sawtooth technologies

Input212Sample OutputCase #1:2Case #2:19Source2014 ACM/ICPC Asia Regional Shanghai Online Problem Solving:Each m four edge, each edge at most with the original edge intersection, forming a n-1 intersection, is not related to Euler theorem?? Then the team-mates magically moved out F (n) =f (n-1) +4*4* (n-1) +1; then came out 8*n^2-7*n+1 ...Well, the point is that he used the formula directly with the C + + large number template T. So, I used the Java large number of classes handed a pitch, 1900m

* n/2 + 1-N * 9 = N * (8 * N-7) + 1 Because N is a maximum of 10 ^ 12 ,__ int64 (long) is 9*10 ^ 18, N * n will overflow data. If there is no computing time complexity at the beginning, a common big number operation is used, and the result times out. Later, the senior engineer said that the big data was optimized, Is to divide a large number into two parts, respectively, with _ int64. To prevent the overflow of the two-digit multiplication data, the right half of my number is nine digits. For e

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 5047 Problem descriptionthink about a plane: ● One straight line can divide a plane into two regions. ● Two lines can divide a plane into at most four regions. ● Three lines can divide a plane into at most seven regions. ● And so on... Now we have some figure constructed with two parallel rays in the same direction, joined by two straight segments. it looks like a character "M ". you are given n such "M" S. what is the maximum num

Question: Find n 'M'-type broken lines to divide a plane into the largest number of faces!Idea: we all know that n straight lines divide a plane into a maximum number of planes: An = An-1 + n + 1That is, F (n) = (N * n + 2)/2What about a line of 'M' type? It has four lines, but the plane is divided due to the relationship between the three vertices.The number is reduced by 9! So there is a recursive formula F (n) = (M * m + 2)/2-9 * n; M = 4 * n Finally, F (n) = (8 * n + 1) * (n-1) + 2)Since n

2014 ACM/ICPC Asia Regional Shanghai Online 1006 sawtooth

Question link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 5047 Solution Report: Ask a "M" type to divide the plane of a rectangle into a maximum of several blocks. The input has n "M". Now the formula is 8 * n ^ 2-7 * n + 1, but the range of N is 10 ^ 12, as long as the square is within the range of long, what should we do with a large number? I 've tried it all. It's strange that it will time out. I don't think it will happen according to estimation. Maybe it's because the intermediate res

Hdu 5047 Sawtooth combined mathematical precision, hdusawtooth Question link: Click the open link Question: omitted Train of Thought: transfer the card .. I don't want to talk much about it. I mainly want to record the fast reading and writing of java to prevent such bad questions from coming into being next time. Cpp version: #include Java version: import java.util.*;import java.io.*;import java.math.*;public class test {public static void main

ZOJ 3814 Sawtooth Puzzle status compression search, zoj3814 Since there are only four statuses in a box, the total number of statuses is only 4 ^ 9, and bfs can be solved. The trouble lies in simulation. The method of saving my status is to regard the initial status as 000000000. If it is rotated once clockwise, + 1, 3 + 1 = 0. During the bfs process, you need to set a dfs calculation to which boxes will be affected by rotating the current box. Note t

IE compatible picture reduced blur distortion (sawtooth) problem

Last two articlesArticleNeither of the methods described can be the best way to implement the anti-sawtooth font. Let's see how the master did it. Fr é d é Ric Lavigne, author of the famous skin L F and webmaster of www.javootoo.com, a great repository of look and feels for swing, didn't think so and found an elegant and clever way to get the same result Okay, for simplicity, jar package Http://download.csdn.net/detail/laizhenhai88/5094403 As lon

Since there are only four statuses in a box, the total number of statuses is only 4 ^ 9, and BFS can be solved. The trouble lies in simulation. The method of saving my status is to regard the initial status as 000000000. If it is rotated once clockwise, + 1, 3 + 1 = 0. During the BFS process, you need to set a DFS calculation to which boxes will be affected by rotating the current box. Note that there are more than one target status, because some boxes remain unchanged after rotation, we must ca

The Win7 system plays the video movie to appear Sawtooth, mosaic, blur how to do? 1, click "Start-Control Panel-system-Advanced system settings;" 2. In the Pop-up System Properties dialog box, switch to the Advanced tab and click Settings in the Performance area. 3, in the pop-up "Visual Effects" tab, click "Custom", will "enable desktop combination" before the check to remove; 4, after the modification, save the settings to e

relatively troublesome, need to pass some xxxx.parsexxx (), to convert the corresponding data type, although, some trouble, but by comparing on some OJ systems and scanner, Bufferreader efficiency is one times higher than scanner, this gap can be imagined, read more data, the effect is more obvious.AC ProgramImport Java.io.*;import java.math.*;p ublic class main{public static BufferedReader cin=new BufferedReader (new InputStreamReader (system.in)); public static BufferedWriter cout=new Buffe

Introduction Based on the generation of images to achieve a mobile phone number of the need to turn pictures. Content is also very simple, directly using mobile phone number to generate a PNG image. is for the background to be transparent so that other places are invoked. There is no sawtooth mainly relies on a code: G. Textrenderinghint= Textrenderinghint.antialias; Generate pictures 1, serrated 2, no Sawto