 5 ".
Here is a short and interesting way to solve this problem:
for x in range(101):print"fizz"[x%3*4::]+"buzz"[x%5*4::]or x
Set
In addition to the built-in python data types, the collection module also inc
print "Fizz" to replace this number, 5 multiples print "Buzz", for a number that is both a multiples of 3 and a multiples of 5 to print "Fizzbuzz".
Here is a short, interesting way to solve this problem:
For x in range (101):p rint "Fizz" [x%3*4::]+ "Buzz" [X%5*4::]or X
Collection
In addition to Python's built-in data types, the collection module also includes special use cases that are counter useful in some situations. If you've been in this ye
data = {'user': 1, 'name': 'Max', 'three': 4}is_admin = data.get('admin', False)
Get sublist
X = [1, 2, 3, 4, 5, 6] # The first three print x [: 3] >>> [1, 2, 3] # four middle print x [] >>> [,] # The last three print x [-3:] >>>>, 6] # print x [: 2] >>> [1, 3, 5] # print x [1: 2] >>>> [2, 4, 6]
Fix FizzBuzz with 60 characters
Some time ago, Jeff Atwood promoted a simple programming exercise called FizzBuzz
as follows:
Write a program, print the numbers 1 to, and print "Fizz" in multiples of 3 to replace this number, and print "Buzz" in multiples of 5 ", print "FizzBuzz" for numbers that are multiples of 3 and multiples of 5 ".Here is a short way to solve this problem:
For x in range (101): print "fizz" [x % 3*4:] + "buzz" [x % 5*4:] or x
15. set
Counter database used
The code is as follows:
From collections import CounterPrint Counter ("hello ")>>> C
': 1, ' name ': ' Max ', ' three ': 4}is_admin = data.get (' admin ', False)
Get child list
x = [1,2,3,4,5,6] #前3个print x[:3]>>> [x-ray] #中间4个print x[1:5]>>> [2,3,4,5] #最后3个print x[-3:]>> > [4,5,6] #奇数项print x[::2]>>> [1,3,5] #偶数项print x[1::2]>>> [2,4,6]
60 Character Resolution Fizzbuzz
A short time ago Jeff Atwood promoted a simple programming exercise called Fizzbuzz, which referred to the following ques
number 1 to 100, 3 multiples print "Fizz" to replace this number, 5 multiples print "Buzz", for a number that is both a multiples of 3 and a multiples of 5 to print "Fizzbuzz".Here is a short way to solve this problem:
For x in range (101):p rint "Fizz" [x%3*4::]+ "Buzz" [X%5*4::]or X
15. Collection
Use the Counter library.
Copy the Code code as follows:
From collections Import Counter
Print Counter ("Hello")
>>> Counter ({' L ': 2, ' h ': 1, ' E ':
Print X[:3]
>>> [1,2,3]
#中间4个
Print X[1:5]
>>> [2,3,4,5]
#最后3个
Print X[-3:]
>>> [4,5,6]
#奇数项
Print X[::2]
>>> [1,3,5]
#偶数项
Print X[1::2]
>>> [2,4,6]
14.6 characters to solve Fizzbuzz
Some time ago Jeff Atwood promoted a simple programming exercise called Fizzbuzz, citing the following questions:
Write a program that prints numbers 1 to 100, multiples of 3, prints "fiz
]
Convert List to String
Teams = ["Packers", "49ers", "Ravens", "patriots"]
print ",". Join (teams)
>>> ' Packers, 49ers, Ravens , Patriots '
Get elements from the dictionary
I admit try/except code is not elegant, but here is a simple way to try to find the key in the dictionary, if you do not find the corresponding alue will be set with the second parameter to its variable value.
data = {' user ': 1, ' name ': ' Max ', ' Three ': 4}
try:
is_admin = data[' admin ']
number that is both a multiples of 3 and a multiples of 5 to print "Fizzbuzz".Here is a short, interesting way to solve this problem:For x in range (101):p rint "Fizz" [x%3*4::]+ "Buzz" [X%5*4::]or XCollectionIn addition to Python's built-in data types, the collection module also includes special use cases that are counter useful in some situations. If you've been in this year's Facebook Hackercup, you can even find out what's practical about him.Fro
Write Python,python, write Python programming, write Python programming, and write in Python for international students.I and write the team members are graduated from the domestic and overseas computer professional well-known institutions , are now employed in the domestic
': 1, ' name ': ' Max ', ' Three ': 4}Is_admin = data.get (' admin ', False) Get child listx = [1,2,3,4,5,6]#前3个Print X[:3]>>> [About]#中间4个Print X[1:5]>>> [2,3,4,5]#最后3个Print X[-3:]>>> [4,5,6]#奇数项Print X[::2]>>> [1,3,5]#偶数项Print X[1::2]>>> [2,4,6] 60 Character Resolution FizzbuzzA short time ago Jeff Atwood promoted a simple programming exercise called Fizzbuzz, which referred to the following questions:Write a program that prints the number 1 to 1
Baptism soul, practice python (2) -- python installation and configuration, python -- python
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