sample xsd and xml file

JAXB makes the tedious mechanical coding between Java and XML the past, and now it's easy to generate the corresponding Java file through an XSD file, and I typically use maven-jaxb2-plugin to implement XSD-to-Java file generation

Simply put: XML Schema is a class of XML, which is also equivalent to the table structure pattern of relational tables. Most of the time it is possible for a program to automatically generate its XSD based on an existing XML, or to generate its corresponding XSD based on rel

Method One:I use XmlReader to deal with it because I feel XmlReader simple point.I have made an example to illustrate that the XML in the example is not very complex and has no child nodes.XML file (a.xml):XML version= "1.0" encoding= "Utf-8"?> Profile> profileID>0001profileID> desciption>My contentdesciption> URL>http://www.bclc.com/app/DidYouWin/WinningNumbe

This text connection: http://blog.csdn.net/bluishglc/article/details/7596118 , reprint please indicate the source!Sometimes you will find that the past has been started normal system, one day when the startup will report the shape of the following error:[Plain]View Plaincopy org.xml.sax.saxparseexception:schema_reference.4:failed to read schema document ' http://www.springframework.org/Schema/beans/spring-beans-2.0.xsd ', because 1) could not

XPath can find the node but associate the. xsd file (schema specification) with the XML file when the original operation does not use an XSD XML file. There was an error, and the node w

Sometimes you may find that a system that has been activated in the past has been launched on a certain day with the following error: [plain] view plain copy org.xml.sax.saxparseexception:schema_reference.4:failed to read schema document ' http:Www.springframework.org/schema/beans/spring-beans-2.0.xsd ', because 1) could not find the document;2) The document could not is read; 3) The root element of the document is not Obviously, the

DTD is an effective method to ensure that the XML document format is correct. you can compare the XML document and DTD file to see whether the document complies with the specifications, and whether the elements and labels are correctly used. 1. DTD (rule net Type Definition) Document Type Definition (DTD) is an XML con

Come, nonsense not much to say, directly into the state. First use Altova XMLSpy to draw an XSD file, or use the code to write an XSD file, directly write the code to check the data. Just use the simplest student. The student.xsd of the painting The code is as follows: The tools I use here are: jaxb-ri-20120516;

There was an error in configuring Spring XML todaymultiple annotations found at the: -schema_reference.4:failed to read schema document ' HTTP://WWW.SPRINGFR Amework.org/schema/context/spring-context-4.2.xsd ', because 1) could not find the document; 2) The document could Xsd:schema>. -Cvc-complex-type.2.4.c:the matching wildcard is strict, but no declaration can be found for element ' Context:pr

About XSD and DTD in XML structure and the use of standaloneXmlDeclaration declare= document.Createxmldeclaration ("1.0", "Utf-8", "yes"); Yes is the value of standalone,There is a standalone in the declaration in XMLStandalone is used to indicate whether the file calls other external files. A value of "yes" indicates that no external

xml= Extensible Markup Language (extensible Markup Language).Extensible Markup Language XML is a simple data storage language that describes data using a series of simple tags that are available Convenient way to build, although XML occupies more space than binary data, but XML is extremely simple and easy to grasp an

C: \ Program Files \ Microsoft Visual Studio 9.0 \ Vc> xsd d: \ rule11.xml Microsoft (r) XML schemas/datatypes support Utility [Microsoft (R). Net Framework, version 2.0.50727.3038] Copyright (c) Microsoft Corporation. All rights reserved. Writing File 'C: \ Program Files \ Microsoft Visual Studio 9.0 \ Vc \ rule11

Sometimes you will find that the past has been started normal system, one day when the startup will report the shape of the following error: [plain] view plain copy org.xml.sax.saxparseexception:schema_reference.4:failed to read schema document ' http:Www.springframework.org/schema/beans/spring-beans-2.0.xsd ', because 1) could not find the document;2) The document could not be read; 3) The root element of the document is not Obviously, the

use Vistual Studio's own Xsd.exe tool to automatically generate XSD1 from XML, command prompt-Find the folder where the VS comes with the Xsd.exe toolFor example: C:\Program Files (x86) \microsoft Sdks\windows\v7.0a\binNote: Win7 operating system "command Prompt" to run as Administrator2. Copy the XML file to the folder where the Xsd.exe tool is located, and the

1. The XSD file defines the element and type in a namespace. The type defined here is used by element (this namespace or another namespace), but not by XML files. 2. the XML file has a unique root element. 3. When creating an XML